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a) 2(4x-8)-7(3+x)=|-4|.(3-2)
8x-16-21-7x=4
8x-7x=4+16+21
x=41
Vậy x=41
b) 8(x-|-7|)-6(x-2)=|-8|.6-50
8x-56-6x+12=8.6-50
8x-6x=48-50+56-12
2x=42
x=42:2
x=21
Vậy x=21
c) -7(5-x)-2(x-10)=15
-35+7x-2x+20=15
7x-2x=15+35-20
5x=30
x=30:5
x=6
Vậy x=6
d) 4(x-1)-3(x-2)=-|-5|
4x-4-3x+6=-5
4x-3x=-5+4-6
x=-7
Vậy x=-7
e) -4(x+1)+(89x-3)=24
-4x-4+89x-3=24
-4x+89x=24+4+3
85x=31
x=31/85
f) 5(x-30)-2(x+6)=9
5x-150-2x-12=9
5x-2x=9+150+12
3x=171
x=171:3
x=57
Vậy x=57
g) -3(x-5)+6(x+2)=9
-3x+15+6x+12=9
-3x+6x=9-15-12
3x=-18
x=-18:3
x=-6
Vậy x=-6
h) 7(x-9)-5(6-x)=-6+11x
7x-63-30+5x=-6+11x
7x+5x-11x=-6+62+30
x=86
Vậy x=86
k) 10(x-7)-8(x+5)=6.(-5)+24
10x-70-8x-40=-30+24
10x-8x=-30+24+70+40
2x=104
x=104:2
x=52
Vậy x=52
cái chữ này cj nhìn khó hiểu quá nên em thông cảm nếu muốn bt đáp án thì viết rõ ra đc chứ^^
\(\frac{a}{27}=\frac{-5}{9}=\frac{-45}{b}\)
\(=>\frac{a.3}{81}=\frac{-45}{81}=\frac{-45}{b}\)
=>b=81
a.3=-45
a=-15
Vậy a=-15;b=81
\(a)2\left(4x-8\right)-7\left(3+x\right)=|-4|\left(3-2\right)\)
\(\Leftrightarrow8x-16-21-7x=4\)
\(\Leftrightarrow\left(8x-7x\right)=16+21+4\)
\(\Leftrightarrow x=41\)
\(b)3|x-3|=15-|-9|+7|-3|-\left(-21\right)\)
\(\Leftrightarrow3|x-3|=15-9+7.3+21\)
\(\Leftrightarrow3|x-3|=15-9+21+21\)
\(\Leftrightarrow3|x-3|=48\)
\(\Leftrightarrow|x-3|=16\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=-16\\x-3=16\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-13\\x=19\end{cases}}\)
\(c)4\left(x-5\right)-7\left(5-x\right)+10\left(5-x\right)=-3\)
\(\Leftrightarrow4x-20-35+7x+50-10x=-3\)
\(\Leftrightarrow4x+7x-10x=20+35-50-3\)
\(\Leftrightarrow x=2\)
\(d)6|x-3|-9|x-3|=-21\)
\(\Leftrightarrow|x-3|\left(6-9\right)=-21\)
\(\Leftrightarrow-3|x-3|=-21\)
\(\Leftrightarrow|x-3|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=-7\\x-3=7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=10\end{cases}}\)
a) 2(x - 5) - 3(x + 7) = 14
<=> 2x - 10 - 3x - 21 = 14
<=> 2x - 3x = 14 + 10 + 21
<=> x = -45
Vậy x = -45
b) 5(x - 6) - 2(x + 3) = 12
<=> 5x - 30 - 2x - 6 = 12
<=> 5x - 2x = 12 + 30 + 6
<=> 3x = 48
<=> x = 16
Vậy x = 16
c) 3(x - 4) - (8 - x) = 12
<=> 3x - 12 - 8 + x = 12
<=> 3x + x = 12 + 12 + 8
<=> 4x = 32
<=> x = 8
Vậy x = 8
d) -7(3x - 5) + (7x - 14) = 28
<=> -21x + 35 + 7x - 14 = 28
<=> -21x + 7x = 28 - 35 + 14
<=> -14x = 7
<=> x = -1/2
Vậy x = -1/2
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(\Leftrightarrow2x-10-3x-21=14\)
\(\Leftrightarrow-x=45\)
\(\Leftrightarrow x=-45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(\Leftrightarrow5x-30-2x-6=12\)
\(\Leftrightarrow3x=48\)
\(\Leftrightarrow x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(\Leftrightarrow3x-12-8+x=12\)
\(\Leftrightarrow4x=32\)
\(\Leftrightarrow x=8\)
\(d,-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\)
\(\Leftrightarrow-7x=21\)
\(\Leftrightarrow x=-3\)
a. 3/5 . 15/7 - 15/7 . 8/5
= 15/7(3/5-8/5)
=15/7. -\(\frac{1}{1}\)
=22/7
b. 4/5 . 1 3/7 + 4/5 . 4/7
=4/5(13/7+4/7)
=4/5.17/7
= 68/35
c, \(6\cdot x+3\cdot x-4=105\)
\(6\cdot x+3\cdot x=105+4\)
\(6\cdot x+3\cdot x=109\)
\(\left(6+3\right)\cdot x=109\)
\(9\cdot x=109\)
\(x=109:9\)
\(x=\frac{109}{9}\)
d, \(200-\left(8\cdot x+7\right)=121\)
\(8\cdot x+7=200-121\)
\(8\cdot x+7=79\)
\(8\cdot x=79-7\)
\(8\cdot x=72\)
\(x=72:8\)
\(x=9\)
\(c,6.x+3.x-4=105\)
\(\left(6+3\right).x=105+4\)
\(9x=109\)
\(x=\frac{109}{9}\)
\(d,200-\left(8.x+7\right)=121\)
\(8.x+7=200-121\)
\(8.x+7=79\)
\(8.x=72\)
\(x=9\)