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\(\sqrt{x-1+2\sqrt{x-2}}-\sqrt{x-1-2\sqrt{x-2}}=1\)
\(\Leftrightarrow\left(\sqrt{x-1+2\sqrt{x-1}}\right)^2=\left(1+\sqrt{x-1-2\sqrt{x-2}}\right)^2\)
\(\Leftrightarrow x-1+2\sqrt{x-2}-x=2\sqrt{x-1-2\sqrt{x-2}}+x-2\sqrt{x-2}-x\)
\(\Leftrightarrow2\sqrt{x-2}-1=2\sqrt{x-1-2\sqrt{x-2}}-2\sqrt{x-2}\)
\(\Leftrightarrow4x-4\sqrt{x-2}-7=-8\sqrt{x-2}-8\sqrt{x-2}.\sqrt{x-2\sqrt{x-2}-1}+8x-12\)
\(\Leftrightarrow5-4\sqrt{x-2}-4x=-8\sqrt{x-2}-8\sqrt{x-2}.\sqrt{x-2\sqrt{x-2}-1}\)
\(\Leftrightarrow x=\frac{9}{4}\) (tmyk)
D = \(\frac{\left(\sqrt{x}-\sqrt{y}\right)^2}{2\left(\sqrt{x}-\sqrt{y}\right).\left(\sqrt{x}+\sqrt{y}\right)}\) . \(\frac{2\sqrt{x}}{\sqrt{x}-\sqrt{y}}\) = \(\frac{\sqrt{x}}{\sqrt{x}+\sqrt{y}}\)
what hell ?
Bạn giải hộ ai à?
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.vi diệu !
\(\left(\frac{\sqrt{\left(-4\right).\left(-9\right)}}{\sqrt{2}}-\sqrt{2}.x\right):5,6=-7,2\)
\(\left(\frac{\sqrt{36}}{\sqrt{2}}-\sqrt{2}.x\right):\frac{28}{5}=\frac{-36}{5}\)
\(\frac{6}{\sqrt{2}}-\sqrt{2}.x=\frac{-36}{5}.\frac{28}{5}\)
\(\frac{6}{\sqrt{2}}-\sqrt{2}.x=\frac{-1008}{25}\)
\(\sqrt{2}.x=\frac{6}{\sqrt{2}}-\frac{-1008}{25}\)
\(\sqrt{2}.x=\frac{6}{\sqrt{2}}+\frac{1008}{25}\)
\(\sqrt{2}.x=\frac{150+\sqrt{2}.1008}{\sqrt{2}.25}\)
\(x=\frac{150+\sqrt{2}.1008}{\sqrt{2}.25}.\frac{1}{\sqrt{2}}\)
\(x=\frac{150+\sqrt{2}.1008}{25.2}=\frac{75+\sqrt{2}.504}{25}\)
Vậy \(x=\frac{75+\sqrt{2}.504}{25}\)
Khiếp bn quá ,toán lớp 8 cg giải dc