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a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.
b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.
c) x : 7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.
d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.
e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.
g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135
Bài làm :
\(a\text{)}...\Leftrightarrow\orbr{\begin{cases}x\div7-7=0\\x.3-12=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x\div7=7\\x.3=12\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=49\\x=4\end{cases}}\)
\(b\text{)}\Leftrightarrow...\Leftrightarrow x\div2=15\Leftrightarrow x=15.2=30\)
\(c\text{)}...\Leftrightarrow100\div x=20\Leftrightarrow x=100\div20=5\)
\(d\text{)}...\Leftrightarrow x\div5=27\Leftrightarrow x=27.5=135\)
\(a)\left(x-5\right).2=0\)
\(\Rightarrow x-5=0\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
\(b)x.3-13=47\)
\(\Rightarrow x.3=47+13\)
\(\Rightarrow x.3=60\)
\(\Rightarrow x=60:3\)
\(\Rightarrow x=20\)
Vậy \(x=20\)
\(c)\left(x.7-7\right)\left(x.12+24\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x.7-7=0\Rightarrow x.7=7\Rightarrow x=1\\x.12+24=0\Rightarrow x.12=-24\Rightarrow x=-2\end{cases}}\)
Vậy\(x\in\left\{1;-2\right\}\)
\(e)140-10.x=120\)
\(\Rightarrow10.x=140-120\)
\(\Rightarrow10.x=20\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(g)x.5-127=273\)
\(\Rightarrow x.5=273+127\)
\(\Rightarrow x.5=400\)
\(\Rightarrow x=400:5\)
\(\Rightarrow x=80\)
Vậy \(x=80\)
bài 2) a) \(2\left(x+1\right)=0\Leftrightarrow x+1=0\Leftrightarrow x=-1\) vậy \(x=-1\)
b) \(x\left(x-2\right)=0\Leftrightarrow\left\{{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=2\end{matrix}\right.\) vậy \(x=0;x=2\)
c) \(\left(x-1\right)\left(x+7\right)=0\Leftrightarrow\left\{{}\begin{matrix}x-1=0\\x+7=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\x=-7\end{matrix}\right.\) vậy \(x=1;x=-7\)
d) \(\left(x+2\right)\left(x^2-9\right)=0\Leftrightarrow\left\{{}\begin{matrix}x+2=0\\x^2-9=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\x^2=9\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\\left\{{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\end{matrix}\right.\) vậy \(x=-2;x=3;x=-3\)
e) \(x^2\left(x-5\right)+2\left(x-5\right)=0\Leftrightarrow\left(x^2+2\right)\left(x-5\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x^2+2=0\\x-5=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x\in\varnothing\\x=5\end{matrix}\right.\) vậy \(x=5\)
bài 1) \(A=48+\left(-48-174\right)+\left|-74\right|=48-48-174+74=-100\)
\(B=\left(-123\right)+77+\left(-257\right)-23-43=-123+77-257-23-43=-369\)
\(C=\left(-57\right)+\left(-159\right)+47+169=-57-159+47+169=0\)
quá hợp lí 
\(a,x\left(x+3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x+3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=-3\end{cases}}}\)
\(b,\left(x-2\right)\left(5-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\5-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)
\(c,\left(x-1\right)\left(x^2+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x^2+1=0\end{cases}\Rightarrow x=1}\)
\(d,-12\left(x-5\right)+7\left(3-x\right)=15\)
\(-12x+60+21-7x=15\)
\(-19x+81=15\)
\(-19x=15-81\)
\(-19x=-66\)
\(x=\frac{66}{19}\)
\(e,30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(30x+60-6x+30-24x=100\)
\(0x+90=100\)
\(0x=10\) ( vô lí )
=> không có giá trị x nào thõa mãn
a) x(x + 3) = 0
=> \(\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\)
Mà x < x + 3
=> x = 0
b)( x - 2 )( 5 - x ) = 0
=> \(\orbr{\begin{cases}x-2=0\Rightarrow x=2\\5-x=0\Rightarrow x=5\end{cases}}\)
=> \(x\in\left\{2,5\right\}\)
c) ( x - 1 )( x2 + 1 ) = 0
=> \(\orbr{\begin{cases}x-1=0\Rightarrow x=1\\x^2+1=0\Rightarrow x^2=-1\end{cases}}\)
Vì x2 không thể bằng -1 => x = 1
d)-12 ( x - 5 ) + 7 ( 3 - x ) = 15
=> -12x - (-60) + 21 - 7x = 15
=> -12x + 60 + 21 + (-7x) = 15
=>[-12x + (-7x)] + 81 = 15
=> -19x = -66
=> \(x\in\varphi\)
\(a,\left(x-7\right):5=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
\(b,\left(x:7-7\right)\left(x:12-12\right)=0\)
\(\Rightarrow\hept{\begin{cases}x:7=7\\x:12=12\end{cases}}\)
\(\Rightarrow x=1\)
\(c,300-x:5=273\)
\(\Rightarrow x:5=27\)
\(\Rightarrow x=27.5=135\)
\(d,135+x:2=150\)
\(\Rightarrow x:2=15\)
\(\Rightarrow x=30\)
a) \(\left(x-7\right):5=0\)
\(\Rightarrow x-7=0\times5\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=0+7\)
\(\Rightarrow x=7\)
Vậy x = 7
b) \(\left(x:7-7\right)\left(x:12-12\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x:7-7=0\\x:12-12=0\end{cases}}\Rightarrow\orbr{\begin{cases}x:7=7\\x:12=12\end{cases}}\Rightarrow\orbr{\begin{cases}x=49\\x=144\end{cases}}\)
Vậy x = 49 hoặc x = 144
c) \(300-x:5=273\)
\(\Rightarrow x:5=300-273\)
\(\Rightarrow x:5=27\)
\(\Rightarrow x=27\times5\)
\(\Rightarrow x=135\)
Vậy x = 135
d) \(135+x:2=150\)
\(\Rightarrow x:2=150-135\)
\(\Rightarrow x:2=15\)
\(\Rightarrow x=15\times2\)
\(\Rightarrow x=30\)
Vậy x = 30
_Chúc bạn học tốt_
Bài 1 :
a, Ta có : \(\left(-123\right)+\left|-13\right|+\left(-7\right)\)
= \(\left(-123\right)+13+\left(-7\right)=\left(-117\right)\)
b, Ta có : \(\left|-10\right|+\left|45\right|+\left(-\left|-455\right|\right)+\left|-750\right|\)
= \(10+45-455+750=350\)
c, Ta có : \(-\left|-33\right|+\left(-15\right)+20-\left|45-40\right|-57\)
= \(\left(-33\right)+\left(-15\right)+20-5-57=-90\)
a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.
b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.
c) x : 7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.
d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.
e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.
g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135