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10 - { [ ( x : 3 + 17 ) : 10 + 3 : 24 ] : 10 } = 5
[ ( x : 3 + 17 ) : 10 + 3 : 24 ] : 10 = 10 - 5 = 5
( x : 3 + 17 ) : 10 + 3 : 24 = 5 x 10
( x : 3 + 17 ) : 10 + 48 = 50
( x : 3 + 17 ) : 10 = 50 - 48
( x : 3 + 17 ) : 10 = 2
x : 3 + 17 = 2 x 10
x : 3 + 17 = 20
x : 3 = 20 - 17 = 3
x = 3 x 3 = 9
a) [(2x+14) : 4 - 3] : 2 = 1
(2x+14) : 4 - 3 = 1/2
(2x+14) : 4 = 1/2 + 3
(2x+14) : 4 = 7/2
2x+14 = 7/2 . 1/4
2x = 7/8 - 1/4
2x = 5/8
x= 5/8.1/2
x= 5/16
a: \(\Leftrightarrow2x+\dfrac{7}{2}=\dfrac{16}{3}:\dfrac{8}{3}=2\)
=>2x=-3/2
hay x=-3/4
b: 2x+3=5
=>2x=2
hay x=1
c: =>3(x-2)=4(5+x)
=>4x+20=3x-6
=>x=-26
\(3\left(2x-6\right)-4\left(1+2x\right)-2\left(x-4\right)=4-3\left(1+2x\right)-5\left(1-2x\right).\)
\(\Leftrightarrow6x-18-4-8x-2x+8=4-3-6x-5+10x\)
\(\Leftrightarrow-4x-14=4x-4\)
\(\Leftrightarrow-4x-4x=-4+14\)
\(\Leftrightarrow-8x=10\)
\(\Leftrightarrow x=-\frac{5}{4}\)
3.2x - 3.6 - 4+4.2x - 2x-2.(-4) = 4 - 3+3.2x - 5-5.(-2x)
6x -18 -4 +8x -2x +8 = 4 -3 +6x -5 +10x
6x +8x -2x -18-4+8 = 4-3-5+6x+10x
12x-22 = -4+16x
12x-16x = -4+22
-4x = 18
x = 18: (-4)
x = -4,5
Mình không chắc là đúng đâu đấy, tại giải vội quá, nếu sai thì ming bạn thông cảm ^.^
(2x - 1)(3 - y) = 20
=> 2x - 1 và 3 - y thuộc Ư(20)
vì 2x - 1 không chia hết cho 2 nên ta không xét Ư(20) chia hết cho 2
ta có bảng :
2x-1 | -1 | 1 | -5 | 5 |
3-y | -20 | 20 | -4 | 4 |
x | 0 | 1 | -2 | 3 |
y | 23 | -17 | 7 | -1 |
\(\left(2x-1\right).\left(3-y\right)=20\)
\(=>2x-1;3-y\inƯ\left(20\right)\)
Ta có bảng sau :
\(2x-1\) | \(-1\) | \(1\) | \(-5\) | \(5\) |
\(3-y\) | \(-20\) | \(20\) | \(-4\) | \(4\) |
\(x\) | \(0\) | \(1\) | \(-2\) | \(3\) |
\(y\) | \(23\) | \(-17\) | \(7\) | \(-1\) |
Vậy ...
7) \(\dfrac{-5}{17}+\dfrac{3}{17}\le\dfrac{x}{17}\le\dfrac{13}{17}+\dfrac{-11}{17}\)
\(\Rightarrow\dfrac{-2}{17}\le\dfrac{x}{17}\le\dfrac{2}{17}\)
\(\Rightarrow-2\le x\le2\)
\(\Rightarrow x\in\left\{-2;-1;0;1;2\right\}\)
8) \(\dfrac{2}{3}\left(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{1}{3}\right)\le\dfrac{x}{18}\le\dfrac{7}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\)
\(\Rightarrow\dfrac{2}{3}\left(\dfrac{6}{12}+\dfrac{9}{12}-\dfrac{4}{12}\right)\le\dfrac{x}{18}\le\dfrac{7}{3}\left(\dfrac{6}{12}-\dfrac{2}{12}\right)\)
\(\Rightarrow\dfrac{2}{3}\cdot\dfrac{11}{12}\le\dfrac{x}{18}\le\dfrac{7}{3}\cdot\dfrac{4}{12}\)
\(\Rightarrow\dfrac{22}{36}\le\dfrac{x}{18}\le\dfrac{28}{36}\)
\(\Rightarrow\dfrac{11}{18}\le\dfrac{x}{18}\le\dfrac{14}{18}\)
\(\Rightarrow x\in\left\{11;12;13;14\right\}\)
8) \(\dfrac{2}{3}\left(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{1}{3}\right)\le\dfrac{x}{18}\le\dfrac{7}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\\ \dfrac{2}{3}\left(\dfrac{6}{12}+\dfrac{9}{12}-\dfrac{4}{12}\right)\le\dfrac{x}{18}\le\dfrac{7}{3}\left(\dfrac{3}{6}-\dfrac{1}{6}\right)\\ \dfrac{2}{3}.\dfrac{11}{12}\le\dfrac{x}{18}\le\dfrac{7}{3}.\dfrac{2}{6}\\ \dfrac{11}{18}\le\dfrac{x}{18}\le\dfrac{14}{18}\\ \Rightarrow11\le x\le14\\ \Rightarrow x\in\left\{11;12;13;14\right\}\)
a)
\(\left(\frac{1}{8}x-\frac{3}{8}\right)\left(2x^2+3\right)=0\)
+) 1/8x - 3/8 = 0
1/8x = 3/8
x = 3
+) 2x^2 + 3 = 0
2x^2 = -3
x^2 = -3/2
mà mũ chẵn luôn lớn hơn hoặc bằng 0 => loại
b)
\(\left|\frac{5}{3}x-1\right|+\frac{4}{5}\le\frac{4}{5}\)
\(\left|\frac{5}{3}x-1\right|\le0\)
mà \(\left|\frac{5}{3}x-1\right|\ge0\forall x\)
=> 5/3x - 1 = 0
5/3x = 1
x = 3/5
Vậy,..........
?? bài ez z tự làm đc mak
\(a,x-4=-7\Leftrightarrow x=-3\)
\(b,-2x+5=-7\Leftrightarrow-2x=-12\Leftrightarrow x=6\)
\(c,\left(4-x\right)-17=15\Leftrightarrow4-x=32\Leftrightarrow x=-28\)
\(d,8-2\left(2x-3\right)=14\Leftrightarrow8-4x+6=14\Leftrightarrow-4x=14-8-6\)
\(\Leftrightarrow-4x=0\Leftrightarrow x=0\)
\(f,|x-5|=11\Leftrightarrow\orbr{\begin{cases}x-5=11\\x-5=-11\end{cases}\Rightarrow\orbr{\begin{cases}x=16\\x=-6\end{cases}}}\)
\(g,1\le|x|\le5\)
\(\Rightarrow x=1;5;\pm2;\pm3;\pm4\)