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/x+4/15/-/-3,75/=-/-2,15/
/x+4/15/-15/4=-\(\frac{43}{20}\)
x+4/15=\(\frac{43}{20}+\frac{15}{4}\)
x+4/15=59/10
x=59/10-4/15
x=\(5\frac{19}{30}\)
\(\frac{-5}{x}=\frac{-y}{8}=\frac{18}{72}\)
\(\Leftrightarrow\frac{-5}{x}=\frac{-y}{8}=\frac{1}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}-\frac{5}{x}=\frac{1}{4}\\-\frac{y}{8}=\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-5.4:1\\-y=8.1:4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-20\\-y=2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-20\\y=-2\end{cases}}}\)
vậy x=-20 và y=-2
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Giải
Ta có:\(\frac{x}{5}+1=\frac{1}{y-1}\)
\(\Rightarrow\frac{x}{5}+\frac{5}{5}=\frac{1}{y-1}\)
\(\Rightarrow\frac{x+5}{5}=\frac{1}{y-1}\)
\(\Leftrightarrow\left(x+5\right).\left(y-1\right)=5\)
Vì \(x;y\in Z\)
\(\Rightarrow x+5;y-1\in Z\)
\(\Rightarrow x+5;y-1\inƯ\left(5\right)=\left\{-5;-1;1;5\right\}\)
Ta lập bảng:
x + 5 | -5 | -1 | 1 | 5 |
y - 1 | -1 | -5 | 5 | 1 |
x | -10 | -6 | -4 | 0 |
y | 0 | -4 | 6 | 2 |
Vậy có 4 cặp ( x ; y ) cần tìm.
~~~~~~~~ *** ~~~~~
15 - ( 13 + x) = x- ( 23 - 17 )
15-13-x=x-23+17
2x=(-15)+(-13)-23+17
2x=(-28)-23+17
2x=(-51)+17
2x=(-34)
x=(-34):2
x=(-17)
15 - ( 13 + x ) = x - ( 23 - 17 )
15 - 13 - x = x - 6
-x - x = -6 + ( -2 )
-x + ( -x ) = -8
2.(-x) = -8
-x = -8 : 2
-x = -4
=> x = 4
Vậy x = 4
Chúc bạn học giỏi
Ta có:
15 chia hết cho 2x-1
Suy ra 2x-1 thuộc Ư(15)
mà Ư(15)={1;3;5;15}
*2x-1=1
=>2x=1+1=2
=>x=2/2=1
*2x-1=3
=>2x=3+1=4
=>x=4/2=2
*2x-1=5
=>2x=5+1=6
=>x=6/2=3
*2x-1=15
=>2x=15+1=16
=>x=16/2=8
Vậy x=1;2;3;8.
Ta có:
\(\frac{1}{-3}< \frac{x}{3}\le0\)
\(\Rightarrow\frac{1}{-3}< \frac{x}{3}\le\frac{0}{3}\)
\(\Rightarrow\frac{-1}{3}< \frac{x}{3}\le\frac{0}{3}\)
\(\Rightarrow-1< x\le0\)
\(\Rightarrow x=0\)
vậy: \(x=0\)
Đổi 1/-3 = -1/3 ; 0 = 0/3
Suy ra -1 < x <_ 0
Suy ra x = 0
Vậy x = 0
( x - 340 ) . 15 = 0
x - 340 = 0 .15
x - 340 = 0
x = 0 + 340
x = 340 .
Ta có:
\(Coi\) \(A=\left(\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}+\frac{1}{340}\right).x=1\frac{1}{5}\)
\(=\left(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\right).x=\frac{6}{5}\)
\(\Rightarrow3A=\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+\frac{3}{17.20}\right).x=\frac{6}{5}.3=\frac{18}{5}\) \(=\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+\frac{1}{17}-\frac{1}{20}\right).x\)
\(=\left(\frac{1}{2}-\frac{1}{20}\right).x\)
\(=\frac{9}{20}.x=\frac{18}{5}\)
\(\Rightarrow x=\frac{18}{5}:\frac{9}{20}=8\)
Vậy \(x=8\).
\(5300x=340\left(x+\frac{1}{15}\right)\)
\(\Leftrightarrow5300x=340x+\frac{68}{3}\)
\(\Leftrightarrow5300x-340x=\frac{68}{3}\)
\(\Leftrightarrow4960x=\frac{68}{3}\)
\(\Leftrightarrow x=4960:\frac{68}{3}\)
\(\Leftrightarrow x=....\)(tự tính)
5300x=340x +\(\frac{68}{3}\)
4960x=\(\frac{68}{3}\)
x=\(\frac{34}{7440}\)