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a: \(\dfrac{x-3}{5-x}=\dfrac{5}{7}\left(x\ne5\right)\)
=>7(x-3)=5(5-x)
=>7x-21=25-5x
=>12x=46
=>x=23/6
b: \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)(ĐKXĐ: \(x\notin\left\{1;-7\right\}\))
=>(x-2)(x+7)=(x+4)(x-1)
=>\(x^2+5x-14=x^2+3x-4\)
=>5x-14=3x-4
=>2x=10
=>x=5(nhận)
\(đk:x\ne-5\\ \dfrac{x-3}{x+5}=\dfrac{5}{7}\\ =>7\left(x-3\right)=5.\left(x+5\right)\\ =>7x-21=5x+25\\ =>7x-5x=25+21\\ =>2x=46\\ =>x=23\left(t/m\right)\)
\(\dfrac{x-3}{x+5}=\dfrac{5}{7}\left(x\ne-5\right)\)
\(\Rightarrow7\left(x-3\right)=5\left(x+5\right)\)
\(\Rightarrow7x-21=5x+25\)
\(\Rightarrow7x-21-5x-25=0\)
\(7x-5x-21-25=0\)
\(2x-46=0\)
\(2x=0+46=46\)
\(x=\dfrac{46}{2}=23\left(tmđk\right)\)
\(5^{12}:5^{x+2}=\left(-5\right)^3.\left(-5\right)^7\)
\(\Rightarrow5^{12-x-2}=\left(-5\right)^{3+7}\)
\(\Rightarrow5^{10-x}=\left(-5\right)^{10}\)
\(\Rightarrow5^{10-x}=5^{10}\)
\(\Rightarrow10-x=10\)
\(\Rightarrow x=0\)
\(\Leftrightarrow x+\dfrac{1}{2}=-\dfrac{7}{5}\cdot\dfrac{5}{2}=-\dfrac{7}{2}\\ \Leftrightarrow x=-\dfrac{7}{2}-\dfrac{1}{2}=-4\)
Ta có: \(\frac{x-3}{x+5}=\frac{5}{7}\Rightarrow7\left(x-3\right)=5\left(x+5\right)\)
\(7x-21=5x+25\)
\(7x-21-5x=25\)
\(2x-21=25\)
\(2x=25+21=46\)
\(x=46:2=23\)
Tick nha. Cần gấp
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{7^x.7^2+7^x.7+7^x}{57}=\frac{7^x.\left(7^2+7+1\right)}{57}=7^x\)
\(\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}=\frac{5^{2x}+5^{2x}.5+5^{2x}.5^3}{131}=\frac{5^{2x}\left(1+5+5^3\right)}{131}=\frac{25^x.131}{131}=25^x\)
\(\Rightarrow7^x=25^x\Rightarrow x=0\)
\(\dfrac{5}{x}=\dfrac{7}{5}\)
\(\Rightarrow x.7=5.5\)
\(\Rightarrow x.7=25\)
\(\Rightarrow x=25:7\)
\(\Rightarrow x=\dfrac{25}{7}\)
\(\dfrac{5}{x}=\dfrac{7}{5}\)
\(\Rightarrow x=\dfrac{5.5}{7}=\dfrac{25}{7}\)