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\(\left(x+184-278\right)-\left(184-278\right)=4\\\left(x+184-278\right)-\left(-94\right)=4\\ \left(x+184-278\right)+94= 4\\ \left(x+184-278\right)= 4-94\\ \left(x+184-278\right)=-90\\ x+184=-90+278\\ x+184=188\\ x=188-184\\ 4.\)
( x + 184 - 278 ) - ( 184 - 278 ) = 4
x + 184 - 278 - 184 + 278 = 4
x + 0 = 4
x = 4
a, ( 45 + y ) = 278 - 118
( 45 + y ) = 160
y = 160 - 45
y = 115
b, \(2,3y+\frac{1}{2}y-y=9\)
\(y\left(\frac{2}{3}+\frac{1}{2}-1\right)=9\) ( Đến đây bn tự quy đồng nha )
\(y.\frac{1}{6}=9\)
\(y=9:\frac{1}{6}=9.6=54\)
@@ Bài kia bó tay
\(\Leftrightarrow x+2\in\left\{1;-1;11;-11\right\}\)
hay \(x\in\left\{-1;-3;9;-13\right\}\)
Ta có:
\(3x+5\) ⋮ \(x-1\)
⇒ \(3x-3+8\) ⋮ \(x-1\)
⇒ \(3\left(x-1\right)+8\) ⋮ \(x-1\)
⇒ 8 ⋮ \(x-1\)
⇒ \(x-1\inƯ\left(8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
⇒ \(x\in\left\{2;0;3;-1;5;-3;9;-7\right\}\)
Vậy: ...
3x-(x-5)=25
=> 3x-x+5=25
=> 2x=25-5
=> 2x=20
=> x=20:2
=> x= 10
\(3x-\left(\dfrac{2}{5}+x\right)=0,4\)
\(3x-\dfrac{2}{5}-x=0,4\)
\(2x-\dfrac{2}{5}=\dfrac{2}{5}\)
\(2x=\dfrac{2}{5}+\dfrac{2}{5}\)
\(2x=\dfrac{4}{5}\)
\(x=\dfrac{2}{5}\)
Ta có: \(3x-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{5}\)
\(\Leftrightarrow2x-\dfrac{2}{5}=\dfrac{2}{5}\)
\(\Leftrightarrow2x=\dfrac{4}{5}\)
hay \(x=\dfrac{2}{5}\)
tu lam di