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3x + 4 + 3x + 2 = 270
35 + 33 = 270
= > x = 5 - 4 = 1
=> x = 3 - 2 = 1
=> x = 1
3x + 4 + 3x + 2 = 270
10.3x + 2 = 270
3x + 2 = 270 : 10
3x + 2 = 27
3x + 2 = 33
x + 2 = 3
x = 3 - 2
x = 1
[(2x - 4) + 9]3 = 36
(2x - 4 + 9)3 = 729
x = 2
\(3^{x+4}+3^{x+2}=270\)
\(< =>3^x.81+3^x.9=270\)
\(< =>3^x=\frac{270}{90}=3< =>x=1\)
\(3^{x+4}+3^{x+2}=270\)
\(\Leftrightarrow3^x.81+3^x.9=270\)
\(\Leftrightarrow3^x\left(81+9\right)=270\)
\(\Leftrightarrow3^x.90=270\)
\(\Leftrightarrow3^x=3\)
\(\Leftrightarrow x=1\)
3x+2=369
=>x+2=69
x=69-2
x=67
2x-5=810
2x-5=230
=>x-5=30
x=30+5
x=35
3x+2+3x=810
3x.32+3x=810
3x.(32+1)=810
3x.10=810
3x=810:10
3x=81
3x=34
=>x=4
5x+1-5x=500
5x.5-5x=500
5x.(5-1)=500
5x.4=500
5x=500:4
5x=125
5x=53
=>x=3
a) 3x+2 = 369
x + 2 = 69
x = 69 - 2
x = 67
b) 2x-5 = 810
2x-5 = 230
x - 5 = 30
x = 30 + 5
x = 35
c) 3x+2 + 3x = 810
3x . 9 + 3x . 1 = 810
3x . ( 9 + 1 ) = 810
3x . 10 = 810
3x = 810 : 10
3x = 81
3x = 34
=> x = 4
d) 5x+1 - 5x = 500
5x . 5 - 5x . 1 = 500
5x . ( 5 - 1 ) = 500
5x . 4 = 500
5x = 500 : 4
5x = 125
5x = 53
=> x = 3
a) X-4,2=58,4-24,9
X-4,2= 33,5
X= 33,5+4,2
X=37,7
b) \(\frac{4}{5}-X=\frac{1}{5}+\frac{2}{7}\)
\(\frac{4}{5}-X=\frac{17}{35}\)
\(X=\frac{4}{5}-\frac{17}{35}\)
\(X=\frac{5}{7}\)
c)\(X-140:35=270\)
\(X-4=270\)
X=274
d) 3.X + 2.X = 25
X.(3+2) = 25
X = 25:(3+2)
X=5
a) b) \(\frac{4}{5}-x=\frac{1}{5}+\frac{2}{7}\)
x – 4,2 = 58,4 – 24,9 \(\frac{4}{5}-x=\frac{17}{35}\)
x – 4,2 = 33,5 \(x=\frac{4}{5}-\frac{17}{35}\)
x = 33,5 + 4,2 \(x=\frac{11}{35}\)
x = 37,7
c) d) \(3\times x+2\times x=25\)
x – 140 : 35 = 270 \(x\times\left(3+2\right)=25\)
x - 4 = 270 \(x\times5=25\)
x = 270 + 4 \(x=25\div5\)
x = 274 \(x=5\)
\(2^{x+4}+2^{x+3}+2^{x+2}+2^{x+1}=1920\)
\(15.2^{x+1}=1920\)
\(2^{x+1}=1920:15\)
\(2^{x+1}=128\)
\(2^{x+1}=2^7\)
\(x+1=7\)
\(x=7-1\)
\(x=6\)
=> x = 6
ko chép lại đầu bài nha
=(53x+800):7020=(49x+147):6000
=(53x+800).6000=70
x=145,0369515
lưu ý:mik làm theo cách suy luận nhé @@@
b, \(2^{x+3}+2^x=144\Rightarrow2^x\times2^3+2^x=144\Rightarrow2^x\times\left(2^3+1\right)\Rightarrow2^x\times9=144\Rightarrow2^x=16\Rightarrow x=4\)
tự kl nah bạn
\(3^x+3^{x-2}=270\)
\(3^x+3^{x-2}=10\cdot3^3\)\(\Rightarrow\frac{3^x+3^{x-2}}{3}=3^{x-3}+3^{x-5}=10\)
\(3^{x-3}=\left(3^x\right)-3^3\)
\(\frac{3^x}{3^3}+\frac{3^x}{3^5}=10\)
\(\Rightarrow10\cdot3^{x-5}=2\cdot5\)
\(\Rightarrow3^{x-5}=1;x=5\)