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(2x-6)(2x-18)=0
\(\Rightarrow\hept{\begin{cases}2x-6=0\\2x-18=0\end{cases}}\Rightarrow\hept{\begin{cases}2x=6\\2x=18\end{cases}}\Rightarrow\hept{\begin{cases}x=3\\x=9\end{cases}}\)
Vậy ...
a)2x - 12 = 18
2x=18+12
2x=30
x=30:2
x=15
b)6^2 - (x+3)=45
36-(x+3)=45
x+3=36-45
x+3=-9
x=-9-3
x=-12
a, (2\(x\) -5) + 17 = 6
2\(x\) - 5 = 6 - 17
2\(x\) - 5 = - 11
2\(x\) = - 11 + 5
2\(x\) = -6
\(x\) = -3
b, (-18).\(x\) = - 36
\(x\) = -36 : (-18)
\(x\) = 2
c, 15 - (-11\(x\) - 7) = -22
- 11\(x\) - 7 = 15 + 22
-11\(x\) - 7 = 37
11\(x\) = -37 - 7
11\(x\) = - 44
\(x\) = - 4
a) \(\left(2x-5\right)+17=6\Rightarrow2x-5=-11\Rightarrow2x=-6\Rightarrow x=-3\)
b) \(\left(-18\right)x=-36\Rightarrow x=\left(-36\right):\left(-18\right)=2\)
c) \(15-\left(-11x-7\right)=-22\)
\(\Rightarrow15+11x+7=-22\)
\(\Rightarrow11x=-22-7-15\)
\(\Rightarrow11x=-44\)
\(\Rightarrow x=-44:11=-4\)
a: 18:(x-3)=6
=>x-3=18:6=3
=>x=3+3=6
b: \(3^{x-1}+4=85\)
=>\(3^{x-1}=81\)
=>\(3^{x-1}=3^4\)
=>x-1=4
=>x=5
c: 2x+3x=55
=>5x=55
=>x=55/5=11
d: \(\left(x-3\right)^3+11=53\)
=>\(\left(x-3\right)^3=53-11=42\)
=>\(x-3=\sqrt[3]{42}\)
=>\(x=\sqrt[3]{42}+3\)
a) 18 : (x - 3) = 6
x - 3 = 18 : 6
x - 3 = 3
x = 3 + 3
x = 6
b) 3ˣ⁻¹ + 4 = 85
3ˣ⁻¹ = 85 - 4
3ˣ⁻¹ = 81
3ˣ⁻¹ = 3⁴
x - 1 = 4
x = 4 + 1
x = 5
c) 2x + 3x = 55
5x = 55
x = 55 : 5
x = 11
d) Sửa đề:
(x - 3)³ - 11 = 53
(x - 3)³ = 53 + 11
(x - 3)³ = 64
(x - 3)³ = 4³
x - 3 = 4
x = 4 + 3
x = 7
a, 7\(x\).(\(x\) - 10) = 0
\(\left[{}\begin{matrix}7x=0\\x-10=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\)
Vậy \(x\in\) {0; 10}
b, 17.(3\(x\) - 6).(2\(x\) - 18) = 0
\(\left[{}\begin{matrix}3x-6=0\\2x-18=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}3x=6\\2x-18=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=6:3\\x=18:2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=9\end{matrix}\right.\)
\(-6x=18\)
\(\Leftrightarrow x=\frac{18}{-6}\)
\(\Leftrightarrow x=-3\)
\(2x-\left(-3\right)=7\)
\(\Leftrightarrow2x=7-3\)
\(\Leftrightarrow2x=4\)
\(\Leftrightarrow x=\frac{4}{2}\)
\(\Leftrightarrow x=2\)
\(\left|x\right|< 6\)
\(\Leftrightarrow x\in\left\{\pm1;...\pm5\right\}\)
a , - 6x = 18
=> x = 18 : ( -6 )
=> x = -3 thuộc Z
Vậy x = - 3
b , 2x - ( - 3 ) = 7
2x + 3 = 7
=> 2x = 7 - 3
=> 2x = 4
=> x = 4 : 2
=> x = 2 thuộc Z
Vậy x = 2
c , | x | < 6
=> \(\left|x\right|\in\left\{1;2;3;4;5\right\}\)
=> \(x\in\left\{\pm1;\pm2;\pm3;\pm4;\pm5\right\}\)
Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16
7+x=-16
x=-16-7
x=-23
2) 2x – 35 = 15
2x=15+35
2x=50
x=50:2
x=25
3) 3x + 17 = 12
3x=12-17
3x=-5
x=-5/3
4) (2x – 5) + 17 = 6
2x-5=6-17
2x-5=-11
2x=-11+5
2x=-6
x=-6:2
x=-3
5) 10 – 2(4 – 3x) = -4
2(4-3x)=10-(-4)
2(4-3x)=14
4-3x=14:2
4-3x=7
3x=4-7
3x=-3
x=-3:3
x=-1
6) - 12 + 3(-x + 7) = -18
3(-x+7)=-18-(-12)
3(x+7)=-6
x+7=-6:3
x+7=-2
x=-2-7
x=-9
x + 18 = 6 - 2x
x + 2x = 6 - 18
3x = - 12
x = -4
=.= hk tốt!!
x+2x = 6 - 18
3x = -12
x = -12 : 3
x = -4
Vậy......