Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}\right)=1\)
\(4x+\left(1-\frac{1}{16}\right)=1\)
\(4x+\frac{15}{16}=1\)
\(4x=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{64}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\frac{15}{16}=1\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{16}\div4\)
\(x=\frac{1}{64}\)
Vậy ...
Ta có:
(1/2 + 1/4 + 1/8 + 1/16) = 8/16 + 4/16 + 2/16 + 1/16 = 15/16.
1/2 + 1/6 + 1/12 + 1/20 +…+ 1/132 = 1/(1.2) + 1/(2.3) + 1/(3.4) + 1/(4.5) +…+1/(11.12)
= (1 – 1/2) + (1/2 – 1/3) + (1/3 – 1/4) + (1/4 – 1/5) +…+ (1/11 – 1/12)
= 1 – 1/12 = 11/12
Vậy x = (15/16) : (11/12) = 45/44.
(1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
(1-1/2+1/2-1/4+1/4-1/8+1/8-1/16):x=1/1x2+1/2x3+1/3x4+1/4x5+...+1/11x12
(1-1/16):x=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/11-1/12
15/16:x=1-1/12
15/16:x=11/12
x=15/16:11/12
x=45/44
\(\left(\frac{1}{2}+x\right)+\left(\frac{1}{4}+x\right)+\left(\frac{1}{8}+x\right)+\left(\frac{1}{16}+x\right)=1\)
\(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)+\left(x+x+x+x\right)=1\)
\(\frac{15}{16}+4x=1\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{64}\)
( x + x + x + x ) + ( \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\) ) = 1
x * 4 + \(\frac{15}{16}\) = 1
x * 4 = 1 - \(\frac{15}{16}\)
x * 4 = \(\frac{1}{16}\)
x = \(\frac{1}{16}\) : 4
x = \(\frac{1}{64}\)
1/2+1/4+1/6+1/8+1/16):x=3/1*2+3/2*3+3/3*4+...+3/15*16
\(\frac{53}{48}:x=3(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{15.16})\)
\(\frac{53}{48}:x=3(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{15}-\frac{1}{16})\)
\(\frac{53}{48}:x=3(1-\frac{1}{16})\)
\(\frac{53}{48}:x=\frac{45}{16}\)
\(x=\frac{53}{48}:\frac{45}{16}\)
\(x=\frac{53}{135}\)
Chúc bạn học tốt
1/ `|x|=10<=> x=\pm 10`
2/ `|x-8|=0<=>x-8=0<=>x=8`
3/ `7+|x|=12<=>|x|=5<=>x=\pm 5`
4/ `|x+1|=3`
$\Leftrightarrow\left[\begin{array}{1}x+1=3\\x+1=-3\end{array}\right.\\\Leftrightarrow\left[\begin{array}{1}x=3\\x=-4\end{array}\right.$
5/ `15-x=16-(14-42)`
`<=>15-x=16+28`
`<=>15-x=44`
`<=>x=-29`
6/ `210-(x-12)=168`
`<=>210-x+12=168`
`<=>222-x=168`
`<=>x=54`
3) Tìm số tự nhiên x, biết:
a) \(2^x=4\)
\(2^x=2^2\)
\(\Rightarrow x=2\)
___________
b) \(2^x=1\)
\(2^x=2^0\)
\(\Rightarrow x=0\)
___________
c) \(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
___________
d) \(3^x=9\)
\(3^x=3^2\)
\(\Rightarrow x=2\)
___________
e) \(5^x=125\)
\(5^x=5^3\)
\(\Rightarrow x=3\)
___________
f) \(8^x=64\)
\(8^x=8^2\)
\(\Rightarrow x=2\)
___________
h) \(3^{x+1}=3^2\)
\(\rightarrow x+1=2\)
\(x=2-1\)
\(x=1\)
\(\Rightarrow x=1\)
Chúc bạn học tốt
a: 2^x=4
=>2^x=2^2
=>x=2
b: 2^x=1
=>2^x=2^0
=>x=0
c: 2^x=16
=>2^x=2^4
=>x=4
d; 3^x=9
=>3^x=3^2
=>x=2
e: 5^x=125
=>5^x=5^3
=>x=3
f: 8^x=64
=>8^x=8^2
=>x=2
f: 3^x+1=3^2
=>x+1=2
=>x=1
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\Rightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(\Rightarrow4x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}\right)=1\)
\(\Rightarrow4x+1-\frac{1}{16}=1\)
\(\Rightarrow4x=1-1+\frac{1}{16}=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{16}:4=\frac{1}{64}\)
vậy \(x=\frac{1}{64}\)