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a) 35 chia hết cho : 5 ; 7 ; 35
b) 25 ; 50 ; 100 .
c ) 15 ; 3 ; 5
d ) Là 1 nhé
\(x^2=x^3\\ \Rightarrow x^2-x^3=0\\ \Rightarrow x^2\left(1-x\right)\\ \Rightarrow\left[{}\begin{matrix}x^2=0\\1-x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
11 chia hết cho 2a+9 -> 2a+9 \(\in\)Ư(11)={1;-1;11;-11}
Ta có bảng sau:
2a+9 1 -1 11 -11
a -4 -5 1 -10
Vậy a ={-10;-5;-4;-1}
Khi y \(\ge3\) => 2x < 0 => x \(\in\varnothing\)
=> y < 3
=> y \(\in\left\{0;1;2\right\}\)
Khi y = 2 => 2x = 64 => x = 7
Khi y = 1 => 2x = 484 => x \(\in\varnothing\)
Khi y = 0 => 2x =504 => x \(\in\varnothing\)
Vậy x = 7 ; y = 2
\(Khi\text{ y}\ge3\Rightarrow2^x< 0\Rightarrow x\in\varnothing\)
\(\Rightarrow y< 3\)
\(\Rightarrow y\in\left\{0;1;2\right\}\)
\(Khi\text{ y}=2\Rightarrow2^x=64\Rightarrow x=7\)
\(Khi\text{ y}=1\Rightarrow2^x=484\Rightarrow x\in\varnothing\)
\(Khi\text{ y}y=0\Rightarrow2^x=504\Rightarrow x\in\varnothing\)
\(\text{Vậy x=7;y=2}\)
\(\text{Hok tốt!}\)
\(\text{@Kaito Kid}\)
1.
a) \(2^x=128\)
\(2^x=2^7\)
\(=>x=7\)
b) \(8^{x-1}=64\)
\(8^{x-1}=8^2\)
\(=>x-1=2\)
\(x=2+1\)
\(=>x=3\)
c) \(3+3^x=30\)
\(3^x=30-3\)
\(3^x=27=3^3\)
\(=>x=3\)
d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?
e) \(3^2.x=3^5\)
\(x=3^5:3^2\)
\(=>x=3^3=27\)
f) \(\left(2x-1\right)^3=343\)
\(\left(2x-1\right)^3=7^3\)
\(=>2x-1=7\)
\(2x=7+1\)
\(2x=8\)
\(x=8:2\)
\(=>x=4\)
\(#Wendy.Dang\)
a,\(2^x\)=128 b,\(8^{x-1}\)=64 c,3+\(3^x\)=30 d,x+2=64
\(2^7\)=128 \(8^{x-1}\)=\(8^2\) \(3^x\)=30-3 x=64-2
=>x=7 =>x-1=2 \(3^x\)=27 x=62
x=2+1=3 \(3^x\)=\(3^3\)
=>x=3
e,\(3^2\).x=\(3^5\) f,(2x-\(1^3\))=343
x=\(3^5\):\(3^2\) 2x=1+343
x=27 2x=344
x=344:2
x=172
Tìm x bít
5(x+35)=515
x+35 =515:5
x+35 =103
x =103-35
x = 68
Vậy x = 68 .
x + 4131 : 35 = 5.32
x+17=45
x=45-17
x=28
x+4131:35=5 x 32
x+17=45
x=45+17
x=62
HOK TỐT