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a, x+4/7=7/4-1/4
x + 4/7 = 6/4
x = 6/4 - 4/7
x = 26/28
b, 9/2+(x-3/4)=25/4
x - 3/4 = 25/4 - 9/2
x - 3/4 = 7/4
x = 7/4 + 3/4
x = 10/4
a, x+4/7=7/4-1/4
x+4/7= 3/2
x = 3/2-4/7= 13/14
b,9/2+(x-3/4)=25/4
x-3/4 = 25/4 - 9/2 = 7/4
x= 7/4 + 3/4 = 5/2
a: =>x=3/7+3/5=15/35+21/35=36/35
b: =>x/35=4/5-5/7=28/35-25/35=3/35
=>x=3
c: =>x<3/4+8/4=11/4
=>\(x\in\left\{0;1;2;3\right\}\)
d: =>5/3<x<5/6+24/6=29/6
=>\(x\in\left\{2;3;4\right\}\)
e: =>x<10/12-9/12=1/12
=>x=0
f: =>2/3<x<12/6-5/6=7/6
=>x=1
a, \(\frac{2}{3}:\frac{5}{7}:\frac{x}{9}=\frac{2}{7}:\frac{3}{5}:\frac{10}{9}\Leftrightarrow\frac{2\times7\times9}{3\times5\times x}=\frac{2\times5\times9}{7\times3\times10}\Leftrightarrow\frac{42}{5\times x}=\frac{3}{7}\Leftrightarrow294=15\times x\Leftrightarrow x=19,6\)
Các phần sau tương tự.
Dùng phương pháp nhân chéo và kiểm tra trình độ tính toán, khả năng rút gọn.
Thay kết quả vào x để kiểm tra lại bài.
a) x + 5/7 = 5/4 + 1/2
suy ra x + 5/7 = 7/4
suy ra x= 7/4 - 5/7
suy ra x= 29/28
a) \(x+\frac{5}{7}-\frac{1}{2}=\frac{5}{4}\)
\(x+\frac{5}{7}=\frac{5}{4}+\frac{1}{2}\)
\(x+\frac{5}{7}=\frac{7}{4}\)
\(x=\frac{7}{4}-\frac{5}{7}\)
\(x=\frac{29}{28}\)
a) \(x+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}-\dfrac{1}{2}\)
\(x=\dfrac{6}{10}-\dfrac{5}{10}\)
\(x=\dfrac{1}{10}\)
b) \(x\times\dfrac{6}{7}=\dfrac{5}{21}\)
\(x=\dfrac{5}{21}:\dfrac{6}{7}\)
\(x=\dfrac{5}{21}\times\dfrac{7}{6}\)
\(x=\dfrac{5}{18}\)
c) \(x:\dfrac{4}{3}=\dfrac{8}{9}\)
\(x=\dfrac{8}{9}\times\dfrac{4}{3}\)
\(x=\dfrac{32}{27}\)
a: x=3/5-1/2=6/10-5/10=1/10
b: x=5/21:6/7=5/21x7/5=35/105=1/3
c: x=8/9x4/3=32/27
\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)
\(=3+\frac{35}{11}\times \frac{121}{245}\)
\(=3+\frac{11}{7}\)
\(= 3\frac{1}{7}(=\frac{22}{7})\)
Bài 1:
a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)
\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{6}{7}\)
b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)
\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)
\(\Rightarrow x=\dfrac{1}{6}\)
Lớp 4?
a) \(\dfrac{x+1}{4}=\dfrac{36}{x+1}\)
\(\Rightarrow\left(x+1\right)^2=144\)
\(\Rightarrow\left[{}\begin{matrix}x+1=12\\x+1=-12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=11\\x=-13\end{matrix}\right.\)
Vậy: \(x\in\left\{11;-13\right\}\)
b) \(\dfrac{x}{7}=\dfrac{55x-4}{28}\)
\(\Rightarrow4x=55x-4\)
\(\Rightarrow-51x=-4\)
\(\Rightarrow x=\dfrac{4}{51}\)
Vậy: \(x=\dfrac{4}{51}\)
a) \(\dfrac{x + 1}{4} = \dfrac{36}{x + 1} \)
\(\Rightarrow\) \(( x + 1 )( x + 1 ) = 36 . 4 \)
\(\Rightarrow ( x + 1 )^2 = 144 \)
\(\Rightarrow ( x + 1 )^2 = 12^2 = ( -12 )^2 \)
\(\Rightarrow\) \(x + 1 ∈ \) { \(12 ; -12 \) }
\(\Rightarrow \) \(x \) \(∈ \) { \(11 ; -13 \) }
Vậy \(x ∈ \) { \(11 ; -13 \) }
\(x+\dfrac{1}{4}=\dfrac{7}{2}\)
\(x=\dfrac{7}{2}-\dfrac{1}{4}\)
\(x=\dfrac{14}{4}-\dfrac{1}{4}\)
\(x=\dfrac{13}{4}\)
\(x\) + \(\dfrac{1}{4}\) = \(\dfrac{7}{2}\)
\(x\) = \(\dfrac{7}{2}\) - \(\dfrac{1}{4}\)
\(x\) = \(\dfrac{13}{4}\)