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1) (x - 2)2 - (x - 3)(x + 3) = 17
=> x2 - 4x + 4 - x2 + 9 = 17
=> -4x = 17 - 13
=> -4x = 4
=> x = -1
2) TTT
3) x2 + 6x - 147 = 0
=> x2 + 19x - 13x - 147 = 0
=> x(x + 19) - 13(x + 19) = 0
=> (x - 13)(x + 19) = 0
=> \(\orbr{\begin{cases}x-13=0\\x+19=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=13\\x=-19\end{cases}}\)
4) (3x - 5)(2x + 3) - 6x2 = 7
=> 6x2 + 9x - 10x - 15 - 6x2 = 7
=> -x - 15 = 7
=> -x = 7 + 15
=> -x = 22
=> x = -22
5) TL
1, \(5x\left(x-1\right)=x-1\Rightarrow5x\left(x-1\right)-\left(x-1\right)=0\)
\(\Rightarrow\left(x-1\right)\left(5x-1\right)=0\Rightarrow\orbr{\begin{cases}x-1=0\\5x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{5}\end{cases}}}\)
2, \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)
\(\Rightarrow24x^2-10x-24x^2+8x=30\) \(\Rightarrow-2x=30\Rightarrow x=-15\)
3, \(3x\left(3-2x\right)+6x\left(x-1\right)=15\) \(\Rightarrow9x-6x^2+6x^2-6x=15\Rightarrow3x=15\Rightarrow x=5\)
4, \(x\left(x-3\right)+x-3=0\Rightarrow\left(x-3\right)\left(x+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)
a, (3x - 5)(2x - 1) - (x + 2)(6x - 1) = 0
=> 6x^2 - 3x - 10x + 5 - (6x^2 - x + 12x - 2) = 0
=> 6x^2 - 13x + 5 - 6x^2 - 11x + 2 = 0
=> -24x + 7 = 0
=> - 24x = -7
=> x = 7/24
b, (3x - 2)(3x + 2) - (3x - 1)^2 = -5
=> 9x^2 - 4 - 9x^2 + 6x - 1 = -5
=> 6x - 5 = -5
=> 6x = 0
=> x = 0
c, x^2 = -6x - 8
=> x^2 + 6x + 8 = 0
=> x^2 + 2.x.3 + 9 - 1 = 0
=> (x + 3)^2 = 1
=> x + 3 = 1 hoặc x + 3 = -1
=> x = -2 hoặc x = -4
a. \(9\left(x+2\right)-3\left(x+2\right)=0\)
\(\Leftrightarrow9x+18-3x-6=0\)
\(\Leftrightarrow6x+12=0\)
\(\Leftrightarrow x=-2\)
e. \(\left(2x-1\right)^2-45=0\)
\(\Leftrightarrow4x^2-2x+1-45=0\)
\(\Leftrightarrow4x^2-2x-44=0\)
Đến đó tự giải tiếp nha!
c. \(2\left(2x-5\right)-3x=0\)
\(\Leftrightarrow4x-10-3x=0\)
\(\Leftrightarrow x-10=0\)
\(\Leftrightarrow x=10\)
g. \(2x^2-6x=0\)
\(\Leftrightarrow2x\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
(3x−4).(2x+1)−(6x+5).(x−3)=3
6x2+3x-8x-4-6x2+18x-5x+15=3
8x+11=3
8x=3-11
8x=-8
x=-8:8
x=-1
\(\left(3x-4\right).\left(2x+1\right)-\left(6x+5\right).\left(x-3\right)=3\)
\(\Leftrightarrow6x^2+3x-8x-4-6x^2-18x+5x-15=3\)
\(\Leftrightarrow-18x-19=3\)
\(\Leftrightarrow-18x=-16\)
\(\Leftrightarrow x=\frac{8}{9}\)