Question

[Thảo Minh Donna]

Tìm x biết :

\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)

Answer 1

[Hoàng Phúc]

\(\Rightarrow\frac{x-1}{2009}-1+\frac{x-2}{2008}-1=\frac{x-3}{2007}+\frac{x-4}{2006}\)

\(\Rightarrow\frac{x-1-2009}{2009}+\frac{x-2-2008}{2008}=\frac{x-3-2007}{2007}+\frac{x-4-2006}{2006}\)

\(\frac{x-1-2009}{2009}+\frac{x-2-2008}{2008}-\frac{x-3-2007}{2007}-\frac{x-4-2006}{2006}=0\)

\(\Rightarrow\frac{x-2010}{2009}+\frac{x-2010}{2008}-\frac{x-2010}{2007}-\frac{x-2010}{2006}=0\)

=>(x-2010)(1/2009+1/2008-1/2007-1/2006)=0

mà 1/2009+1/2008-1/2007-1/2006 khác 0

=>x-2010=0=>x=2010

Answer 2

[Lonely Member]

cho mìh đi rồi gửi lại đề bài qua tin nhắn cho mìh, mìh sẽ giải cho bn