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\(\dfrac{2}{3}.3^{x+1}-7.3^x=-405\)
\(\Rightarrow\dfrac{2}{3}.3^x.3^1-7.3^x=-405\)
\(\Rightarrow2.3^x-7.3^x=-405\)
\(\Rightarrow3^x.\left(2-7\right)=-405\)
\(\Rightarrow3^x.-5=-405\)
\(\Rightarrow3^x=\dfrac{-405}{-5}\)
\(\Rightarrow3^x=81\)
Vì \(3^4=81\) nên \(x=4\)
\(\dfrac{2}{3}.3^{x+1}-7.3^x=-405\)
\(\Leftrightarrow\dfrac{2}{3}.3.3^x-7.3^x=-405\)
\(\Leftrightarrow3^x\left(2-7\right)=-405\)
\(\Leftrightarrow3^x.\left(-5\right)=-405\)
\(\Leftrightarrow3^x=81\)
\(\Leftrightarrow3^x=3^4\)
\(\Leftrightarrow x=4\)
Vậy..
a) \(\frac{2}{3}.3^{x+1}-7.3^x=-405\)
=> \(\frac{2}{3}.3^x.3-7.3^x=-405\)
=> \(2.3^x-7.3^x=-405\)
=> \(3^x\left(2-7\right)=-405\)
=> \(3^x.\left(-5\right)=-405\)
=> \(3^x=-405:\left(-5\right)\)
=> \(3^x=81\)
=> \(x=4\)
b) \(\frac{3}{1-2x}=\frac{-5}{3x-2}\)
=> \(3\left(3x-2\right)=-5\left(1-2x\right)\)
=> \(9x-6=-5+10x\)
=> \(9x-10x=-5+6\)
=> \(-x=1\)
=> \(x=-1\)
Bài 1:
Giải:
Ta có: \(\frac{1+3y}{12}=\frac{1+7y}{4x}=\frac{1+1+3y+7y}{12+4x}=\frac{2+10y}{2\left(6+2x\right)}=\frac{2\left(1+5y\right)}{2\left(6+2x\right)}=\frac{1+5y}{6+2x}=\frac{1+5y}{5x}\)
+) Xét \(1+5y=0\Rightarrow y=\frac{-1}{5}\Rightarrow1+5y=0\) ( loại )
+) Xét \(1+5y\ne0\Rightarrow6+2x=5x\)
\(\Rightarrow5x-2x=6\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=2\)
Mà \(\frac{1+3y}{12}=\frac{1+5y}{5x}\)
\(\Rightarrow\frac{1+3y}{12}=\frac{1+5y}{10}\)
\(\Rightarrow10\left(1+3y\right)=12\left(1+5y\right)\)
\(\Rightarrow10+30y=12+60y\)
\(\Rightarrow10-12=60y-30y\)
\(\Rightarrow-2=30y\)
\(\Rightarrow y=\frac{-1}{15}\)
Vậy \(x=2,y=\frac{-1}{15}\)
tra mạng đi Min Cute