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\(\left(x+9\right)+\left(x-8\right)+\left(x+7\right)+\left(x-6\right)+\left(x+5\right)+\left(x-4\right)+\left(x+3\right)+\left(x-2\right)+\left(x+1\right)=95.9\\ =>x+9+x-8+x+7+x-6+x+5+x-4+x+3+x-2+x+1=855\\ =>\left(x+x+x+x+x+x+x+x+x\right)+\left(9-8+7-6+5-4+3-2+1\right)=855\\ =>9x+5=855\\ =>9x=855-5\\ =>9x=850\\ =>x=\dfrac{850}{9}\)
\(\left(x+9\right)+\left(x-8\right)+...+\left(x-2\right)+\left(x+1\right)\)
\(=x+9+x-8+...+x-2+x+1\)
\(=\left(x+9+x-8\right)+...+\left(x+5\right)+...+\left(x-2+x+1\right)\)
(Ta gộp 4 số vào 1 tổng, riêng (x+5) là ta giữ nguyên)
\(=\left(2x-1\right)+...+\left(x+5\right)+...+\left(2x-1\right)\)
\(=4\left(2x-1\right)+\left(x+5\right)\)
\(=8x-4+x-5\)
\(=9x-9\) (1)
Từ bài toán trên, ta có:
\(\left(x+9\right)+\left(x-8\right)+...+\left(x-2\right)+\left(x+1\right)=95,9\)
Từ (1)
\(\Leftrightarrow9x-9=95,9\)
\(9x=95,9-9\)
\(x=86,9:9\)
\(x=9,6\left(5\right)\)
1) 201,5 - 36,4 : 2,5 x 0,9
= 201,5 - 14,56 x 0,9
= 201,5 - 13,104
= 188,396
2)
a) X - 31,27 = 101
X = 101 + 31,27
X = 132,27
b) X + 1031 = 14,5
X = 14,5 - 1031
X = -1016,5
c) 87,5 x X = 4725
X = 4725 : 87,5
X = 54
d) 186 : X = 3720
X = 186 : 3720
X = 1/20
3)
a) 1,47 x 3,6 + 1,47 x 6,4
= 1,47 x (3,6 + 6,4)
= 1,47 x 10
= 14,7
b) 25,8 x 1,02 - 25,8 x 1,01
= 25,8 x ( 1,02 - 1,01)
= 25,8 x 0,01
=0,258
1) 188,396
2) Tìm X
a) X = 132,27
b) X = - 1016,5
c) X = 54
d) X = 20
3. Tính thuận tiện nhất
a) 1,47 x 3,6 + 1,47 x 6,4 = 1,47 x (3,6 + 6,4)
= 1,47 x 10
= 14,7
b) 25,8 x 1,02 - 25,8 x 1,01 = 25,8 x (1,02 - 1,01)
= 25,8 x 0,01
= 0,258
Nha bạn
1. a
\(\dfrac{8}{5}-\dfrac{5}{6}\cdot\dfrac{3}{4}\)
\(=\dfrac{8}{5}-\dfrac{5\cdot3}{3\cdot2\cdot4}\)
\(=\dfrac{8}{5}-\dfrac{5}{8}=\dfrac{39}{40}\)
1.b
\(=\dfrac{7}{8}+\dfrac{5}{6}\cdot\dfrac{3}{2}\)
\(=\dfrac{7}{8}+\dfrac{5\cdot3}{3\cdot2\cdot2}\)
\(=\dfrac{7}{8}+\dfrac{5}{4}=\dfrac{17}{8}\)
2.a
\(\dfrac{4}{5}+x=\dfrac{11}{10}\)
\(x=\dfrac{11}{10}-\dfrac{4}{5}=\dfrac{3}{10}\)
2.b
\(x-\dfrac{3}{4}=\dfrac{5}{7}\)
\(x=\dfrac{5}{7}+\dfrac{3}{4}=\dfrac{41}{28}\)
a) x + x : 4 *1,6 + x : 6*3,6 = 222
\(\Rightarrow x+x\cdot0,4+x.0,6=222\)
\(\Rightarrow x.\left(1+0,4+0,6\right)=222\)
\(\Rightarrow x.2=222\)
\(\Rightarrow x=222:2=111\)
b) \(\left(x+0,2\right)+\left(x+0,4\right)+...+\left(x+1\right)=9,6\)
\(\Rightarrow\left(x+x+x+x+x\right)+\left(0,2+0,4+0,6+0,8+1\right)\) =9,6
\(\Rightarrow5.x+\left[\left(1-0,2\right):0,2+1\right].\left(1+0,2\right):2\) = 9,6
\(\Rightarrow5.x+3=9,6\)
\(\Rightarrow5.x=9,6-3=6,6\)
\(\Rightarrow x=6,6:5=1,32\)
(x+0,2)+(x+0,4)+(0,6)+(0,8)+(x+1)=9,6
5x+(0,2+0,4+0,6+0,8+1)=9,6
5x+3=9,6
5x =9,6-3
5x =6,6
x =6,6:5
x =1,32
a) x + 3.6 = 4.26 + 7.52 b) 0.12 * x = 6
x + 3.6 = 11.78 x = 6 : 0.12
x = 11.78 - 3.6 x = 50
x = 8.18
a: =>3,6<x<8,5
hay \(x\in\left\{4;5;6;7;8\right\}\)
b: =>3,5<x<3,6
hay \(x\in\left\{3.51;3.52;3.53;3.54;3.55;...\right\}\)
( x+x+x+x+x+x) + (9-8+7-6+5-4)=63,6
x x 6 +3=63,6
x x 6 = 63,6-3
x x 6 =60,6
x =60,6:6
x =10,1
nha bn
cam on bn nhieu
Ta có:
(x + 9) + (x - 8) + (x + 7) + (x - 6) + (x + 5) + (x - 4) = 63,6
x + 9 + x - 8 + x + 7 + x - 6 + x + 5 + x - 4 = 63,6
(x + x + x + x + x + x) + (9 - 8 + 7 - 6 + 5 - 4) = 63,6
6x + 3 = 63,6
6x = 63,6 - 3
6x = 60,6
x = 60,6 : 6
x = 10,1
Vậy x = 10,1
a: 93,68-x:3,6=91,38
=>x:3,6=93,68-91,38=2,3
=>\(x=2,3\times3,6=8,28\)
b: \(27,72:3+x\times6=28,44\)
=>\(x\times6+9,24=28,44\)
=>\(x\times6=28,44-9,24=19,2\)
=>x=19,2:6=3,2
\(a,93,68-x:3,6=91,38\\ x:3,6=2,3\\ x=8,28.\\ b,27,72:3+x\times6=28,44\\ 9,24+x\times6=28,44\\ x\times6=19,2\\ x=3,2.\)