Question

[OoO Kún Chảnh OoO]

tim x biet :

a) ( 2x²+4 ) - (x²-3/2 ) = (-3+4x²)+ ( -4x²/3+1)

b) ( I xI -4) - ( 2- I-xI ) = 1/3 . I xI -5

Answer 1

[bui huynh nhu 898]

\(2x^2+4-\left(x^2-\frac{3}{2}\right)=\left(-3+4x^2\right)+\left(-\frac{4x^2}{3}+1\right)\)

\(2x^2-x^2+4+\frac{3}{2}=\)\(-3+1+4x^2-\frac{4x^2}{3}\)

\(x^2+\frac{11}{2}=-2+-\frac{16x^2}{3}\)

\(x^2+\frac{16x^2}{3}=\frac{-11}{2}-2=-\frac{15}{2}\)

\(\frac{19x^2}{3}=-\frac{15}{2}\)

\(19x^2=\frac{-15}{2}.3=-\frac{45}{2}\)

\(x^2=\frac{-45}{2}:19=-\frac{45}{38}\)