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19 tháng 12 2017

a) ta có : \(\left(2x-7\right)-\left(x+135\right)=0\Leftrightarrow2x-7-x-135=0\)

\(\Leftrightarrow x-142=0\Leftrightarrow x=142\) vậy \(x=142\)

b) ta có : \(12-\left(39-3x\right)=0\Leftrightarrow12-39+3x=0\Leftrightarrow3x-27=0\)

\(\Leftrightarrow3x=27\Leftrightarrow x=\dfrac{27}{3}=9\) vậy \(x=9\)

c) ta có : \(\left(14-3x\right)+\left(6+x\right)=0\Leftrightarrow14-3x+6+x=0\)

\(\Leftrightarrow20-2x=0\Leftrightarrow2x=20\Leftrightarrow x=\dfrac{20}{2}=10\) vậy \(x=10\)

25 tháng 10 2015

dái wa      

25 tháng 10 2015

Giúp mình đi mình đang cần gấp

10 tháng 2 2018

a. -3

b. -71

c. -40

d. 358

e. ?i

f. 10

mình chỉ cho đáp án được thôi vì mình đang gấp nên ko thể trình bày được, câu e mình ko hiểu bạn ghi gì hết. bạn gửi lại câu e đi.

10 tháng 2 2018

rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrjrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr                                                                    hãy tìm chữ j  

15 tháng 1 2018

a) 3x + 12 = 2x - 4

=> 3x - 2x = -4 - 12

=> 1x = -16

=> x = -16

vậy___

b) 14 - 3x = -x + 4

=> 14-4 = -x+3x

=> 10 = 2x

=> x = 10 : 2

=> x = 5

vậy_____

\(c) ( 2x - 8 ) ( x + 6 ) = 0\)

\(\Rightarrow\orbr{\begin{cases}2x-8=0\\x+6=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-6\end{cases}}\)

vậy_____

15 tháng 8 2017

Mọi người giúp mình nhanh nhé ! Mình đang cần gấp ok

(2x-7)-135=0

2x-7=0+135

2x-7=135

2x=135+7

2x=142

   x=142:2

   x=71

vậy x=71

b)122+(37-3x)=0

              37-3x=0-122

               37-3x=-122

                      3x=37-(-122)

                       3x=159

                          x=159:3

                          x=53

 vậy x=53 

nhớ **** cho mình nha

11 tháng 8 2017

chuan com me nau

27 tháng 2 2020

Bài 1 Tìm x biết:

a)65-(29-x)=32

65 -29+x=31

x=31-65+29

x=-5

b)(x+5)-(x+23)=x-34

x+5 -x +23 = x-34

(x-x)+ (23+5)=x-34

0+28=x-34

28=x-34

28+34=x

62=x

=>x=62

c)(16-x)+(x-38)=x+44

16-x+x-38=x+44

-x+x-x=44-16+38

-x=36

=>x=-36

d)-12+3(-x+7)=-18

3(-x+7)=-18+12

3(-x+7)=-6

-x+7=-6:3

-x+7=-2

-x=-2-7

-x=-9

=>x=9

27 tháng 2 2020

Baif 2

d)|7-x|=10

=> \(\left[{}\begin{matrix}7-x=10\\7-x=-10\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=7-10\\x=-10-7\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=-3\\x=-17\end{matrix}\right.\)

e)(x-6).(7-2x)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}x-6=0\\7-2x=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0+6\\2x=7\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=6\\x=7:2\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=6\\x=3,5\end{matrix}\right.\)

f)(9-x).(2x+8)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}9-x=0\\2x+8=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0+9\\2x=-8\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=9\\x=-4\end{matrix}\right.\)

g)x(-x+8).(-3x-18)=0

\(\Rightarrow\) \(\left[{}\begin{matrix}x=0\\-x+8=0\\-3x-18=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\-x=0+8\\-3x=0+18\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\-x=8\\-3x=18\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\x=-8\\x=18:\left(-3\right)\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\x=-8\\x=-6\end{matrix}\right.\)

h)(-x+8).(x-54).(-24-x)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}-x+8=0\\x-54=0\\-24-x=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}-x=8\\x=0+54\\-x=0+24\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=8\\x=54\\-x=24\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=8\\x=54\\x=-24\end{matrix}\right.\)

18 tháng 9 2016

a ) 2x - 1 = 7

     2x        = 7 + 1

      2x         = 8

        x         = 8 : 2

        x         = 4

b ) 3 ( x + 5 ) = 21

         ( x + 5 ) = 21 : 3

         ( x + 5 ) = 7

            x         = 2

c ) 20 - ( 3x - 1 ) = 15

             ( 3x - 1 ) = 20 - 15

             ( 3x - 1 ) = 5

                3x        = 6

                  x         = 2

d ) ( x - 135 ) -120 = 0

      ( x - 135 )          = 120

       x                        = 120  + 135

       x                        = 255

18 tháng 9 2016

a)2x - 1 = 7

=>2x=8

=>x=4

b) 3(x+5) = 21

=>x+5=7

=>x=2

c) 20 - (3x - 1) = 15

=>3x-1=5

=>3x=6

=>x=2

d) (x  - 135) - 120 = 0

=>x-135=120

=>x=155

27 tháng 7 2015

a. |3x-6|=0

=> 3x-6=0

=> 3x=6

=> x=6:3

=> x=2

b. |7-2x| \(\ge0\)

mà |7-2x|=-8

=> không tồn tại x

c. |5x+6|=14

=> 5x+6=14        hoặc 5x+6=-14

=> 5x=14-6        hoặc 5x=-14-6

=> 5x=8              hoặc   5x=-20

=> x=8/5             hoặc        x=-4

27 tháng 7 2015

a) => 3x - 6= 0

=> 3x = 6

=> x = 2

b) |7 - 2x| \(\ge\) 0.

Mà đề cho |7 - 2x| = -8

=> x \(\in\) rỗng

c) |5x + 6| = 14

=> 5x + 6 = 14 hoặc 5x + 6 = -14

=> 5x = 8 hoặc 5x = -20

=> x = 8/5 hoặc x = -4