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\(\frac{72-x}{3}=\frac{x-18}{5}\)
\(\Rightarrow\frac{\left(72-x\right).5}{15}=\frac{3\left(x-18\right)}{15}\)
\(\Rightarrow\left(72-x\right).5=3\left(x-18\right)\)
\(\Rightarrow360-5x=3x-54\)
\(\Rightarrow-3x-5x=-360-54\)
\(\Rightarrow-8x=-414\)
\(\Rightarrow x=51,75\)
+) Vì \(\frac{72-x}{3}=\frac{x-18}{5}\)
\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)
\(5.72-5x=3x-3.18\)
\(360-5x=3x-54\)
\(-5x-3x=-54-360\)
\(-8x=-414\)
\(x=-414:\left(-8\right)\)
\(x=51,75\)
Vậy x = 51,75
Ta có : \(\frac{72-x}{3}=\frac{x-18}{5}\)
\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)
\(\Rightarrow360-5x=3x-54\)
\(\Rightarrow360-54=5x-3x\)
\(\Rightarrow306=2x\) hay \(2x=306\)
x = 306 : 2 \(\Rightarrow x=153\)
Vậy x = 153
Mình không chắc chắn lắm ! Bạn thử kiểm tra lại nha !
\(\frac{x}{3}=\frac{y}{5}\Rightarrow\frac{x}{3}:\frac{y}{5}=1\Rightarrow\frac{x}{3}.\frac{5}{y}=1\Rightarrow\frac{x}{y}=\frac{3}{5}\)
mà \(x+y=72\)
vậy +) \(x=\frac{3}{5+3}-72\)
\(=\frac{3}{8}-72\)
\(=27\)
+) \(y=72-27\)
\(=45\)
thank trc ^__^
\(\frac{72-x}{x-18}=\frac{x}{5}\)
=> 5(72 - x) = x(x - 18)
=> 360 - 5x = x2 - 18x
=> x2 - 13x = 360
=> x2 - 6,5x - 6,5x + 42,25 = 360 + 42,25
=> x(x - 6,5) - 6,5(x - 6,5) = 402,25
=> (x - 6,5)2 = 402,25
=> \(\orbr{\begin{cases}x=\sqrt{402,25}+6,5\\x=-\sqrt{402,25}+6,5\end{cases}}\)
\(\frac{72-x}{3}=\frac{x-18}{5}\)
\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)
\(\Rightarrow360-5x=3x-54\)
\(\Rightarrow-5x-3x=-54-360\)
\(\Rightarrow-8x=-414\)
\(\Rightarrow x=207\)
Theo tính chất dãy tỉ số bằng nhau ta có:
x/3=y/5=x+y/3+5=72/8=9
Suy ra: x=9.3=27
y=9.5=45
\(\frac{x}{3}=\frac{y}{5}\Rightarrow x=3k\) ; \(y=5k\)
\(x+y=72\Rightarrow3k+5k=20\Rightarrow8k=20\Rightarrow k=\frac{20}{8}=\frac{5}{2}\)
\(\Leftrightarrow\frac{x}{3}=\frac{5}{2}\Rightarrow x=\frac{5}{2}.3=\frac{15}{2}\)
\(\Leftrightarrow\frac{y}{5}=\frac{5}{2}\Rightarrow y=\frac{5}{2}.5=\frac{25}{2}\)
Vậy \(x=\frac{15}{2};y=\frac{25}{2}\)
c) \(\left|x\right|=3,5\Rightarrow\left[{}\begin{matrix}x=3,5\\x=-3,5\end{matrix}\right.\)
d) \(\left|x\right|=-2,7\Rightarrow x\in\varnothing\)
l) \(\left|x+\dfrac{3}{4}\right|-5=-2\Rightarrow\left|x+\dfrac{3}{4}\right|=3\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=3\\x+\dfrac{3}{4}=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3-\dfrac{3}{4}\\x=-3-\dfrac{3}{4}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\\x=\dfrac{15}{4}\end{matrix}\right.\)
Đính chính câu l \(x=-\dfrac{15}{4}\) không phải \(x=\dfrac{15}{4}\)
\(\frac{x}{3}=\frac{y}{5}=\frac{x+y}{3+5}=\frac{72}{8}=9\)
\(\frac{x}{3}=9=>x=27;\frac{y}{5}=9=>y=45\)
Câu sau tương tự
Chúc bạn học tốt
\(\left(x-5\right)^2=\left(18\dfrac{1}{3}:5\right).\dfrac{11}{3}\)
\(\Leftrightarrow\left(x-5\right)^2=\dfrac{55}{3}.\dfrac{1}{5}.\dfrac{11}{3}\)
\(\Leftrightarrow\left(x-5\right)^2=\dfrac{121}{9}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=\dfrac{11}{3}\\x-5=-\dfrac{11}{3}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{26}{3}\\x=\dfrac{4}{3}\end{matrix}\right.\)
\(\Leftrightarrow5\left(72-x\right)=3\left(x-18\right)\\ \Leftrightarrow360-5x=3x-54\\ \Leftrightarrow360-5x-3x+54=0\\ \Leftrightarrow414-8x=0\\ \Leftrightarrow x=\dfrac{207}{4}\)