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`4x(x-5)-(x-1) (4x-3)-5=0`
`=> 4x*x - 4x*5 - ( x*4x-3*x-1*4x+ 1*3) -5=0`
`=> 4x^2 - 20x-(4x^2 -3x-4x+3)-5=0`
`=> 4x^2 - 20x-4x^2+3x+4x-3-5=0`
`=>-13x-8=0`
`=> -13x=8`
`=> x=-8/13`
Vậy `x=-8/13`
`4x(x-5)-(x-1)(4x-3)-5 = 0`
`=> 4x^2 - 20x - (4x^2 -3x-4x+3)= 5`
`=> 4x^2 - 20x - 4x^2 + 3x + 4x -3 = 5`
`=> (4x^2 - 4x^2) - (20x - 3x - 4x) = 8`
`=> -13x = 8`
`=> x = -8/13`
a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)
b, \(-2x+2=2\Leftrightarrow x=0\)
c, \(-2x-6=-8\Leftrightarrow x=1\)
\(\dfrac{4x-5}{7-4x}=\dfrac{7x-28}{26-7x}\)
\(\Leftrightarrow104x-28x^2-130+35x=49x-28x^2-196+112x\)
\(\Leftrightarrow-22x=-66\)
hay x=3
\(\Rightarrow\left(4x-5\right)\left(26-7x\right)=\left(7-4x\right)\left(7x-28\right)\\ \Rightarrow104x-28x^2-130+35x=49x-196-28x^2+112x\\ \Rightarrow-22x=-66\Rightarrow x=3\)
a/Ta có: M(x)+N(x) = (2x5 - 4x3 + 2x2 + 10x - 1) + (-2x5 + 2x4 + 4x3 + x2 + x - 10)
= 2x5 - 2x5 - 4x3 + 4x3 + 2x4 + 2x2 + x2 + 10x + x -1 - 10
= 2x4 + 3x2 + 11x - 11
b/ Ta có: A(x) = N(x)-M(x) = (-2x5 + 2x4 + 4x3 + x2 + x - 10) - (2x5 - 4x3 + 2x2 + 10x - 1)
= -2x5 - 2x5 + 2x4 + 4x3 + 4x3 + x2 - 2x2 + x - 10x -10 + 1
= -2x5 + 2x4 + 8x3 - x2 - 9x -9
4x - ( x + \(\frac{1}{2}\)) = 2x - ( \(\frac{1}{2}\)- 5 )
=> 4x - x - \(\frac{1}{2}\)= 2x - \(\frac{1}{2}\)+ 5
=>3x - \(\frac{1}{2}\)= 2x - \(\frac{1}{2}\)+ 5
=> 3x - 2x - \(\frac{1}{2}\)+ \(\frac{1}{2}\)= 5
=> x - 0 = 5
=> x = 5 + 0
=> x = 5
4x - (x+1/2)=2x-(1/2-5)
<=> 4x - x - 1/2 = 2x - 1/2 + 5
<=> 3x = 2x +5
<=> x = 5
Ta thấy \(\left|x+\frac{1}{8}\right|\ge0\forall x;\left|x+\frac{2}{8}\right|\ge0\forall x;\left|x+\frac{5}{8}\right|\ge0\forall x\)
\(\Rightarrow\left|x+\frac{1}{8}\right|+\left|x+\frac{2}{8}\right|+\left|x+\frac{5}{8}\right|\ge0\)
\(\Rightarrow4x\ge0\Rightarrow x\ge0\)
\(\Rightarrow x+\frac{1}{8}+x+\frac{2}{8}+x+\frac{5}{8}=4x\)
\(\Rightarrow3x+1=4x\)
=> x = 1 (t/m)
Vậy x=1
| 4x - 1 | + 4x =5
TH1: \(4x-1\ge0\)
\(4x-1+4x=5\)
\(4x+4x=5+1\)
\(8x=6\)
\(x=\frac{3}{4}\)( thỏa mãn \(4x-1\ge0\))
TH2: 4x - 1 <0
\(-\left(4x-1\right)+4x=5\)
\(-4x+1+4x=5\)
\(1=5\) ( vô lí)
Vậy \(x=\frac{3}{4}\)