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đổi 75%=3/4.Ta có:
3/4xX+3/4xX+X=30
(3/4+3/4+1)xX=30
5/2 x X=30
X = 30:5/2
X = 12
\(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)
\(\frac{5}{2}\times x=30\)
\(x=30\div\frac{5}{2}\)
\(x=12\)
a,100%X-40%X=3,6
=>60%X=3,6
=>X=3,6:60%
=>X=6
b,30%X+100%=52
=>130%X=52
=>X=52:130%
=>X=40
ta có:\(\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{99.100}=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{50}\right)=\frac{1}{51}+...+\frac{1}{100}\)
\(\frac{2012}{51}+\frac{2012}{52}+...+\frac{2012}{100}=2012\left(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\right)\)
bài toán được viết lại như sau:
\(\left(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\right).x=2012\left(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\right)\)
\(\Rightarrow x=2012\left(\frac{1}{51}+...+\frac{1}{100}\right):\left(\frac{1}{51}+...+\frac{1}{100}\right)\)
\(\Rightarrow x=2012\)
vậy x=2012
a) \(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+x=30\)
\(x\times\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\times\frac{5}{2}=30\)
\(x=30\div\frac{5}{2}\)
\(x=30\times\frac{2}{5}\)
\(x=12\)
b) \(x-40\%=36\)
\(x-\frac{2}{5}=36\)
\(x=36+\frac{2}{5}\)
\(x=36\frac{2}{5}\)
c) \(30\%\times x+x=52\)
\(\frac{3}{10}\times x+x=52\)
\(x\times\left(\frac{3}{10}+1\right)=52\)
\(x\times\frac{13}{10}=52\)
\(x=52\div\frac{13}{10}\)
\(x=40\)
40
Chúc bạn may mắn
(30% + 1) x X = 52
130% x X = 52
X = 52 : 130%
X = 40