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5 tháng 1 2017
a, 3 - 2x = 3 . (5 - x) + 4
3 - 2x = 15 - 3x + 4
-2x + 3x = 15 + 4 - 3
x = 16
b, 4 - (7x + 2017) = 6 . (5 - x) - 2017
4 - 7x - 2017 = 30 - 6x - 2017
-7x + 6x = 30 - 2017 - 4 + 2017
-x = 26
x = -26
c, 15 - x . (x + 1) = 4 - x^2 + 2x
15 - x^2 - x = 4 - x^2 + 2x
-x^2 - x + x^2 - 2x = 4 - 15
-3x = -11
x = 11/3
d, -4 . (x - 5) + 2016 = 3 . (8 - x) - (2x - 2016)
-4x + 20 + 2016 = 24 - 3x - 2x + 2016
-4x + 3x +2x = 24 + 2016 - 20 - 2016
x = 4
đúng 100%
10 tháng 4 2022
a: \(\Leftrightarrow2x-2+\left(-8\right)\left(x-2\right)=1\cdot\left(-8\right)\left(x+3\right)\)
=>2x-2-8x+16=-8x-24
=>2x+14=-24
=>2x=-38
hay x=-19
b: \(\Leftrightarrow-\left(2x-1\right)-\left[9-1\right]\cdot\left(2x-1\right)=3+2\left(2x-1\right)-28\)
=>-2x+1-8(2x-1)=3+6x-2-28
=>-2x+1-16x+8=6x-27
=>-18x+9=6x-27
=>-24x=-36
hay x=3/2
HM
0
LT
0
DH
15 tháng 8 2017
\(\dfrac{1-2x}{2017}+\dfrac{2-2x}{2016}=\dfrac{3-2x}{2015}+\dfrac{4-2x}{2014}\)
\(\Rightarrow\left(\dfrac{1-2x}{2017}+1\right)+\left(\dfrac{2-2x}{2016}+1\right)=\left(\dfrac{3-2x}{2015}+1\right)+\left(\dfrac{4-2x}{2014}+1\right)\)
\(\Rightarrow\dfrac{2018-2x}{2017}+\dfrac{2018-2x}{2016}-\dfrac{2018-2x}{2015}-\dfrac{2018-2x}{2014}=0\)
\(\Rightarrow\left(2018-2x\right)\left(\dfrac{1}{2017}+\dfrac{1}{2016}-\dfrac{1}{2015}-\dfrac{1}{2014}\right)=0\)
Vì \(2017>2016>2015>2014\) nên
\(\dfrac{1}{2017}< \dfrac{1}{2016}< \dfrac{1}{2015}< \dfrac{1}{2014}\)
\(\Rightarrow\dfrac{1}{2017}+\dfrac{1}{2016}-\dfrac{1}{2015}-\dfrac{1}{2014}< 0\)
\(\Rightarrow2018-2x=0\Rightarrow x=1009\)
Vậy...........
Chúc bạn học tốt!!!
HD
15 tháng 8 2017
\(\dfrac{1-2x}{2017}+\dfrac{2-2x}{2016}=\dfrac{3-2x}{2015}+\dfrac{4-2x}{2014}\)
\(\Rightarrow\left(\dfrac{1-2x}{2017}+1\right)+\left(\dfrac{2-2x}{2016}+1\right)=\left(\dfrac{3-2x}{2015}+1\right)+\left(\dfrac{4-2x}{2014}+1\right)\)
\(\Rightarrow\dfrac{2018-2x}{2017}+\dfrac{2018-2x}{2016}-\dfrac{2018-2x}{2015}-\dfrac{2018-2x}{2014}=0\)
\(\Rightarrow\left(20418-2x\right)\left(\dfrac{1}{2017}+\dfrac{1}{2016}-\dfrac{1}{2015}-\dfrac{1}{2014}\right)=0\)
\(Ta\) \(có\)\(:\) \(2017>2016>2015>2014\)
\(\Rightarrow\dfrac{1}{2017}< \dfrac{1}{2016}< \dfrac{1}{2015}< \dfrac{1}{2014}\)
\(\Rightarrow\dfrac{1}{2017}+\dfrac{1}{2016}-\dfrac{1}{2015}-\dfrac{1}{2014}< 0\)
\(\Rightarrow2018-2x=0\)
\(\Rightarrow2x=2018-0\)
\(\Rightarrow2x=2018\)
\(\Rightarrow x=2018:2\)
\(\Rightarrow x=1009\)
GR
29 tháng 9 2017
a) 2x + 25 = 145
\(\Rightarrow\)2x = 145 - 25
\(\Rightarrow\)2x = 120
\(\Rightarrow\)x = 60
b) 216 : x + 34 : x = 10
\(\Rightarrow\)( 216 + 34) : x = 10
\(\Rightarrow\)250 : x = 10
\(\Rightarrow\)x = 250 : 10
\(\Rightarrow\)x = 25
c) 2017 : x - 17 : x = 1000
\(\Rightarrow\)( 2017 - 17 ) : x = 1000
\(\Rightarrow\)2000 : x = 1000
\(\Rightarrow\)x = 2000 : 1000
\(\Rightarrow\)x = 2
d) 4057 + (2x : 38 ) = 20395
\(\Rightarrow\)2x : 38 = 20395 - 4057
\(\Rightarrow\)2x : 38 = 16338
\(\Rightarrow\)2x = 16338 . 38
\(\Rightarrow\)2x = 620844
\(\Rightarrow\)x = 620844 : 2
\(\Rightarrow\)x = 310422
e) ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ... + ( x + 28 ) = 155 ( có 10 số hạng x )
\(\Rightarrow\)x + 1 + x + 4 + x + 7 + ... + x + 28 = 155
\(\Rightarrow\)10x + ( 1 + 4 + 7 + ... + 28 ) = 155
\(\Rightarrow\)10x + 145 = 155
\(\Rightarrow\)10x = 155 - 145
\(\Rightarrow\)10x = 10
\(\Rightarrow\)x = 1
NN
0
TM
0
10 tháng 9 2021
Bài 2:
a: Ta có: \(2^{x+1}\cdot3^y=12^x\)
\(\Leftrightarrow2^{x+1}\cdot3^y=2^{2x}\cdot3^x\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+1=2x\\x=y\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)