Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A:23x-18=14x
23x-14x=18
9x =18
x =18:9
x =2
Vậy ....
B:2x+1 :16 = 8
2x+1 =8x16
2x+1 =128
2x+1 =27
x+1 =7
x =7-1
x =6
Vậy ....
A
23x-18=14x
18=23x-14x
18=9x
2=x
B
2x+1:16=8
2x+1=128
2x+1=27
x+1=7
x=6
C
2x+4x=20
2x+4x=23+4.3
x=3
\(3^{2x+1}=243\)
\(\Rightarrow3^{2x+1}=3^5\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4:2\)
\(\Rightarrow x=2\)
\(3^2x+1=243\)
\(9x=243-1\)
\(9x=242\)
\(x=242:9\)
\(\Rightarrow x=\dfrac{242}{9}\)
1: =>3^x=81
=>x=4
2: =>2^x=8
=>x=3
3: =>x^3=2^3
=>x=2
4: =>x^20-x=0
=>x(x^19-1)=0
=>x=0 hoặc x=1
5: =>2^x=32
=>x=5
6: =>(2x+1)^3=9^3
=>2x+1=9
=>2x=8
=>x=4
7: =>x^3=115
=>\(x=\sqrt[3]{115}\)
8: =>(2x-15)^5-(2x-15)^3=0
=>(2x-15)^3*[(2x-15)^2-1]=0
=>2x-15=0 hoặc (2x-15)^2-1=0
=>2x-15=0 hoặc 2x-15=1 hoặc 2x-15=-1
=>x=15/2 hoặc x=8 hoặc x=7
1. Tìm số tự nhiên x biết:
1) \(3^x.3=243\)
\(3^x=243:3\)
\(3^x=81\)
\(3^x=3^4\)
\(\Rightarrow x=4\)
_____
2) \(7.2^x=56\)
\(2^x=56:7\)
\(2^x=8\)
\(2^x=2^3\)
\(\Rightarrow x=3\)
_____
3) \(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=3\)
_____
4) \(x^{20}=x\)
\(x^{20}-x=0\)
\(x\left(x^{19}-1\right)=0\)
\(\Rightarrow x=0\) hoặc \(x=1\)
5) \(2^x-15=17\)
\(2^x=17+15\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
_____
6) \(\left(2x+1\right)^3=9.81\)
\(\left(2x+1\right)^3=729=9^3\)
\(\rightarrow2x+1=9\)
\(2x=9-1\)
\(2x=8\)
\(x=8:2\)
\(\Rightarrow x=4\)
_____
7) \(x^6:x^3=125\)
\(x^3=125\)
\(x^3=5^3\)
\(\Rightarrow x=5\)
_____
8) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=7\\x=8\end{matrix}\right.\)
_____
9) \(3^{x+2}-5.3^x=36\)
\(3^x.\left(3^2-5\right)=36\)
\(3^x.\left(9-5\right)=36\)
\(3^x.4=36\)
\(3^x=36:4\)
\(3^x=9\)
\(3^x=3^2\)
\(\Rightarrow x=2\)
_____
10) \(7.4^{x-1}+4^{x+1}=23\)
\(\rightarrow7.4^{x-1}+4^{x-1}.4^2=23\)
\(4^{x-1}.\left(7+4^2\right)=23\)
\(4^{x-1}.\left(7+16\right)=23\)
\(4^{x-1}.23=23\)
\(4^{x-1}=23:23\)
\(4^{x-1}=1\)
\(4^{x-1}=4^1\)
\(\rightarrow x-1=0\)
\(x=0+1\)
\(\Rightarrow x=1\)
Chúc bạn học tốt
A) \(3^x\cdot3=243\)
\(\Leftrightarrow3^x=243:3=81\)
\(\Leftrightarrow3^x=3^4\)
\(\Leftrightarrow x=4\)
B) \(2^x-15=17\)
\(\Leftrightarrow2^x=17+15\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
C) \(\left(x-1\right)^2-7=42\)
\(\Leftrightarrow\left(x-1\right)^2=49\)
\(\Rightarrow\orbr{\begin{cases}x-1=7\\x-1=-7\end{cases}\Rightarrow\orbr{\begin{cases}x=8\\x=-6\end{cases}}}\)
1) ( 2016 . 2016 - 2013 . 2009 ) . X = 18
( 4064256 - 4044117 ) . X = 18
0 . X = 18
X = 18 : 0
X = \(\varnothing\)
Vậy X = \(\varnothing\)
2) ( \(\frac{1}{3}\) + \(\frac{1}{9}\) + \(\frac{1}{27}\) + \(\frac{1}{81}\) + \(\frac{1}{243}\) ) . X = \(\frac{2}{3}\)
\(\frac{121}{243}\) . X = \(\frac{2}{3}\)
X = \(\frac{2}{3}\) : \(\frac{121}{243}\)
X = \(\frac{162}{121}\)
CHÚC BẠN HỌC TỐT
32x -1 = 243
32x -1 = 35
2x-1=5
2x=5+1
2x=6
x=6:2
x=3
(2 x-1)3 = 27
(2 x-1)3 =33
2x-1=3
2x=3+1
2x=4
x=4:2
x=2
(2x-1)3= 27
(2x-1)3=33
2x-1=3
2x=3+1
2x=4
x=4:2
x=2
Ok, xong!!!