Câu hỏi của Nguyễn Thị An

Question

Tìm x biết -2/3.(x-1/4)=1/3 .(2x+1)

Nguyễn Lê Phước Thịnh · Accepted Answer

$-\dfrac{2}{3}\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}\left(2x+1\right)$=>$-\dfrac{2}{3}\cdot x+\dfrac{2}{3}\cdot\dfrac{1}{4}=\dfrac{1}{3}\cdot2x+\dfrac{1}{3}$=>$-\dfrac{2}{3}x+\dfrac{2}{12}=\dfrac{2}{3}x+\dfrac{1}{3}$=>$-\dfrac{4}{3}x=\dfrac{1}{3}-\dfrac{2}{12}=\dfrac{1}{6}$=>$x=-\dfrac{1}{6}:\dfrac{4}{3}=-\dfrac{1}{6}\cdot\dfrac{3}{4}=\dfrac{-1}{8}$Câu trả lời: $-\dfrac{2}{3}\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}\left(2x+1\right)$=>$-\dfrac{2}{3}\cdot x+\dfrac{2}{3}\cdot\dfrac{1}{4}=\dfrac{1}{3}\cdot2x+\dfrac{1}{3}$=>$-\dfrac{2}{3}x+\dfrac{2}{12}=\dfrac{2}{3}x+\dfrac{1}{3}$=>$-\dfrac{4}{3}x=\dfrac{1}{3}-\dfrac{2}{12}=\dfrac{1}{6}$=>$x=-\dfrac{1}{6}:\dfrac{4}{3}=-\dfrac{1}{6}\cdot\dfrac{3}{4}=\dfrac{-1}{8}$

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