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Bài giải
\(\left(\frac{1}{4}\text{ x }x-\frac{1}{8}\right)\text{ x }\frac{3}{4}=\frac{1}{4}\)
\(\left(\frac{1}{4}\text{ x }x-\frac{1}{8}\right)=\frac{1}{4}\text{ : }\frac{3}{4}\)
\(\frac{1}{4}\text{ x }x-\frac{1}{8}=\frac{1}{3}\)
\(\frac{1}{4}\text{ x }x=\frac{1}{3}+\frac{1}{8}\)
\(\frac{1}{4}\text{ x }x=\frac{11}{24}\)
\(x=\frac{11}{24}\text{ : }\frac{1}{4}=\frac{11}{24}\text{ x }4\)
\(x=\frac{11}{6}\)
\(\left(\frac{1}{4}\times a-\frac{1}{8}\right)\times\frac{3}{4}=\frac{1}{4}\)
\(\Rightarrow\frac{1}{4}\times a-\frac{1}{8}=\frac{1}{4}:\frac{3}{4}\)
\(\Rightarrow\frac{1}{4}\times a-\frac{1}{8}=\frac{1}{3}\)
\(\Rightarrow\frac{1}{4}\times a=\frac{1}{3}+\frac{1}{8}\)
\(\Rightarrow\frac{1}{4}\times a=\frac{11}{24}\)
\(\Rightarrow a=\frac{11}{24}:\frac{1}{4}\)
\(\Rightarrow a=\frac{11}{6}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\Leftrightarrow4\text{x}+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}=1\)
\(\Leftrightarrow4\text{x}+\frac{15}{16}=1\)
\(\Leftrightarrow4\text{x}=1-\frac{15}{16}\)
\(\Leftrightarrow4\text{x}=\frac{1}{16}\)
\(\Leftrightarrow x=\frac{1}{16}:4=\frac{1}{64}\)
(x+1/2)+(x+1/4)+(x+1/8)+(x+16)=1
(x.x.x.x)+(1/2+1/4+1/8+1/16=1
4x+(1/2+1/4+1/8+1/16)=1
4x+(8/16+4/16+2/16+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/16:4
=>x=1/64
tick cho mk nha bạn
ta có:(x+x+x+x)+(1/2+1/4+1/8+1/16)=1 4x+15/16=1 4x=1-15/16 4x=1/16 x=1/16:4=1/64 vậy x=1/64 Mình trả lời trước nhé
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(x+\frac{1}{2}+x+\frac{1}{4}+x+\frac{1}{8}+x+\frac{1}{16}=1\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
Đặt \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}\)
\(2A=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}\)
\(A=1-\frac{1}{2^4}\)
\(A=\frac{15}{16}\)
Thay A vào đẳng thức ta có
\(4x+\frac{15}{16}=1\)
\(4x=1-\frac{15}{16}\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{16}\div4\)
\(x=\frac{1}{64}\)
\(\Rightarrow x+\frac{1}{2}+x+\frac{1}{4}+x+\frac{1}{8}+x+\frac{1}{16}=1\)
\(\Rightarrow4\times x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(\Rightarrow4\times x+\frac{8+4+2+1}{16}=1\)
\(\Rightarrow4\times x+\frac{15}{16}=1\)
\(\Rightarrow4\times x=1-\frac{15}{16}=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{16}:4=\frac{1}{16}\times\frac{1}{4}\)
\(\Rightarrow x=\frac{1}{64}\).
`3/4 : x =1 1/2`
`=> 3/4 : x= 3/2`
`=>x= 3/4 : 3/2`
`=>x= 3/4 xx 2/3`
`=> x= 6/12`
`=> x= 1/2`
Vậy `x=1/2`
Thay `5/8-x` thì
`5/8-1/2= 5/8- 4/8=1/8`
\(\dfrac{3}{4}:x=1\dfrac{1}{2}\)
\(\dfrac{3}{4}:x=\dfrac{3}{2}\)
\(x=\dfrac{3}{4}:\dfrac{3}{2}\)
\(x=\dfrac{1}{2}\)
Vậy: \(\dfrac{5}{8}-x=\dfrac{5}{8}-\dfrac{1}{2}=\dfrac{1}{8}\)
(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1
4x+(1/2+1/4+1/8+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/64
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(4x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\frac{15}{16}=1\)
\(4x=1-\frac{15}{16}\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{16}:4\)
\(x=\frac{1}{64}\)
khong hieu can hoi
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