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\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)
\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)
\(x=1\div\left(-\frac{3}{5}\right)\)
\(x=-\frac{5}{3}\)
\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)
\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)
\(-\frac{4}{21}\cdot x=\frac{3}{5}\)
\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)
\(x=-\frac{63}{20}\)
\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{5}{7}\cdot x=1\)
\(x=1\div\frac{5}{7}\)
\(x=\frac{7}{5}\)
\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)
\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)
\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)
\(\frac{17}{33}\cdot x=\frac{9}{14}\)
\(x=\frac{9}{14}\div\frac{17}{33}\)
\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)
\(\left(x^2.y\right)^5.\left(x^2.y^2\right)^7.\left(x.y^2\right)^6.x^3\)
\(=x^{10}.y^5.x^{14}.y^{14}.x^6.y^{12}.x^3\)
\(=x^{33}.y^{31}\)
\(\frac{4^5\times3\div0,8\%-\left(-150\right)\times\left(-20\right)\times\left(-5\right)+1000\times5^4\div0,25}{\left(-64\right)\times\left(-1,25\right)\times\left(-2,5\right)\times\left(-5\right)}\)=\(\frac{4^5\times3\times1000:2^3-\left(-150\right)\times100+1000\times5^4\times100:5^2}{64\times125\times25\times5:1000}\)
= \(\frac{\left(2^2\right)^5\times3\times10^3:2^3+15\times10^3+10^5\times5^2}{64\times5^3\times5^2\times5:10^3}\) = \(\frac{2^7\times3\times10^3+3\times5\times10^3+10^5\times5^2}{\left(2^6\times5^6\right):10^3}=\frac{10^3\times\left(2^7\times3+3\times5+10^2\times5^2\right)}{10^3}\)
= \(\left(2^7\times3+3\times5+10^2\times5^2\right)\)
=> \(A=-2^{10}+2^7\times3+3\times5+10^2\times5^2=2^7\left(3-2^3\right)+3\times5+10^2\times5^2\)
= - 27 . 5 + 3.5 + 100 .25 = 5. (-27 + 3 + 500) = 5. 375 = 1875
a) \(\left(\dfrac{1}{2}x-3\right)\left(-\dfrac{1}{3}+x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-3=0\\-\dfrac{1}{3}+x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=0+3\\-\dfrac{1}{3}+x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3:\dfrac{1}{2}\\x=0-\left(-\dfrac{1}{3}\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=\dfrac{1}{3}\end{matrix}\right.\)
d) \(9x^2=1\)
\(\Leftrightarrow x^2=1:9\)
\(\Leftrightarrow x^2=\dfrac{1}{9}\)
\(\Leftrightarrow x^2=\left(\dfrac{1}{3}\right)^2\)
\(\Leftrightarrow x=\dfrac{1}{3}\)
\(a,\left(4+6\times x\right)\times5=290\)
\(4+6\times x=290:5\)
\(4+6\times x=58\)
\(6\times x=54\)
\(x=9\)
\(b,428\times x-12\times x-18\times x=5208000\)
\(\left(428-12-18\right)\times x=5208000\)
\(398\times x=5208000\)
\(x=\dfrac{5208000}{398}\)
\(c,5\times x+3,75\times x+1,25\times x=20\)
\(x\times\left(5+3,75+1,25\right)=20\)
\(x\times10=20\)
\(x=2\)
\(d,280:\left(7+3\times2\right)=4\)
Đề thiếu bạn nhé.
\(f,6\times\left(28-8\times x\right)=72\)
\(28-8\times x=12\)
\(8\times x=16\)
\(x=2\)
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