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24 tháng 3 2020
dài lắm nên mình làm tắt
1) (x - 5)^2 + (x + 3)^2 = 2(x - 4)(x + 4) - 5x + 7
<=> x^2 - 10x + 25 + x^2 + 6x + 9 = 2x^2 + 8x - 8x - 32 - 5x + 7
<=> 2x^2 - 4x + 34 = 2x^2 - 5x - 25
<=> -4x + 34 = -5x - 25
<=> x + 34 = -25
<=> x = -25 - 34
<=> x = - 59
2) (x + 3)(x - 2) - 2(x + 1)^2 = (x - 3)^2 - 2x^2 + 4x
<=> x^2 - 2x + 3x - 6 - 2x^2 - 4x - 2 = x^2 - 6x + 9 - 2x^2 + 4x
<=> -x^2 - 3x - 8 = -x^2 - 2x + 9
<=> -3x - 8 = -2x + 9
<=> -x - 8 = 9
<=> -x = 9 + 8
<=> x = -17
3) (x + 1)^3 - (x + 2)(x - 4) = (x - 2)(x^2 + 2x + 4) + 2x^2
<=> x^3 + 2x^3 + x + x^2 + 2x + 1 - x^2 + 4x - 2x + 8 = x^3 + 2x^2 + 4x - 2x^2 - 4x - 8 + 2x^2
<=> 2x^2 + 5x + 9 = 2x^2 - 8
<=> 5x + 9 = -8
<=> 5x = -8 - 9
<=> 5x = -17
<=> x = -17/5
4) (x - 2)^3 + (x - 5)(x + 5) = x(x^2 - 5x) - 7x + 3
<=> x^3 - 4x^2 + 4x - 2x^2 + 8x - 8 + x^2 - 5^2 = x^3 - 5x^2 - 7x + 3
<=> 12x - 33 = -7x + 3
<=> 19x - 33 = 3
<=> 19x = 3 + 33
<=> 19x = 36
<=> x = 36/19
5) (x + 4)(x^2 - 4x + 16) - x(x - 4)^2 = 8(x - 3)(x + 3)
<=> x^3 - 4x^2 + 16x + 4x^2 - 16x + 64 - x^3 + 8x^2 - 16x = 8x^2 - 72
<=> -16x + 64 = -72
<=> -16x = -72 - 64
<=> -16x = -136
<=> x = 136/16 = 17/2
6) 4(x - 1)(x + 2) - 5(x + 7) = (2x + 3)^2 - 5x + 3
<=> 4x^2 + 8x - 4x - 8 - 5x - 35 = 4x^2 + 12x + 9 - 5x + 3
<=> -x - 43 = 7x + 12
<=> -8x - 43 = 12
<=> -8x = 12 + 43
<=> -8x = 55
<=> x = -55/8
7) (x - 1)(x^2 + x + 1) + 3(x - 2)^2 = x(x^2 + 3x - 1)
<=> x^3 + x^2 + x - x^2 - x - 1 + 3x^2 - 12x + 12 = x^3 + 3x^2 - x
<=> 3x^2 - 12x + 11 = 3x^2 - x
<=> -12x + 11 = -x
<=> 11 = -x + 12x
<=> 11 = 11x
<=> x = 1
8) (x + 5)(x - 5) - (x + 3)(x^2 - 3x + 9) = 5 - x(x^2 - x - 2)
<=> x^2 - 25 - x^3 + 3x^2 - 9 - 3x^2 + 9x - 27 = 5 - x^3 + x^2 + 2x
<=> -52 - x^3 = 5 - x^3 + 2x
<=> -52 = 5x + 2x
<=> -5x - 2x = 52
<=> -7x = 52
<=> x = -52/7
9) (x + 2)^2 - 2(x + 3)(x - 4) = 5 - x(x - 3)
<=> x^2 + 4x + 4 - 2x^2 + 8x - 6x + 24 = 5 - x^3 + 3x
<=> 6x + 28 = 5 + 3x
<=> 6x + 28 - 3x = 5
<=> 3x + 28 = 5
<=> 3x = 5 - 28
<=> 3x = -23
<=> x = -23/3
10) (x + 7)(x - 7) - (x + 2)^2 = 5(x - 2) + (x - 7)
<=> x^2 - 49 - x^2 - 4x - 4 = 5x - 10 + x - 7
<=> -53 - 4x = 6x - 17
<=> -4x = 6x + 36
<=> -4x - 6x = 36
<=> -10x = 36
<=> x = -36/10 = -18/5
NV
8 tháng 1 2018
Bài 2: a) \(3x^3-3x=0\Leftrightarrow3x\left(x^2-1\right)=0\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
b) \(x^2-x+\frac{1}{4}=0\Leftrightarrow x^2-2.\frac{1}{2}+\left(\frac{1}{2}\right)^2=0\Leftrightarrow\left(x-\frac{1}{2}\right)^2=0\)
\(\Leftrightarrow x-\frac{1}{2}=0\Leftrightarrow x=\frac{1}{2}\)
NN
15 tháng 11 2017
2)
a) \(3x^3-3x=0\)
\(\Leftrightarrow3x\left(x^2-1\right)=0\)
\(\Leftrightarrow3x\left(x-1\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x=0\\x-1=0\\x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\\x=-1\end{matrix}\right.\)
Vậy x=0 ; x=-1 ; x=1
b) \(x^2-x+\dfrac{1}{4}=0\)
\(\Leftrightarrow x^2-2.x.\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2=0\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right)^2=0\)
\(\Leftrightarrow x-\dfrac{1}{2}=0\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
Vậy \(x=\dfrac{1}{2}\)
NN
15 tháng 11 2017
1)
a) \(\left(x-2\right)\left(x^2+3x+4\right)\)
\(\Leftrightarrow x^3+3x^2+4x-2x^2-6x-8\)
\(\Leftrightarrow x^3+x^2-2x-8\)
b) \(\left(x-2\right)\left(x-x^2+4\right)\)
\(=x^2-x^3+4x-2x+2x^2-8\)
\(=3x^2-x^3+2x-8\)
c) \(\left(x^2-1\right)\left(x^2+2x\right)\)
\(=x^4+2x^3-x^2-2x\)
d) \(\left(2x-1\right)\left(3x+2\right)\left(3-x\right)\)
\(=\left(6x^2+4x-3x-2\right)\left(3-x\right)\)
\(=18x^2+12x-9x-6-6x^3-4x^2+3x^2+2x\)
\(=17x^2+5x-6-6x^3\)
30 tháng 11 2017
\(4x^2-25+\left(2x+7\right)\left(5-2x\right)\)
\(=\left(2x-5\right)\left(2x+5\right)+\left(2x+7\right)\left(5-2x\right)\)
\(=\left(2x-5\right)\left(2x+5\right)-\left(2x-7\right)\left(2x-5\right)\)
\(=\left(2x-5\right)\left(2x+5-2x+7\right)\)
\(=\left(2x-5\right).12\)
Những câu khác làm tương tự
NH
1
10 tháng 9 2016
\(x^2-3=0\)
\(\Leftrightarrow x^2=3\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=3\\x=-3\end{array}\right.\)
\(\left(x+2\right).\left(x^2-2x+4\right)+x.\left(5-x\right).\left(x-5\right)=-17\)
\(\Leftrightarrow x^3-8+x.-\left(x-5\right).\left(x+5\right)=-17\)
\(\Leftrightarrow x^3-8-x.\left(x^2-25\right)=-17\)
\(\Leftrightarrow x^3-8-x^3+25x=-17\)
\(\Leftrightarrow-8+25x=-17\)
\(\Leftrightarrow25x=-9\)
\(\Leftrightarrow x=-\frac{9}{25}\)
\(x^3-3x^2-3x+1=0\)
\(\Leftrightarrow\left(x-1\right)^3=0\)
\(\Leftrightarrow x=1\)
NT
27 tháng 10 2017
a) \(=2xy^2\left(x^2+8x+15\right)\)
\(=2xy^2\left[\left(x^2+8x+16\right)-1\right]\)
\(=2xy^2\left[\left(x+4\right)^2-1\right]\)
\(=2xy^2\left(x+4+1\right)\left(x+4-1\right)\)
\(=2xy^2\left(x+5\right)\left(x-3\right)\)
mấy câu sau tự làm nha :*
29 tháng 10 2017
b,=(x^2-10x+25)-4
=(x-5)^2-2^2
=(x-5-2)(x-5+2)
=(x-7)(x-3)
Q
18 tháng 7 2017
a) \(\left(4x-1\right)^2-\left(3x+2\right)\left(3x-2\right)=\left(7x-1\right)\left(x+2\right)+\left(2x+1\right)^2-\left(4x^2+7\right)\)(1)
\(\Leftrightarrow\left(16x^2-8x+1\right)-\left(9x^2-4\right)=\left(7x^2+14x-x-2\right)+\left(4x^2+4x+1\right)-\left(4x^2+7\right)\)
\(\Leftrightarrow16x^2-8x+1-9x^2+4=7x^2+13x-2+4x^2+4x+1-4x^2-7\)
\(\Leftrightarrow7x^2-8x+5=7x^2+17x-8\)
\(\Leftrightarrow7x^2-8x-7x^2-17x=-8-5\)
\(\Leftrightarrow-25x=-13\)
\(\Leftrightarrow x=\dfrac{13}{25}\)
Vậy tập nghiệm phương trình (1) là \(S=\left\{\dfrac{13}{25}\right\}\)