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5 + ( x + 27 ) = 64
( x + 27 ) = 64 - 5 ( x + 27 ) = 59 x = 59 - 27 x = 32a) \(\Rightarrow x+27=59\Rightarrow x=32\)
b) \(\Rightarrow x-2=39\Rightarrow x=41\)
c) \(\Rightarrow x+5=-322\Rightarrow x=-327\)
d) \(\Rightarrow5x=35\Rightarrow x=7\)
e) \(\Rightarrow4\left(x-5\right)=56\Rightarrow x-5=14\Rightarrow x=19\)
f) \(\Rightarrow15+x=37\Rightarrow x=22\)
g) \(\Rightarrow7\left(13-x\right)=35\Rightarrow13-x=5\Rightarrow x=8\)
h) \(\Rightarrow10\left(x+1\right)=100\Rightarrow x+1=10\Rightarrow x=9\)
a)16. x2 = 64
x2 = 64 : 16
x2 = 4
x2 = 22
⇒ x = 2
b) (5.x - 2) - 64 = -36
(5.x - 2) = -36 + 64
5.x - 2 = 28
5.x = 28 + 2
5.x = 30
x = 30 : 5
x = 6
c) (2x - 10).(5 - x) = 0
TH1: 2x - 10 = 0
2x = 0 + 10
2x = 10
x = 10 : 2
x = 5
TH2: 5 - x = 0
x = 5 - 0
x = 5
⇒ Vậy x = 5.
a) 4x = 64
4x = 43
=> x = 3
c) 5x+2 = 25
5x+2 = 52
=> x + 2 = 2
=> x = 0
mình thấy phần b hình như sai đề
Có:
a)\(4^x=64=4^3=>x=3\)
b)\(2^{x+1}=25=>2^x.2=25\Rightarrow2^x=25:2=12,5\)
=> ....
c)\(5^{x+2}=25\Rightarrow5^x.5^2=25=>5^x.25=25=>5^x=25:25=1\)
=>x=0
a: =>(x-5)(x+5)=0
=>x=5 hoặc x=-5
b: \(\Leftrightarrow\left[{}\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Leftrightarrow x\in\left\{1;-3\right\}\)
c: =>x-3=4
hay x=7
d: =>x+1=7
hay x=6
e: =>x=0 và y-2=0
hay x=0 và y=2
a) \(\left|x\right|-\frac{7}{6}=\frac{9}{15}\)
=> \(\left|x\right|=\frac{9}{15}+\frac{7}{6}=\frac{53}{30}\)
=> \(\orbr{\begin{cases}x=\frac{53}{30}\\x=-\frac{53}{30}\end{cases}}\)
b) \(\left|x-\frac{4}{3}\right|=\frac{1}{6}\)
=> \(\orbr{\begin{cases}x-\frac{4}{3}=\frac{1}{6}\\x-\frac{4}{3}=-\frac{1}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{7}{6}\end{cases}}\)
c) \(\left|x-\frac{4}{3}\right|-\frac{1}{3}=\frac{1}{2}\)
=> \(\left|x-\frac{4}{3}\right|=\frac{1}{2}+\frac{1}{3}\)
=> \(\left|x-\frac{4}{3}\right|=\frac{5}{6}\)
=> \(\orbr{\begin{cases}x-\frac{4}{3}=\frac{5}{6}\\x-\frac{4}{3}=-\frac{5}{6}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{13}{6}\\x=\frac{1}{2}\end{cases}}\)
d) \(\frac{8}{3}-\left|\frac{7}{9}-x\right|=-\frac{1}{5}\)
=> \(\left|\frac{7}{9}-x\right|=\frac{43}{15}\)
=> \(\orbr{\begin{cases}\frac{7}{9}-x=\frac{43}{15}\\\frac{7}{9}-x=-\frac{43}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x=-\frac{94}{45}\\x=\frac{164}{45}\end{cases}}\)
e) \(\left|x-\left(\frac{1}{4}\right)^2\right|-\frac{25}{64}=0\)
=> \(\left|x-\frac{1}{16}\right|=\frac{25}{64}\)
=> \(\orbr{\begin{cases}x-\frac{1}{16}=\frac{25}{64}\\x-\frac{1}{16}=-\frac{25}{64}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{29}{64}\\x=-\frac{21}{64}\end{cases}}\)
f) \(\left(x-\frac{1}{4}\right)^2+\frac{17}{64}=\frac{21}{32}\)
=> \(\left(x-\frac{1}{4}\right)^2=\frac{25}{64}\)
=> \(\left(x-\frac{1}{4}\right)^2=\left(\frac{5}{8}\right)^2\)
=> \(\orbr{\begin{cases}x-\frac{1}{4}=\frac{5}{8}\\x-\frac{1}{4}=-\frac{5}{8}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{7}{8}\\x=-\frac{3}{8}\end{cases}}\)
Bài 1:
a) Ta có: (x2 - 36)(x2 -25)= 0
\(\Leftrightarrow\)(x2 - 62)(x2 - 52)= 0
\(\Leftrightarrow\)(x - 6)(x + 6)(x - 5)(x + 5)= 0
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-6=0\\x+6=0\end{cases}}\)
\(\orbr{\begin{cases}x-5=0\\x+5=0\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)
\(\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
b) \(CMTT\)câu a
Ta có:\(\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
\(\orbr{\begin{cases}x=8\\x=-8\end{cases}}\)
a) Ta có: x 2 = 2 2 nên x = 2.
b) Ta có: x 2 = 5 2 nên x = 5.
c) Ta có: 3 x 5 = 3 nên x 5 = 1 . Do đó x = 1.
d) Ta có: 6 x 3 = 48 nên x 3 = 8 . Do đó x = 2.
e) Ta có: x - 1 2 = 2 2 nên x - 1 = 2 . Do đó x = 3.
f) Ta có: x + 1 2 = 5 2 nên x +1 = 5. Do đó x = 4.
g) Ta có: x - 1 3 = 3 3 nên x - 1 = 3 . Do đó x = 4.
h) Ta có: x + 1 3 = 4 3 nên x +1 = 4. Do đó x = 3
a) (80.x - 801) . 25 = 0
80.x - 801 = 0 : 25
80.x - 801 = 0
80.x = 801
x = 801 : 80
x = 801/80
b) (x.1 - 10).64 = 64
x.1 - 10 = 64 : 64
x - 10 = 1
x = 1 + 10
x = 11
a) (80.x - 801) . 25 = 0
80.x - 801 = 0 : 25
80.x - 801 = 0
80.x = 801
x = 801 : 80
x = 801/80