Question

[lucy heartfilia]

Tìm x

a ) \(15-3\cdot x=6\) b)\(\dfrac{2}{3}-\dfrac{4}{3}\cdot x=\dfrac{1}{2}\) c) \(3^{19}\cdot\left(x-12\right)=4\cdot3^{20}\) d) \(3\cdot\left(x-4\right)=2^2\cdot3^3\)

Answer 1

[Hà Ngân]

a) 15 - 3x = 6

=> 3x = 15 - 6

=> 3x = 9

=> x = 9 : 3 = 3

b) \(\dfrac{2}{3}-\dfrac{4}{3}x=\dfrac{1}{2}\Rightarrow\dfrac{4}{3}x=\dfrac{2}{3}-\dfrac{1}{2}\Rightarrow\dfrac{4}{3}x=\dfrac{1}{6}\Rightarrow x=\dfrac{1}{6}:\dfrac{4}{3}\Rightarrow x=\dfrac{3}{24}=\dfrac{1}{8}\)c) 3¹⁹.(x - 12 ) = 4 . 3²⁰

^{=> x - 12 = 4 . 3}

^{=> x - 12 = 12}

^{=> x = 12 + 12 = 24}

^{d) 3.(x - 4) = 2^2 . 3^3}

^{=> x - 4 = 2^2 . 3^2}

^{=> x - 4 = 36}

^{=> x = 36 + 4 = 40}

Answer 2

[Mashiro Shiina]

a)\(15-3x=6\Rightarrow3x=9\Rightarrow x=3\)

b) \(\dfrac{2}{3}-\dfrac{4}{3}x=\dfrac{1}{2}\Rightarrow\dfrac{4}{3}x=\dfrac{1}{6}\Rightarrow x=\dfrac{1}{8}\)

c) \(3^{19}.\left(x-12\right)=4.3^{20}\Rightarrow x-12=12\Rightarrow x=24\)

d)\(3\left(x-4\right)=2^2.3^3\Rightarrow3x-12=108\Rightarrow3x=120\Rightarrow x=40\)