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\(3x\left(12x-4\right)-9x\left(4x-3\right)=30\)
=>\(36x^2-12x-36x^2+17x=30\)
=>\(17x-12x=30\)
=>\(5x=30\)
=>x=30:5
=>x=6
\(3.\left(12x-4\right)-9.\left(4x-3\right)=30\)
\(\Rightarrow36x-12-36x+27=30\)
\(\Rightarrow36x-36x=30+12-27\)
\(\Rightarrow x.\left(36-36\right)=15\)
\(\Rightarrow x.0=15\)
\(\Rightarrow x=15:0\) \(???\)
ĐỀ bài sai rồi
3x-21/3+4x-32/2 = 5x-37/4 +9x-33/6
7x+(-21/3-32/2) = 14x+(-37/4 - 33/6 )
7x+(-42/6-96/6) = 14x+ (-111/12 - 66/12)
7x+(-138/6) =14x + (-177/12)
7x - 14x =138/6 +(-177/12)
-7x = 276/12+ (-177/12)
-7x = 99/12
-x = 23/28
x = -23/28
`@` `\text {Ans}`
`\downarrow`
`3x(x+3)`
`= 3x*x + 3x*3`
`= 3x^2 + 9x`
`=> 3x(x+3) = 3x^2 + 9x.`
F(x)=62+5x+8+3x-3x2+3x3
=(36+8)+(5x+3x)-3x2+3x3
=3x3-3x2+8x+44
G(x)=12x2-6-9x2+3x3
=3x3+(12x2-9x2)-6
=3x3+3x2-6
F(x)+G(x)=3x3-3x2+8x+44+3x3+3x2-6
=(3x3+3x3)+(-3x2+3x2)+8x+(44-6)
=6x3+8x+38
\(F\left(x\right)=G\left(x\right)\\ \Rightarrow6^2-5x+8+3x-3x^2+3x^3=12x^2-6-9x^2+3x^3\\ \Leftrightarrow-3x^2-2x+44=3x^2-6\\ \Leftrightarrow6x^2+2x-50=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1+\sqrt{301}}{6}\\x=\dfrac{-1-\sqrt{301}}{6}\end{matrix}\right.\)
\(9^x:3^x=3\)
\(\left(3^2\right)^x:3^x=3\)
rút gọn x
\(\Rightarrow3^2:3=3\)
\(\Rightarrow9:3=3;3.3=9\)
\(\Rightarrow x=1\)
x =1
3x( 1+ 27) = 756
3x = 27
x = 3