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\(450:\left(x-19\right)=50\\ \Leftrightarrow x-19=5\\ \Leftrightarrow x=24\)
\(2\left(x-52\right)=2.23+20\\ \Leftrightarrow2\left(x-52\right)=66\\ \Leftrightarrow x-52=33\\ \Leftrightarrow x=85\)
\(10-\left(x-3\right):2=72-100\\ \Leftrightarrow10-\left(x-3\right):2=-28\\ \Leftrightarrow10-\left(x-3\right)=-56\\ \Leftrightarrow x-3=66\\ \Leftrightarrow x=69\)
1.x-19=450:50
x-19=9
x =9+19
x =28
2. 2(x-51)=46+20
2(x-51)=66
x-51=66:2
x-51=33
x =33+51
x =84
A = \(\dfrac{3^{100}.\left(-2\right)+3^{101}}{\left(-3\right)^{101}-3^{100}}\)
A = \(\dfrac{3^{100}.\left(-2\right)+3^{100}.3}{\left(-3\right)^{100}.\left(-3\right)-3^{100}}\)
A = \(\dfrac{3^{100}.\left(-2+3\right)}{3^{100}.\left(-3\right)-3^{100}}\)
A = \(\dfrac{3^{100}.1}{3^{100}.\left(-3-1\right)}\)
A = \(\dfrac{3^{100}}{3^{100}}\) . \(\dfrac{1}{-4}\)
A = - \(\dfrac{1}{4}\)
\(\dfrac{x-6}{50}+\dfrac{x-6}{51}=\dfrac{x-6}{52}+\dfrac{x-6}{53}\)
\(\Rightarrow\dfrac{x-6}{51}+\dfrac{x-6}{50}-\dfrac{x-6}{52}-\dfrac{x-6}{53}=0\)
\(\Rightarrow\left(x-6\right)\left(\dfrac{1}{50}+\dfrac{1}{51}-\dfrac{1}{52}-\dfrac{1}{53}\right)=0\)
\(\Rightarrow x-6=0\) \(\Rightarrow x=6\)
Vậy ...
x-6/50+x-6/51=x-6/52+x-6/53
x+x-x-x=6/50+6/51-6/52-6/53
0x=6/50+6/51-6/52-6/53(vô ly)
=>ko tồn tại giá trị x
\(\left(\frac{24}{5}+x+50\right):\frac{2}{3}\)\(=-51\)
\(\left(\frac{24}{5}+x+50\right)\)\(=-51.\frac{2}{3}\)
\(\left(\frac{24}{5}+x+50\right)\)\(=-34\)
\(\frac{24}{5}\)\(+x\)\(=-34-50\)
\(\frac{24}{5}\)\(+x\)\(=-84\)
\(x=-84-\frac{24}{5}\)
\(x=-88,8\)
\(x_1+x_2+x_3+........+x_{49}+x_{50}+x_{51}=0\)
\(\Rightarrow\left(x_1+x_2\right)+\left(x_3+x_4\right)+...........+\left(x_{49}+x_{50}\right)+x_{51}=0\)
Theo bài ra ta có: \(1+1+1+.......+1+x_{51}=0\) \(\Rightarrow1\times25+x_{51}=0\) \(\Rightarrow x_{51}=-25\)
mà \(x_{50}+x_{51}=0\Rightarrow x_{50}+\left(-25\right)=1\Rightarrow x_{50}=26\)
Bài toán sai
bài toán đúng là x+(x+1)+(x+2)+(x+3)+...+19+20=20
24 hay là 2( số nhân với mẫu rồi cộng tử) rùi đến 4 phần 5