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\(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\)

\(\left(\dfrac{2}{5}-\dfrac{1}{5}\right)x=\dfrac{3}{4}\)

\(\dfrac{1}{5}x=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)

8 tháng 2

\(\dfrac{2}{5}.x-\dfrac{1}{5}.x=\dfrac{3}{4}\) 

\(x.\left(\dfrac{2}{5}-\dfrac{1}{5}\right)=\dfrac{3}{4}\)

     \(x.\dfrac{1}{5}\)         = \(\dfrac{3}{4}\) 

      \(x\)            = \(\dfrac{3}{4}:\dfrac{1}{5}\) 

    \(x\)               \(\dfrac{15}{4}\)

12 tháng 2 2023

\(\dfrac{4-x}{-5}=\dfrac{-5}{4-x}\)
\(\Leftrightarrow\left(4-x\right)\left(4-x\right)=-5\times-5\)
\(\Rightarrow\left(4-x\right)^2=25\)
\(\Rightarrow\left[{}\begin{matrix}4-x=5\\4-x=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=9\end{matrix}\right.\)

12 tháng 2 2023

\(\dfrac{4-x}{-5}=\dfrac{-5}{4-x}\)

\(\Rightarrow\left(4-x\right).\left(4-x\right)=\left(-5\right).\left(-5\right)\)

\(\Rightarrow\left(4-x\right)^2=25\)

\(\Rightarrow\left(4-x\right)^2=5^2\)

\(\Rightarrow4-x=\pm5\)

\(\Rightarrow\left[{}\begin{matrix}4-x=5\\4-x=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=4-5\\x=4-\left(-5\right)\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=9\end{matrix}\right.\)

`@` `\text {Ans}`

`\downarrow`

`2+(x+3)=7`

`\Rightarrow x+3=7-2`

`\Rightarrow x+3=5`

`\Rightarrow x=5-3`

`\Rightarrow x=2`

`5+(3+x)=10`

`\Rightarrow 3+x=10-5`

`\Rightarrow 3+x=5`

`\Rightarrow x=5-3`

`\Rightarrow x=2`

`(4+x)+1=7`

`\Rightarrow 4+x=7-1`

`\Rightarrow 4+x=6`

`\Rightarrow x=6-4`

`\Rightarrow x=2`

`(x+5)+3=9`

`\Rightarrow x+5=9-3`

`\Rightarrow x+5=6`

`\Rightarrow x=6-5`

`\Rightarrow x=1`

`(x-1)-4=7`

`\Rightarrow x-1=7+4`

`\Rightarrow x-1=11`

`\Rightarrow x=11+1`

`\Rightarrow x=12`

`4-(6-x)=1`

`\Rightarrow 6-x=4-1`

`\Rightarrow 6-x=3`

`\Rightarrow x=6-3`

`\Rightarrow x=3`

19 tháng 6 2023

\(2+\left(x+3\right)=7\)

\(\Rightarrow2+x+3=7\)

\(\Rightarrow x+5=7\)

\(\Rightarrow x=2\)

\(5+\left(3+x\right)=10\)

\(\Rightarrow5+3+x=10\)

\(\Rightarrow x+8=10\)

\(\Rightarrow x=2\)

\(\left(4+x\right)+1=7\)

\(\Rightarrow4+x+1=7\)

\(\Rightarrow x+5=7\)

\(\Rightarrow x=2\)

\(\left(x+5\right)+3=9\)

\(=x+5+3=9\)

\(\Rightarrow x+8=9\)

\(\Rightarrow x=1\)

\(\left(x-1\right)-4=7\)

\(\Rightarrow x-1-4=7\)

\(\Rightarrow x-5=7\)

\(\Rightarrow x=12\)

\(4-\left(6-x\right)=1\)

\(\Rightarrow4-6-x=1\)

\(\Rightarrow-2-x=1\)

\(\Rightarrow x=-3\)

19 tháng 6 2023

\(\left(x+2\right)-2=0\)

\(\Rightarrow x+2-2=0\)

\(\Rightarrow x=0\)

\(\left(x+3\right)+1=7\)

\(\Rightarrow x+3+1=7\)

\(\Rightarrow x+4=7\)

\(\Rightarrow x=3\)

\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)

\(\Rightarrow3x=12\)

\(\Rightarrow x=4\)

\(\left(5x+4\right)-1=13\)

\(\Rightarrow5x+4-1=13\)

\(\Rightarrow5x+3=13\)

\(\Rightarrow5x=10\)

\(\Rightarrow x=2\)

\(\left(4x-8\right)-3=5\)

\(\Rightarrow4x-8-3=5\)

\(\Rightarrow4x-11=5\)

\(\Rightarrow4x=16\)

\(\Rightarrow x=4\)

\(8-\left(2x+4\right)=2\)

\(\Rightarrow8-2x-4=2\)

\(\Rightarrow4-2x=2\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

\(7+\left(5x+2\right)=14\)

\(\Rightarrow7+5x+2=14\)

\(\Rightarrow9+5x=14\)

\(\Rightarrow5x=5\)

\(\Rightarrow x=1\)

\(5-\left(3x-11\right)=1\)

\(\Rightarrow5-3x+11=1\)

\(\Rightarrow16-3x=1\)

\(\Rightarrow3x=15\)

\(\Rightarrow x=5\)

17 tháng 6 2021

Các anh các cj giúp em nhé 
Em cảm ơn trước

Giải:

a) \(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)\) 

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}\) 

\(=\dfrac{1.2.3.4}{2.3.4.5}\) 

\(=\dfrac{1}{5}\) 

b) \(\left(1-\dfrac{3}{4}\right).\left(1-\dfrac{3}{7}\right).\left(1-\dfrac{3}{10}\right).\left(1-\dfrac{3}{13}\right).....\left(1-\dfrac{3}{97}\right).\left(1-\dfrac{3}{100}\right)\) 

\(=\dfrac{1}{4}.\dfrac{4}{7}.\dfrac{7}{10}.\dfrac{10}{13}.....\dfrac{94}{97}.\dfrac{97}{100}\) 

\(=\dfrac{1.4.7.10.....94.97}{4.7.10.13.....97.100}\) 

\(=\dfrac{1}{100}\) 

Chúc bạn học tốt!

30 tháng 11 2023

1) -x - 3 = 7

-x = 7 + 3

-x = 10

x = -10

2) x + 5 = -10

x = -10 - 5

x = -15

3) 2x - 7 = 713

2x = 713 + 7

2x = 720

x = 720 : 2

x = 360

4) -129 - (35 - x) = 55

35 - x = -129 - 55

35 - x = -184

x = 35 - (-184)

x = 219

5) 103 - x = 16 - (13 - 8)

103 - x = 16 - 5

103 - x = 11

x = 103 - 11

x = 192

3 tháng 9 2020

a) \(\left(x-5\right)-\frac{1}{3}=\frac{2}{5}\)

\(\Rightarrow\left(x-5\right)=\frac{2}{5}+\frac{1}{3}\)

\(\Rightarrow\left(x-5\right)=\frac{11}{15}\)

\(\Rightarrow x-5=\frac{11}{15}\)

\(\Rightarrow x=\frac{11}{15}+5\)

\(\Rightarrow x=\frac{86}{15}\)

b) \(\frac{2}{3}\cdot x-\frac{3}{2}\cdot x=\frac{5}{12}\)

\(\Rightarrow x\cdot\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\)

\(\Rightarrow x\cdot\left(-\frac{5}{6}\right)=\frac{5}{12}\)

\(\Rightarrow x=\frac{5}{12}:\left(-\frac{5}{6}\right)\)

\(\Rightarrow x=-\frac{1}{2}\)

c) \(-\frac{2}{3}\cdot x+\frac{1}{5}=\frac{3}{10}\)

\(\Rightarrow-\frac{2}{3}\cdot x=\frac{3}{10}-\frac{1}{5}\)

\(\Rightarrow-\frac{2}{3}\cdot x=\frac{1}{10}\)

\(\Rightarrow x=\frac{1}{10}:\left(-\frac{2}{3}\right)\)

\(\Rightarrow x=-\frac{3}{20}\)

d) \(4-\left(\frac{1}{2}\cdot x+\frac{3}{4}\right)=-\frac{1}{5}\)

\(\Rightarrow\left(\frac{1}{2}\cdot x+\frac{3}{4}\right)=4-\left(-\frac{1}{5}\right)\)

\(\Rightarrow\)\(\frac{1}{2}\cdot x+\frac{3}{4}=\frac{21}{5}\)

\(\Rightarrow\)\(\frac{1}{2}\cdot x=\frac{21}{5}-\frac{3}{4}\)

\(\Rightarrow\)\(\frac{1}{2}\cdot x=\frac{69}{20}\)

\(\Rightarrow\)\(x=\frac{69}{20}:\frac{1}{2}\)

\(\Rightarrow\)\(x=\frac{69}{10}\)

20 tháng 1 2016

đề bài cho biết x là số nguyên à ?

 

20 tháng 1 2016

1,=>x^2+2 và x+3 là 2 số nguyên cùng dấu (1)

Với x thuộc Z thì x^2 luôn >hoặc =0 .

2>0=>x^2+2>0 (2)

từ 2 kết luận(1) và (2) =>x^2+2 và x+3 >0

x^2+2>0=>x^2>-2=>x^2 thuộc {0;1;4;9...}=>x thuộc {0;1;2;3...} 

x+3>0=>x>-3

vậy x thuộc N

 

29 tháng 7 2023

\(a,2^x+2^{x+3}=144\\ 2^x.\left(1+2^3\right)=144\\ 2^x.9=144\\ 2^x=144:9\\ 2^x=16=2^4\\ vậy:x=4\)

29 tháng 7 2023

\(b,\left(x-5\right)^{2022}=\left(x-5\right)^{2021}\\ Vì:\left[{}\begin{matrix}0^{2022}=0^{2021}\\1^{2022}=1^{2021}\end{matrix}\right.\\ Vậy:\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)