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câu 1 = 0
câu 2 : X=\(\frac{16}{105}\)
X =\(\frac{180}{77}\)
X = 63
(18\(\dfrac{1}{2}+5\dfrac{3}{8}-7\dfrac{5}{24}\)) - 16\(\dfrac{2}{3}\)
=( \(\dfrac{37}{2}\) + \(\dfrac{43}{8}\) - \(\dfrac{171}{24}\) ) - \(\dfrac{50}{3}\)
= \(\dfrac{50}{3}\) - \(\dfrac{50}{3}\)
=0
24/y=3/5*8/3
24/y=8/5
24:y=8/5
y=24;8/5
y=15
b,42/25:y/5=6/7
y/5=42/25:6/7
y/5=49/25
y:5=49/25
y=49/25*5
y=49/5=9,8
\(\frac{24}{y}:\frac{8}{3}=\frac{3}{5}\)
\(\Rightarrow\frac{24}{y}=\frac{3}{5}\times\frac{8}{3}\)
\(\Rightarrow\frac{24}{y}=\frac{8}{5}\)
\(\Rightarrow y=\frac{8}{5}\times24=\frac{192}{5}\)
b , \(\frac{42}{25}:\frac{y}{5}=\frac{6}{7}\)
\(\Rightarrow\frac{y}{5}=\frac{6}{7}\times\frac{42}{25}=\frac{36}{25}\)
\(\Rightarrow y=\frac{36}{25}\times5=\frac{36}{5}\)
a) \(\frac{24}{x}\div\frac{8}{3}=\frac{3}{5}\)
\(\frac{24}{x}\cdot\frac{3}{8}=\frac{3}{5}\)
\(\frac{24}{x}=\frac{3}{5}\div\frac{3}{8}\)
\(\frac{24}{x}=\frac{24}{15}\)
Vậy x = 15
b) Tương tự