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a) 220 = 22 . 5 . 11
240 = 24 . 3 . 5
300 = 22 . 3 . 52
=> ƯCLN(220;240;300) = 22 . 5 . 3 = 60
=> BCNN(220;240;300) = 24 . 5 . 11 . 3 = 2640
b) 40 = 23 . 5
75 = 3 . 52
105 = 3 . 5 .7
=> ƯCLN(40;75;105) = 5 . 3 = 15
=> BCNN(40;75;105) = 23 . 52 . 3 . 7 = 4200
c) 18 = 2 . 32
36 = 22 . 32
72 = 23 . 32
=> ƯCLN(18;36;72) = 2 . 32 = 18
=> BCNN(18;36;72) = 23 . 32 = 72
a) Ta có: 18=2⋅3^21
24=2^3⋅3
30=2⋅3⋅5
Do đó: ƯCLN(18;24;30)=2⋅3=6 và BCNN(18;24;30)=2^3⋅3^2⋅5=360
b) Ta có: 40=2^3⋅5
75=3⋅5^2
105=3⋅5⋅7105=3⋅5⋅7
Do đó: ƯCLN(40;75;105)=5^1=5 và BCNN(40;75;105)=2^3⋅3⋅5^2⋅7=4200
c) Ta có: 18=2⋅3^2
36=2^2⋅3^2
72=2^3⋅3^2
Do đó: ƯCLN(18;36;72)=2.3^2=2⋅9=18 và BCNN(18;36;72)=2^3⋅3^2=72
a, 220 = 22 . 5 . 11
240 = 24 . 3 . 5
300 = 22 . 3 . 52
ƯCLN(220;240;300) = 22 . 5 = 20
BCNN(220;240;300) = 24 . 3 . 52 . 11 = 13200
b, 40 = 23 . 5
75 = 3 . 52
106 = 2 . 53
ƯCLN(40;75;106) = 1
BCNN(40;75;106) = 23 . 3 . 52 . 53 = 31800
c, 18 = 2 . 32
36 = 22 . 32
72 = 23 . 32
ƯCLN(18;36;72) = 2 . 32 = 18
BCNN(18;36;72) = 23 . 32 = 72
a)Ta có:220=22.5.11
240=24.3.5
300=22.3.52
\(\Rightarrow\)\(ƯCLN\)(220;240;300)=22.5=20
\(BCNN\left(220;240;300\right)=2^4.3.5^2.11=13200\)
b)Ta có:40=23.5
75=3.52
106=2.53
\(\RightarrowƯCLN\)(40;75;106)=1
\(BCNN\left(40;75;106\right)=2^3.3.5^2.53=31800\)
c)Ta có:18=2.32
36=22.32
72=23.32
\(\RightarrowƯCLN\)(18;36;72)=2.32=\(18\)
\(BCNN\left(18;36;72\right)=2^3.3^2=72\)
a) Ta có: 21 = 3.7; 98 = 2.72
=> ƯCLN(21, 98) = 7 ; BCNN(21, 98) = 2.3.72 = 294
b) Ta có: 36 = 22.32, 54 = 2.33
ƯCLN(36, 54) = 2.32 = 18; BCNN(36, 54) = 22.33 = 108.
Phan h moi so ra TSNT roi nhan len la ra!!
a,ta co:
\(220=2^2.5.11\)
\(240=2^4.3.5\)
\(300=2.3.5^2\)
\(\Rightarrow UCLN\left(220,240,300\right)=2.3.5=30\)
\(BCNN\left(220,240,300\right)=2^4.3.5^2=1200\)
Cac cau con lai tuong tu nha!!
HTDT
a ) Ta có : \(220=2^2\cdot5\cdot11\)
\(240=2^4\cdot3\cdot5\)
\(300=2^2\cdot3\cdot5^2\)
\(\Rightarrow\:ƯCLN\)\(\left(220;240;300\right)=2^2\cdot5=20\)
\(\Rightarrow BCNN\left(220;240;300\right)=2^4\cdot3\cdot5^2\cdot11=13200\)
b) Ta có : \(40=2^3\cdot5\)
\(75=3\cdot5^2\)
\(105=3\cdot5\cdot7\)
\(\RightarrowƯCLN\left(40;75;105\right)=5\)
\(\Rightarrow BCNN\left(40;75;105\right)=2^3\cdot3\cdot5^2\cdot7=4200\)
c)
\(C1:\) Ta có : \(18=2\cdot3^2\)
\(36=2^2\cdot3^2\)
\(72=2^3\cdot3^2\)
\(\Rightarrow\:\)\(ƯCLN\)\(\left(18;36;72\right)=2\cdot3^2\)\(=18\)
\(\Rightarrow BCNN\left(18;36;72\right)=2^3\cdot3^2=72\)
\(C2:\) Vì \(36⋮18;72⋮18;18⋮18\) nên \(\:ƯCLN\)\(\left(18;36;72\right)=18\)
Vì \(72\) chia hết cho \(18;36;72\) nên \(BCNN\left(18;36;72\right)=72\)
a,UCLN(220,240.300)=20;BCNN(220,240,300)=13200
B,UCLN(40,75,106)=1;B,BCNN(40,75,106)=31800
C,UCLN(18,36,72)=18;C,BCNN(18,36,72)=72
a)UCLN(220,240,300)=20; BCNN(220,2420,300)=13200
b)UCLN(40,75,106)=0; BCNN(40,75,106)=7950
c)UCLN(18,36,72)=18; BCNN(18,36,72)=72