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320 = 26 . 5
180 = 22 . 32 . 5
=> \(ƯCLN\left(320;180\right)=2^2.5=20\)
\(\Rightarrow BCNN\left(320;180\right)=2^6.3^2.5=2880\)
\(\RightarrowƯC\left(320;180\right)=\left\{2;5\right\}\)
\(\Rightarrow BC\left(320;180\right)=\left\{0;2880;5760;8640;...\right\}\)
320 = 26. 5 320 = 26. 5
180 = 22. 32. 5 180 = 22. 32. 5
ƯCLN(320;180) = 22. 5 = 20 BCNN(320;180) = 26. 32. 5 = 2560
ƯC(320;180) = ( 1;2;4;5;10;20 ) BC(320;180) =( 0;2560;5120;... )
\(a.120=2^3.3.5\)
\(320=2^6.5\)
\(ƯC\left(120;320\right)=\left\{40;80;120;160;200;...\right\}\)
\(ƯCLN\left(120;320\right)=2^3.5=40\)
\(b.455=5.7.13\)
\(950=2.5^2.19\)
\(ƯC\left(455;950\right)=\left\{5;10;15;20;25;...\right\}\)
\(ƯCLN\left(455;950\right)=5\)
\(c.126=2.3^2.7\)
\(108=2^2.3^3\)
\(306=2.3^2.17\)
\(ƯC\left(126;108;306\right)=\left\{18;36;54;72;...\right\}\)
\(ƯCLN\left(126;108;306\right)=2.3^2=18\)
a.120=23.3.5�.120=23.3.5
320=26.5320=26.5
ƯC(120;320)={40;80;120;160;200;...}Ư�(120;320)={40;80;120;160;200;...}
ƯCLN(120;320)=23.5=40Ư���(120;320)=23.5=40
b.455=5.7.13�.455=5.7.13
950=2.52.19950=2.52.19
ƯC(455;950)={5;10;15;20;25;...}Ư�(455;950)={5;10;15;20;25;...}
ƯCLN(455;950)=5Ư���(455;950)=5
c.126=2.32.7�.126=2.32.7
108=22.33108=22.33
306=2.32.17306=2.32.17
ƯC(126;108;306)={18;36;54;72;...}Ư�(126;108;306)={18;36;54;72;...}
ƯCLN(126;108;306)=2.32=18
\(36=2^2\cdot3^2\\ 120=2^3\cdot3\cdot5\\ ƯCLN\left(36,120\right)=2^2\cdot3=12\\ ƯC\left(36,120\right)=Ư\left(12\right)=\left\{...\right\}\)
Ta có: 36= 2^2. 3^2
120= 2^3. 3.5
=> ƯCLN( 36; 120)- 2^2. 3= 12
=> ƯC(36;120) = Ư(12) = { 1; 2; 3; 4; 6; 12}
TL :
\(40=2^3.5.\)
\(24=2^2.3.2\)
UCLN (40;24) = \(2^3=8\)
BC (8) = \(\left\{1;8;16;24;32;40.....\right\}\)
b) \(48=2^4.3\)
\(120=2^3.5\)
UCLN (48;120 ) = \(2^2.3=12\)
a) Ta có:
144=24.3
420=22.3.5.7
ƯCLN(...)=22.3=12
ƯC(...)=Ư(12)={1;2;3;4;6;12}
Các bài sau bn cũng lm thế này nhé:)))
a) 54=2.33; 48=23.6 b)45=5.32 ; 60=22.3.5 c)48=24.3 ; 72=22.32 ;90=2.32.5
TSNT chung:2 TSNT chung:3;5 TSNT chung:2;3
ƯCLN(54;48)=2=2 ƯCLN(45;60)=3.5=15 ƯCLN(48;72;90)=2.3=6
ƯC(54;48)=Ư(2)={1;2} ƯC(45;60)=Ư(15)={1;3;5;15} ƯC(48;72;60)=Ư(6)={1;2;3;6}
a) ƯCLN (12 ; 18 ; 54) = 6 => ƯC(12 ; 18 ; 54) = Ư (6) = {1 ; 2 ; 3 ; 6 ; -1 ; -2 ; -3 ; -6 }
b) ƯCLN (144 ; 120 ; 170 ) = 2 => ƯC ( 140 ; 120 ; 144 ) = {1 ; 2 ; -1 ; -2}
c) ƯCLN (150 ; 350 ) = 50 => ƯC ( 150 ; 350 ) = {1 ; 2 ; 5 ; 10 ; 25 ; 50 ; -1 ; -2 ; -5 ; -10 ; -25 ; -50}
d) ƯCLN ( 1800 ; 190 ) = 10 => ƯC ( 1800 ; 190) = {1 ; 2 ; 5 ; 10 ; -1 ;-2 ; -5 ; -10}
ƯC(12;18 và 54) = {1;2;3;6}
ƯC(144;120 và 170) = {1;2}
ƯC (150 và 350) = {1;2;5;10}
ƯC (120; 320) = {1; 2; 4; 5; 8; 10; 20; 40} ƯCLN (120; 320) = 40 chắc thế:P
=1 ok ok