Question

[phan ngoc hai]

tìm TXĐ   y=1 trên x bình -1

Answer 1

[Nguyễn Linh Chi]

\(y=\frac{1}{x-1}\)

DKXĐ: x - 1 \(\ne\)0 

<=> x \(\ne\)1

=> TXĐ: \(ℝ\backslash\left\{1\right\}\)hoặc \(\left(-\infty;1\right)\)U\(\left(1;+\infty\right)\)hoặc \(\left(-\infty;+\infty\right)\backslash\left\{1\right\}\)