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a) -32 -4.(x-5) = 0
<=>4.(x-5)=-32
<=>x-5=(-32):4
<=>x+5=-8
<=>x=-8+5
<=>x=-3
Vậy x=-3
b) 13.(x-5)=-169
<=>x-5=(-169):13
<=>x-5=-13
<=>x=-13+5
<=>x=-8
vậy x=-8
c) (-2).x+5 = (-3).(-3)+8
<=>(-2).x+5=17
<=>(-2).x=17-5
<=>(-2).x=12
<=>x=12:(-2)
<=>x=-6
Vậy x=-6
d) (-8).x = (-10).(-2)-4
<=>(-8).x=16
<=>x=16:(-8)
<=>x=-2
vậy x=-2
e) (-9).x+3 = (-2).(-7)+16
<=>(-9).x+3=30
<=>(-9).x=30-3
<=>(-9).x=27
<=>x=27:(-9)
<=>x=-3
Vậy x=-3
a) x - 1/2 = 3/5
x = 3/5 + 1/2
x = 11/10
b) x - 1/2 = -2/3
x = -2/3 + 1/2
x = -1/6
c) 2/5 - x = 0,25
x = 2/5 - 0,25
x = 2/5 - 1/4
x = 3/20
a) \(\left(3-x\right)\left(5x+10\right)=0\)
\(\left(3-x\right).5.\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3-x=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)
vậy...
b) \(\left|5x+2\right|-4x=7\)
\(\left|5x+2\right|=7+4x\)
\(\Rightarrow\orbr{\begin{cases}5x+2=7+4x\\5x+2=-7-4x\end{cases}}\Rightarrow\orbr{\begin{cases}5x-4x=7-2\\5x+4x=-7-2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\9x=-9\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)
vậy....
k nha
a, \(\left(3-x\right)\left(5x+10\right)=0\)
\(\Rightarrow3-x=0\) hoặc \(5x+10=0\)
\(\Rightarrow x=3\) hoặc \(x=-2\)
a) \(\left(2x-1\right)^2-25=0\)
\(\left(2x-1\right)^2=0+25=25\)
\(\left(2x-1\right)^2=5^2=\left(-5\right)^2\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x-1=5\\2x-1=-5\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}2x=6\\2x=-4\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-2\end{array}\right.\)
b) \(8x^3-50x=0\)
\(2x\left(4x^2-25\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x=0\\4x^2-25=0\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=0\\4x^2=25\Rightarrow x^2=\frac{25}{4}\Rightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{5}{2}\end{array}\right.\end{array}\right.\)
a) 2 + 3x = (-15) - 19
\(2+3x=-34\\ 3x=-34-2\\ 3x=-36\\ x=-12\)
b,\(10-2x=32\\ 2x=10-32\\ 2x=-22\\ x=-11\)
c,\(Ix-1I-5=0\)
\(\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
Vậy ...
d,\(\left(5-x\right).\left(2x+8\right)=0\)
\(\orbr{\begin{cases}5-x=0\\2x+8=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-4\end{cases}}\)
Vậy...
e, x2 - 4x = 0
x.x - 4x = 0
x. ( 1- 4 ) = 0
x. (-3) = 0
x = 0
f, 3x - 15 = 25 - 5x
3x + 5x = 25 + 15
8x = 40
x= 5
g,( x2 + 2 ) . ( 4x - 16 ) = 0
\(\orbr{\begin{cases}x^2+2=0\\4x-16=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\sqrt{2}\\x=-4\end{cases}}\)
Vậy ...
Học tốt
a) 2 + 3x = (-15) - 19
2+3x=-34
3x=-34-2
3x=-36
x=-36:3
x=-12
b) 10 - 2x = 32
2x=10-32
2x=-22
x=-11
c) / x - 1 / - 5 = 0
|x-1|=5
* x-1=5 * x-1=-5
x=5+1 x=-5+1
x=6 x=-4
d) ( 5 - x ) . ( 2x + 8 ) = 0
* 5-x=0 * 2x+8=0
x=5-0 2x=-8
x=5 x=-8:2=-4
e) x2 - 4x = 0
x(x-4)=0
*x=0
*x-4=0
x=0+4
x=4
f) 3x - 15 = 25 - 5x
3x+5x=25+15
8x=40
x=40:8
x=5
g) ( x2 + 2 ) . ( 4x - 16 ) = 0
* x2+2=0 *4x-16=0
x2=-2 4x=16
Vô lí vì -2 ko chuyển sang mũ 2 đc x=16:4=4
a) (-10).x+30=10
<=>(-10).x=10-30
<=>(-10).x=-20
<=>x=(-20):(-10)
<=>x=2
Vậy x=2
b) x.(2x + 2) = 0
<=>\(\hept{\begin{cases}x=0\\2x+2=0\end{cases}}\)<=>\(\hept{\begin{cases}x=0\\2x=-2\end{cases}}\)<=>\(\hept{\begin{cases}x=0\\x=-1\end{cases}}\)
Vậy x=0 Hoặc x=-1