Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có: 3x+2+4.3x+1=7.36
=> 3x + 1.(3 + 4) = 7.36
=> 3x + 1 . 7 = 7.36
=> 3x + 1 = 36
=> x + 1 = 6
=> x = 5
1:
\(\Leftrightarrow4\cdot3^x\cdot\dfrac{1}{9}+2\cdot3^x\cdot3=4\cdot3^4+2\cdot3^7\)
\(\Leftrightarrow3^x\cdot\left(\dfrac{4}{9}+6\right)=3^4\cdot\left(4+2\cdot3^3\right)\)
\(\Leftrightarrow3^x=729\)
hay x=6
2: \(\Leftrightarrow3^x\cdot4\cdot\dfrac{1}{3}+3^x\cdot2\cdot9=4\cdot3^6+2\cdot3^9\)
\(\Leftrightarrow3^x\cdot\dfrac{58}{3}=42282\)
=>3x=2187
hay x=7
1. ta có
3x+2+4.3x+1+3x−1=66
3x.3+3x.3.4+3x:3=66
3x.3+3x.12+3x.1/3=66
3x.(3+12+1/3)=66
3x.64/3=66
3x=66:64/3
3x=2187
3x=37
=> x=7
\(7\cdot3^{x-1}-3^{x+2}=-540\)
\(\Leftrightarrow3^x\left[7\cdot\left(-3\right)-3^2\right]=-540\)
\(\Leftrightarrow3^x\cdot\left(-30\right)=-540\)
\(\Leftrightarrow3^x=18\)
Ta có : \(7.3^{x-1}-3^{x+2}=-540\)
\(\Leftrightarrow\left(7-3^3\right).3^{x-1}=-540\)
\(\Leftrightarrow\left(7-27\right).3^{x-1}=-540\)
\(\Leftrightarrow-20.3^{x-1}=-540\)
\(\Leftrightarrow3^{x-1}=\left(-540\right):\left(-20\right)\)
\(\Leftrightarrow3^{x-1}=27\)
\(\Leftrightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)
Vậy \(x=4\)
\(3^{x+2}+4.3^{x+1}=7.3\)
\(\Leftrightarrow3^x\left(3^2+4.3\right)=21\)
\(\Leftrightarrow3^x.21=21\)
\(\Leftrightarrow3^x=1\Leftrightarrow x=0\)
\(3^{x+2}+4.3^{x+1}=7.3\)
\(\Leftrightarrow3^{x+2}+4.3^{x+1}=21\)
\(\Leftrightarrow3^x\left(3^2+4.3\right)=21\)
\(\Leftrightarrow3^x.21=21\Leftrightarrow3^x=1\)
\(\Leftrightarrow x=0\)