Question

[Chuột yêu Gạo]

Tìm số nguyên dương n, biết :

\(\left(\frac{1}{32}\right)^n.16^n=1024^{-1}\)

Answer 1

[Minh Hằng]

(\(\dfrac{1}{32}\))ⁿ . 16ⁿ = 1024^-1

<=> (\(\dfrac{1}{32}\) . 16)ⁿ = \(\dfrac{1}{1024}\)

<=> (\(\dfrac{1}{2}\))ⁿ = \(\dfrac{1}{1024}\)

<=> n=10

Vậy n=10