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a. Ta có : 2,5 < 5,2 => 2,53 < 5,23
b. Ta có : 45 = 1024 ; 54 = 625
Vì 1024 > 625 => 45 > 54
\(a.2.5^3va5.2^3\)
\(2.5^3=2.125=250;5.2^3=5.8=40\)
Vì \(250>40\)
\(\Rightarrow2.5^3>5.2^3\)
\(b.4^5va5^4\)
\(4^5=1024;5^4=625\)
Vì \(1024>625\)
\(\Rightarrow4^5>5^4\)
\(c.2^8va2.5^3\)
\(2^8=256;2.5^3=2.125=250\)
Vì \(256>250\)
\(\Rightarrow2^8>2.5^3\)
2.Tìm x:
\(a.2^n+4.2^n=5.2^5\)
\(2^n\left(1+4\right)=5.32\)
\(2^n.5=160\)
\(2^n=160:5\)
\(2^n=32\)
\(2^n=2^5\)
\(\Rightarrow n=5\)
\(b.3^4.3^n:9=3^7\)
\(3^4.3^n:3^2=3^7\)
\(3^4.3^n=3^7.3^2\)
\(3^4.3^n=3^{7+2}\)
\(3^4.3^n=3^9\)
\(3^n=3^9:3^4\)
\(3^n=3^{9-4}\)
\(3^n=3^5\)
\(\Rightarrow n=5\)
\(c.6.2^n+3.2^n=9.2^n\)
\(2^n\left(6+3\right)=9.2^n\)
\(2^n.9=9.2^n\)
\(\Rightarrow2^n=9:9\)
\(\Rightarrow2^n=1\)
\(\Rightarrow2^n=2^0\)
\(\Rightarrow n=0\)
Chúc bạn học tốt!
a) Ta có: \(4^{2x-6}=1\)
\(\Rightarrow2x-6=1\)
\(\Rightarrow2x=6+1=7\)
\(\Rightarrow x=\frac{7}{2}\)
b) Ta có:\(2^{x-1}=16=2^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)
c) Ta có: \(5^{x+1}=125=5^3\)
\(\Rightarrow x+1=3\)
\(\Rightarrow x=2\)
d) Ta có: \(5^{2x-3}-2.5^2=5^2.3\)
\(\Rightarrow5^{2x-3}=5^2.3+2.5^2\)
\(\Rightarrow5^{2x-3}=5^2.\left(3+2\right)=5^2.5=5^3\)
\(\Rightarrow2x-3=3\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
42x-6 = 1
=> 42x-6 = 40
=> 2x - 6 = 0
=> 2x = 6
=> x = 3
5x+1 = 125
=> 5x+1 = 53
=> x + 1 = 3
=> x = 2
52x-3 - 2.52 = 52.3
=> 52x-3 = 52.3 + 2.52
=> 52x-3 = 52( 3 + 2 )
=> 52x-3 = 52.5
=> 52x-3 = 53
=> 2x - 3 = 3
=> 2x = 6
=> x = 3
a, 52x - 3 - 2.52 = 52.3
=> 52x - 3 - 50 = 75
=> 52x - 3 = 125
=> 52x - 3 = 53
=> 2x - 3 = 3
=> 2x = 0
=> x = 0
vậy_
b, (x + 1) + (x + 2) + ....+ (x + 100) = 5750
=> x + 1 + x + 2 + ... + x + 100 = 5750
=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 5750
=> 100x + 5050 = 5750
=> 100x = 700
=> x = 7
vậy_
a) \(5.\left(x-3\right)=15\)
\(x-3=15:5\)
\(x-3=3\)
\(x=6\)
b)\(10+2.x=4^5:4^3\)
\(10+2.x=16\)
\(2x=16-10\)
\(2x=6\)
\(x=3\)
c) \(5^{x+1}=125\)
\(5^{x+1}=5^3\)
\(x+1=3\)
\(x=2\)
d) \(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=2.5^2+5^2.3\)
\(5^{2x-3}=125\)
\(5^{2x-3}=5^2\)
\(2x-3=2\)
\(2x=6\)
\(x=3\)
Mk nhanh nek bn
2.25.9+{[2.125-25.x-20]:(4.3.5)}=453
450 +{[250-25.x -20]:60 }=453
450 +{[230-25.x] :60 }=453
450 +{23/6-13/30x }=453
23/6-5/12x =453-450
46/12-5/12x =3
(46-5x)/12 =3
46-5x =3.12=36
5x =46-36=10
x=2
Mình viết cách ra cho dễ hiểu đó
a) \(2.5^2.3^2+\left\{\left[2.5^3-\left(5x+4\right).5\right]:\left(2^2.3.5\right)\right\}=453\)
\(2.25.9+\left\{\left[2.125-\left(5x+4\right).5\right]:\left(4.3.5\right)\right\}=453\)
\(50.9+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(450+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(\left[250-\left(5x+4\right).5\right]:60=453-450\)
\(\left[250-\left(5x+4\right).5\right]:60=3\)
\(250-\left(5x+4\right).5=3.60\)
\(250-\left(5x+4\right).5=180\)
\(\left(5x+4\right).5=250-180\)
\(\left(5x+4\right).5=70\)
\(5x+4=70:5\)
\(5x+4=14\)
\(5x=14-4\)
\(5x=10\)
\(x=10:5\)
\(x=2\)
Vậy \(x=2\)
b) \(\left|x-\frac{1}{3}\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{3}=-2\\x-\frac{1}{3}=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\left(-2\right)+\frac{1}{3}\\x=2+\frac{1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{7}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-5}{7};\frac{7}{3}\right\}\)