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\(BCNN\left(9,24,35\right)=2520\\ BCNN\left(18,36,108\right)=108\)
a: ƯCLN(40;24)=8
ƯC(40;24)=Ư(8)={1;2;4;8}
b: UCLN(80;144)=16
UCLN(80;144)={1;2;4;8;16}
c: UCLN(9;18;72)=9
ƯC(9;18;72)={1;3;9}
d: ƯCLN(25;55;75)=5
ƯC(25;55;75)={1;5}
\(a,40=2^3.5\\ 24=2^3.3\\ \Rightarrow UCLN_{\left(24;40\right)}=2^3=8\\ \RightarrowƯC_{\left(40;24\right)}=Ư_{\left(8\right)}=\left\{1;2;4;8\right\}\\ b,80=2^4.5\\ 144=2^4.3^2\\ \Rightarrow UCLN_{\left(80;144\right)}=2^4=16\\ \RightarrowƯC_{\left(80;144\right)}=Ư_{\left(16\right)}=\left\{1;2;4;8;16\right\}\\ c,9=3^2\\ 18=2.3^2\\ 72=3^2.2^3\\ \Rightarrow UCLN_{\left(8;18;72\right)}=3^2=9\\ \RightarrowƯC_{\left(9;18;72\right)}=Ư_{\left(9\right)}=\left\{1;3;9\right\}\\ d,25=5^2\\ 55=5.11\\ 75=5^2.3\\ \Rightarrow UCLN_{\left(25;55;75\right)}=5\\ \RightarrowƯC_{\left(25;55;75\right)}=Ư_{\left(5\right)}=\left\{1;5\right\}\)
a: \(24=2^3\cdot3;40=2^3\cdot5\)
=>\(ƯCLN\left(24;40\right)=2^3=8\)
=>\(ƯC\left(24;40\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
b: \(12=2^2\cdot3;52=2^2\cdot13\)
=>\(ƯCLN\left(12;52\right)=2^2=4\)
=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)
c: \(45=3^2\cdot5;180=2^2\cdot3^2\cdot5\)
=>\(ƯCLN\left(45;180\right)=3^2\cdot5=45\)
=>\(ƯC\left(45;180\right)=\left\{1;-1;3;-3;5;-5;9;-9;15;-15;45;-45\right\}\)
d: \(27=3^3;45=3^2\cdot5;75=3\cdot5^2\)
=>\(ƯCLN\left(27;45;75\right)=3\)
=>\(ƯC\left(27;45;75\right)=\left\{1;-1;3;-3\right\}\)
a) 40 và 24:
Ta có: 40= 2^3x5
24= 2^3x 5
USCLN là: 2^3= 8
b) 80 và 144
Ta có: 80= 2^4x5
144= 2^4 x 3^2
USCLN là: 2^4= 16
Các bài khác làm tương tự.
a, BCNN(210;280) = 840 => BC(210;280) = 840k (k ∈ N)
b, BCNN(105;135) = 945 => BC(105;135) = 945k (k ∈ N)
c, BCNN(24;36) = 72 => BC(24;36) = 72k (k ∈ N)
d, BCNN(48;80;72) = 720 => BC(48;80;72) = 720k (k ∈ N)
e, BCNN(42;55;91) = 30030 => BC(42;55;91) = 30030k (k ∈ N)
f, BCNN(12;36;102) = 612 => BC(12;36;102) = 612k (k ∈ N)
10 = 5 . 2
18 = 32 . 2
24 = 23 . 3
BCNN = 360
có 360 = { 0 ; 360 ; 720 ; 1080 ; .... }
ƯCLN (24; 180) = 12. Mà Ư (12) = {1; 2; 3; 4; 6; 12}.
Vậy ƯC (24; 180) = {l; 2; 3; 4; 6}
a 10=2.5
24=23.3
BCNN(10,24)=23.5.3=120
→BC(10,24)=B(120)={0;120;240;360;480;....}
b 20=22.5
35=7.5
60=22.3.5
BCNN(20,35,60)=22.3.5.7=420
→BC(20,35,60)=B(420)={0;420;840;1260;...}
c 48=24.3
120=23.3.5
BCNN(48,120)=24.3.5=240
→BC(48,120)=B(240)={0;240;480;720;...}
d
18=2.32
24=23.3
32=25
BCNN(18,24,32)=25.32=288
→BC(18,24,32)=B(288)={0;288;576;864;...}