Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Đây là cuộc thi nhé. cần sự công bằng. Mong em không tái phạm lần sau. Bạn sẽ bị khóa nick hoặc trừ 5000 điểm nhé!
BQT thân gửi em!
__BQT Lớp 6/7 Hỏi Đáp__
Ta có: \(A=124\left(\frac{1}{1.1985}+\frac{1}{2.1986}+\frac{1}{3.1987}+...+\frac{1}{16.2000}\right)\)
\(=\frac{124}{1984}\left(\frac{1984}{1.1985}+\frac{1984}{2.1986}+\frac{1984}{3.1987}+...+\frac{1984}{16.2000}\right)\)
\(=\frac{1}{16}\left(1-\frac{1}{1985}+\frac{1}{2}-\frac{1}{1986}+\frac{1}{3}-\frac{1}{1987}+...+\frac{1}{16}-\frac{1}{2000}\right)\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{16}\right)-\left(\frac{1}{1985}+\frac{1}{1986}+\frac{1}{1987}+...+\frac{1}{2000}\right)\right]\)
\(B=\frac{1}{1.17}+\frac{1}{2.19}+...+\frac{1}{1984.2000}\)
\(=\frac{1}{16}\left(\frac{16}{1.17}+\frac{16}{2.18}+...+\frac{16}{1984.2000}\right)\)
\(=\frac{1}{16}\left(1-\frac{1}{17}+\frac{1}{2}-\frac{1}{18}+...+\frac{1}{1984}-\frac{1}{2000}\right)\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+...+\frac{1}{1984}\right)\right]-\left[\frac{1}{17}+\frac{1}{18}+...+\frac{1}{2000}\right]\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+...+\frac{1}{16}\right)+\left(\frac{1}{17}+\frac{1}{18}+...+\frac{1}{1984}\right)-\left(\frac{1}{17}+\frac{1}{18}+...+\frac{1}{1984}\right)-\left(\frac{1}{1985}+\frac{1}{1986}+...+\frac{1}{2000}\right)\right]\)
\(=\frac{1}{16}\left[\left(1+\frac{1}{2}+...+\frac{1}{16}\right)-\left(\frac{1}{1985}+\frac{1}{1986}+...+\frac{1}{2000}\right)\right]\)
Vậy A = B
\(A=\left(1985\cdot1987-1\right):\left(1980+1985\cdot1986\right)\)
\(A=3944194\div3944190\)
ko chia hết nên sẽ bằng 1,4 lớn hơn 1
\(\Rightarrow A>1\)
1985x1987-1/1980+1985x1986=1985x1986+1985-1/1980+1985x1986
=1985x1986+1984/1980+1985x1986.Vì 1985x1986+1984>1980+1985x1986
suy ra 1985x1987-1/1980+1985x1986>1
Ta có:
a) 203874 = (2032)437 = (...9)437 = .....9
b) 1682018 = 1682016. 1682 = (1684)504 . (...4) = (...6)504 . (...4) = (...6) . (....4) = .....4
c) 99932019 - 44472017 = 99932018 . 9993 - 44472016 . 4447 = (99932)1009 . 3 - (44472)1008 . 4447 = (....9)1009 . 3 - (....9)1008 . 4447 = ...9 . 3 - ....9 . 7 = ....7 - .....3 = ....4
d) 321985 + 141990 = 321984 . 32 + (142)995 = (324)496 . 32 + (....6)995 = (....6)496 . 32 + (....6) = (....6) . 32 + (....6) = .....2 + ...6 = ....8
\(a;203^{874}=\left(203^4\right)^{218}\times203^2=...1\times...9=...9\)
\(b;168^{2018}=\left(168^4\right)^{504}\times168^2=...6\times...4=...4\)
\(c;9993^{2019}-4447^{2017}=\left(9993^4\right)^{504}\times9993^3-\left(4447^4\right)^{504}\times4447\)
\(=...1\times...7-...1\times...7=...0\)
\(d;32^{1985}+14^{1990}=\left(32^4\right)^{496}\times32+\left(14^2\right)^{995}\)
\(=...6\times32+...6=...2+...6=...8\)
sailor moon mà
cậu tích xem phim sale moon phải không đúng thì nhấn nhé