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Tìm y:
\(\frac{Y}{15}=\frac{2}{5}\) => y = 15 x 2/ 5 = 6
Vậy y = 6
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a. = 0,25 : 0,25 + 0,4 x 2,5 + 0,2 x 5
= 1 + 1 + 1
= 3
b. y x ( 7 + 1 + 12 - 6 - 4) = 45
y x 9 = 45
=> y = 5
\(20\%y+0,4y=12\)
\(\Leftrightarrow\frac{20}{100}y+0,4y=12\)
\(\Leftrightarrow0,2y+0,4y=12\)
\(\Leftrightarrow(0,2+0,4)y=12\)
\(\Leftrightarrow0,6y=12\Leftrightarrow y=20\)
Vậy y = 20
\(\dfrac{1}{5}\times y+0,4\times y+y=32\)
\(\left(\dfrac{1}{5}+0,4+1\right)\times y=32\)
\(\dfrac{8}{5}\times y=32\)
\(y=32:\dfrac{8}{5}\)
\(y=20\)
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\(\Leftrightarrow\) y\(\times\)1/4 + y \(\times\)1/2 + y \(\times\)1/4 + y= 20
\(\Leftrightarrow\)y\(\times\) ( 1/4+1/2+1/4+1)=20
\(\Leftrightarrow\) y\(\times\)2=20
\(\Leftrightarrow\) y=10
\(\dfrac{4}{3}\) = \(\dfrac{20}{4}\)\(x\) - 1
5\(x\) - 1 = \(\dfrac{4}{3}\)
5\(x\) = \(\dfrac{4}{3}\) + 1
5\(x\) = \(\dfrac{7}{3}\)
\(x\) = \(\dfrac{7}{3}\) : 5
\(x\) = \(\dfrac{7}{15}\)
b,
2\(\times\)\(x\) = 3\(\times\) y
\(x\) = \(\dfrac{3}{2}\) \(\times\) y
y - \(\dfrac{3}{2}\) \(\times\) y = 5
\(y\) \(\times\) ( 1 - \(\dfrac{3}{2}\)) = 5
\(y\) \(\times\) - \(\dfrac{1}{2}\) = 5
\(y\) = 5 : (-\(\dfrac{1}{2}\))
\(y\) = - 10
\(x\) = y - 5 = -10 - 5 =-15
\(20\%\text{x}y+0,4\text{x}y=12\)
\(\Rightarrow\left(20\%+0,4\right)\text{x}y=12\)
\(\Rightarrow0,6\text{x}y=12\)
\(\Rightarrow y=12:0,6\)
\(\Rightarrow y=20\)