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\(\dfrac{7}{16}+\dfrac{-1}{8}+\dfrac{9}{32}=\dfrac{14}{32}-\dfrac{4}{32}+\dfrac{9}{32}=\dfrac{19}{32}\)
\(\dfrac{5}{4}-\dfrac{25}{30}\times\dfrac{37}{44}+\dfrac{-25}{30}\times\dfrac{13}{44}+\dfrac{-25}{30}\times\dfrac{-6}{44}\)
\(=-\dfrac{25}{30}\times\left(\dfrac{5}{4}+\dfrac{37}{44}+\dfrac{13}{44}-\dfrac{6}{44}\right)\)
\(=-\dfrac{25}{30}\times\left(\dfrac{55}{44}+\dfrac{37}{44}+\dfrac{13}{44}-\dfrac{6}{44}\right)\)
\(=-\dfrac{25}{30}\times\dfrac{99}{44}\)
\(=-\dfrac{5}{6}\times\dfrac{9}{4}\)
\(=-\dfrac{15}{8}\)
\(\left(\dfrac{7}{16}+\dfrac{-1}{8}+\dfrac{9}{32}\right):\dfrac{5}{4}\)
\(=\left(\dfrac{14}{32}+\dfrac{-4}{32}+\dfrac{9}{32}\right):\dfrac{5}{4}\)
\(=\dfrac{19}{32}:\dfrac{5}{4}\)
\(=\dfrac{19}{32}.\dfrac{4}{5}=\dfrac{19.4}{32.5}=\dfrac{19}{40}\)
\(\dfrac{-25}{30}.\dfrac{37}{44}+\dfrac{-25}{30}.\dfrac{13}{44}+\dfrac{-25}{30}.\dfrac{-6}{44}\)
\(=\dfrac{-25}{30}.\left(\dfrac{37}{44}+\dfrac{13}{44}+\dfrac{-6}{44}\right)\)
\(=\dfrac{-25}{30}.\dfrac{44}{44}=\dfrac{-5}{6}.1=-\dfrac{5}{6}\)
a) (135 - 35) . (-37) + 37 . (-42 - 58)
= 100 . 0 . (-100)
= 0
b) -65 . (87 - 17) - 87 . (17 - 65)
= -65 . 70 - 87 . (-48)
= -4550 - 135
= -4415
a,1-3+5-7+9-.......+33-35
=(1+5+9+....+33)-(3+7+11+...+35)
=153-171
=-18
Tick mk vài cái lên 300 mk giải nốt phần b
a) (–37 ) + (–112)
= –(37 + 112) (cộng hai số nguyên âm).
= –149.
b) (–42) + 52
= 52 – 42 (cộng hai số nguyên khác dấu)
= 10
c) 13 – 31 = –31 + 13 = – (31 – 13) = –18.
d) 14 – 24 – 12 = 14 – (24 + 12) = 14 – 36 = – (36 – 14) = –22.
e) (–25) + 30 – 15 = 30 – 25 – 15 = 30 – (25 + 15) = 30 – 40 = –10
d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)
\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)
hay \(x=\dfrac{25}{372}\)
Vậy: \(x=\dfrac{25}{372}\)
e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)
f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)
\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)
\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)
\(\Leftrightarrow3x=\dfrac{1}{9}\)
hay \(x=\dfrac{1}{27}\)
g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)
\(\Leftrightarrow\dfrac{4}{3}x=2\)
hay \(x=\dfrac{3}{2}\)
Vậy: \(x=\dfrac{3}{2}\)
h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)
Vậy ...
i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)
Vậy ...
a. ( - 37 ) + ( - 112 )
= - ( 37 + 112 )
= - 149
b. ( - 42 ) + 52
= ( 52 - 42 )
= 10
c. 13 - 31
= 13 + ( - 31 )
= - ( 31 - 13 )
= - 18
a. (-37) + (-112) = -(37 + 112) = -149
b. (-42) + 52 = 52 - 42 =10
c. 13 - 31 = 13 + (-31) = - 18
Học tốt nha!!!!!!!!!!!!!!!!!
a.( 15 + 37 ) + ( 2 - 37 - 17 )
= 15 + 37 + 52 - 37 - 17
= 15 + (37 - 37) + (52 - 17)
= 15 + 0 + 35
= 50
b.- ( 21 - 32 ) - ( -12 + 32 )
= 21 + 32 + 12 - 32
= ( 21 + 12 ) + ( 32 - 32 )
= 9 + 0
= 9
c ( 38 - 42 + 14) - ( 25 - 27 - 15 )
= 38 - 42 + 14 + (-25) + 27 + 15
= (38 - 42 + 14) + [( -25 ) + 15] + 27
= 10 + (-10) + 27
= 0 + 27
= 27
#ht
a,37 + 42 - 37 + 22 = 42 - 22 = 20
b,4^4 : 8 + 2^3 . 11
= 2^8 : 2^3 + 2^3.11
= 2^5 + 2^3.11
= 32 + 8.11
= 32 + 88
= 120
c, 6250 : {50^2:[112-(32-2^2.5)]}
= 6250 : {2500 : [ 112 - ( 32 - 4 .5 )]}
= 6250 : { 2500 : [ 112 - 12 ]}
=6250 : { 2500 : 100 }
= 6250 : 25
=250
a,37 + 42 - 37 + 22
Nhận xét : 37 - 37 = 0 còn 42 - 22 = 20