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\(a,\dfrac{-13}{5}-\dfrac{-7}{15}.\dfrac{120}{63}+\dfrac{4}{5}\\ =\dfrac{-13}{5}+\dfrac{8}{9}+\dfrac{4}{5}\\ =\dfrac{-77}{45}+\dfrac{4}{5}\\ =\dfrac{-41}{45}\\ b.\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}\\ =\left(\dfrac{68}{9}+\dfrac{8}{3}\right)-\dfrac{47}{9}\\ =\dfrac{92}{9}-\dfrac{47}{9}\\ =5\)
2)\(-\dfrac{13}{5}--\dfrac{7}{15}.\dfrac{120}{63}+\dfrac{4}{5}\)
\(=-\dfrac{13}{5}+\dfrac{7.15.8}{15.9.7}+\dfrac{4}{5}\)
\(=-\dfrac{13}{5}+\dfrac{8}{9}+\dfrac{4}{5}\)
\(=\left(-\dfrac{13}{5}+\dfrac{4}{5}\right)+\dfrac{8}{9}\)
\(=-\dfrac{9}{5}+\dfrac{8}{9}\)
\(=\dfrac{-81+40}{45}=-\dfrac{41}{45}\)
3)\(\left(7\dfrac{5}{9}+2\dfrac{2}{3}\right)-5\dfrac{2}{9}\)
\(=\left(7\dfrac{5}{9}-5\dfrac{2}{9}\right)+2\dfrac{2}{3}\)
\(=2\dfrac{1}{3}+2\dfrac{2}{3}\)
\(=5\)
Trả lời
568-{5.[143-3.(14-1)]+10}:10
=568-{5.[143-3.13]+10}:10
=568-{5.[143-39]+10}:10
=568-{5.104+10}:10
=568-530:10
=568-53
=515
568-{5x[143-3x13+10}:10
=568-{5x[143-39+10}:10
=568-(5x114):10
=568-570:10
=568-57
=511
#)Giải :
\(\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{4}\right)^{20}=\left(\frac{1}{2}\right)^{15}\div\left(\frac{1}{2}\right)^{40}=\left(\frac{1}{2}\right)^{-25}\)
\(=\left(5\cdot2^6+11\cdot2^4-23\cdot2^4\right):2^6=5+11\cdot\dfrac{1}{2^2}-23\cdot\dfrac{1}{2^2}=5+\dfrac{11}{4}-\dfrac{23}{4}=2\)
2(x-1)-40=-50
2x-2 =-50+40
2x-2 = -10
2x =-10+2
2x = -8
x = -(8:2)
x = -4
dcj ko bạn
2(x-1)-40=-50
=>2(x-1)=-10
Xét số đối của x ta có:
2(-x-1)=10
=>-x-1=5
=>-x=6
Vì số đối của x là -x=6
Vậy x=-6
ừm
a)(+15)+(-15)=0
b)(-23)+(+31)=8
c)I-19I+(-12)=7
d)(-307)+(+7)=(-300)
k nha bn
\(d)8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)
\(=\dfrac{8.7+2}{7}-\left(\dfrac{3.9+4}{9}+\dfrac{4.7+2}{7}\right)\)
\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)
\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)
\(=\left(\dfrac{58}{7}-\dfrac{30}{7}\right)-\dfrac{31}{9}\)
\(=\left(\dfrac{58-30}{7}\right)-\dfrac{31}{9}\)
\(=\dfrac{28}{7}-\dfrac{31}{9}\)
\(=\dfrac{28.9}{7.9}-\dfrac{31.7}{9.7}\)
\(=\dfrac{252}{63}-\dfrac{217}{63}\)
\(=\dfrac{252-217}{63}\)
\(=\dfrac{35}{63}\)
\(=\dfrac{5}{9}\)
\(d,=9^{2017}\left(9-1\right):9^{2017}=8\\ e,=\dfrac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\dfrac{3^{29}\left(11-3\right)}{2^2\cdot3^{28}}=\dfrac{3\cdot8}{2^2}=6\\ f,=\dfrac{2^{10}\cdot3^8+2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}=\dfrac{2^{10}\cdot3^8\left(1+3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{4}{6}=\dfrac{2}{3}\)
Em cảm ơn ạ <3