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3A =1.2.3 +2.3.(4-1) +3.4.(5-2) +4.5.(6-3)....+199.200.(201 -198)
= 1.2.3+2.3.4 -1.2.3 +3.4.5- 2.3.4 + 4.5.6 - 3.4.5 +......+ 199.200.201 -198.199.200
3A =199.200.201
A=199.200.67 =254600
a: \(\left(-305\right)+400+305\)
\(=\left(-305+305\right)+400\)
=0+400
=400
b: \(\left(-511\right)-\left(-11\right)\)
=-511+11
=-(511-11)
=-500
c: \(0-\left(12345+15\right)\)
\(=0-12360\)
=-12360
d: \(333-\left[\left(-14657\right)+57\right]-78\)
\(=333+14657-57-78\)
\(=\left(333-78\right)+14600\)
\(=255+14600=14855\)
\(A=\left(157.57-99.57-57^2\right):57+57\)
\(=\left[\left(157-99\right).57-57^2\right]:57+57\)
\(=\left[58.57-57^2\right]:57+57\)
\(=\left[3306-3249\right]:57+57\)
\(=57:57+57\)
\(=1+57=58\)
Vậy....
\(B=\left[160.\left(730-700\right):2^4-4^2\right].13\)
\(=\left[160.30:16-16\right].13\)
\(=\left[4800:16-16\right].13\)
\(=\left(300-16\right).13\)
\(=284.13=3692\)
Vậy...
\(C=\left(3^2.17+3^2.38-55\right):\left(2^3.68-2^3.13\right)\)
\(=\left(9.17+9.38-55\right):\left(8.68-8.13\right)\)
\(=\left[9.\left(17+38\right)-55\right]:\left[8.\left(68-13\right)\right]\)
\(=\left[9.55-55\right]:\left[8.55\right]\)
\(=\left[8.55\right]:\left[8.55\right]\)
\(=1\)
Vậy...
\(D=2.51^2:17^2+\left(8.5^2-2^4-3^2\right):56+2009\)
\(=2.8+\left(8.25-16-9\right):56+2009\)
\(=18+\left(200-16-9\right):56+2009\)
\(=18+175:56+2009\)
\(=18+\dfrac{25}{8}+2009\)
\(=\dfrac{16241}{8}\)
C = 1.2 + 2.3 + 3.4 + ... + 99.100
C x 3 = 1.2.3 + 2.3.3 + 3.4.3 + ...+ 99.100.3
= 1.2.3 + 2.3. (4-1) + 3.4. (5-2) + ...+ 99.100.(101-98)
= 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ...+ 99.100.101 - 98.99.100
= 99.100.101
=>C = 99.100.101 : 3 = 33.100.101 = 333300
mk hoc roi muon minh giai tick nha
A=(157.57-99.57-572):57+57
A = 1 + 57
A = 58
B=1.2+2.3+3.4+............+n.(n+1)
B = 1.2+2.3+3.4+.............+n(n+1)
=1(1+1) + 2(2+1) + 3(3+1) +...+n(n+1)
=(1^2 + 2^2 + 3^2 +...+ n^2) + (1 + 2 + 3 + ...+ n)
ta có các công thức:
1^2 + 2^2 + 3^2 +...+ n^2 = n(n+1)(2n+1)/6
1 + 2 + 3 + ...+ n = n(n+1)/2
thay vào ta có:
S = n(n+1)(2n+1)/6 + n(n+1)/2
=n(n+1)/2[(2n+1)/3 + 1]
=n(n+1)(n+2)/3