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Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời. \(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\) \(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\) \(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\) \(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\) \(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\) \(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\) \(A=1+\frac{1}{2}\) \(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\) \(A=\frac{3}{2}\) \(A=\dfrac{9-18+14}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{5}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{3}{4}\) \(B=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right)\cdot\dfrac{5}{7}\) \(=\dfrac{7}{5}-\dfrac{11+5}{20}\cdot\dfrac{5}{7}\) \(=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49-20}{35}=\dfrac{29}{35}\) a, \(\left(\dfrac{3}{8}+\dfrac{-3}{4}+\dfrac{7}{12}\right)\dfrac{5}{6}+\dfrac{1}{2}\) \(=\left(\dfrac{-3}{8}+\dfrac{7}{12}\right)\dfrac{5}{6}+\dfrac{1}{2}\) \(=\dfrac{5}{24}.\dfrac{5}{6}+\dfrac{1}{2}\) \(=\dfrac{25}{144}+\dfrac{1}{2}\) \(=\dfrac{97}{144}\) b, \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{5}\) \(=\dfrac{28}{15}.0,75-\dfrac{4}{5}:\dfrac{7}{5}\) \(=\dfrac{7}{5}-\dfrac{4}{7}\) \(=\dfrac{29}{35}\) B1a)\(11\frac34-\left(6\frac56-4\frac12\right)+1\frac23\) =\(11\frac34-6\frac56+4\frac12+1\frac23\) =\(\left(11-6+4+1\right)+\left(\frac34-\frac56+\frac12+\frac23\right)\) =\(10+\left(\frac{9}{12}-\frac{10}{12}+\frac{6}{12}+\frac{8}{12}\right)\) =\(10+\left(-\frac{1}{12}+\frac{6}{12}+\frac{8}{12}\right)\) =10+\(\frac{13}{12}\) =\(\frac{120}{12}+\frac{13}{12}\) =\(\frac{133}{12}\) b)\(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\) = \(\frac{57}{20}-\frac{16}{5}+\frac{129}{20}\times\frac13\) =\(\frac{57}{20}-\frac{16}{5}+\frac{129}{60}\) =\(\frac{171}{60}-\frac{192}{60}+\frac{129}{60}\) =\(\frac{108}{60}\) =\(\frac95\) \(a,\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right)\cdot\frac{10}{11}\) \(=\frac{5}{16}:\frac{1}{8}-\left(\frac{9}{4}-\frac{3}{5}\right)\cdot\frac{10}{11}\) \(=\frac{5}{2}-\frac{33}{20}\cdot\frac{10}{11}\) \(=\frac{5}{2}-\frac{3}{2}\) \(=1\) \(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\) \(\Rightarrow\frac{5}{16}:\frac{125}{1000}-\left(\frac{9}{4}-\frac{6}{10}\right).\frac{10}{11}\) \(\Rightarrow\frac{5}{16}:\frac{1}{8}-\left(\frac{9}{4}-\frac{3}{5}\right).\frac{10}{11}\) \(\Rightarrow\frac{5}{16}.\frac{8}{1}-\left(\frac{45}{20}-\frac{12}{20}\right).\frac{10}{11}\) \(\Rightarrow\frac{5}{2}-\frac{33}{20}.\frac{10}{11}\) \(\Rightarrow\frac{5}{2}-\frac{3.1}{2.1}\) \(\Rightarrow\frac{5}{2}-\frac{3}{2}=\frac{2}{2}=1\) Bài 1: \(g.\frac{5}{11}+\frac{6}{11}=\frac{5+6}{11}=\frac{11}{11}=1\)\(\) \(e.\frac{-17}{25}.\frac{20}{33}+\frac{-17}{25}.\frac{13}{33}+\frac{-3}{25}=\frac{-17}{25}.\left(\frac{20}{33}+\frac{13}{33}\right)+\frac{-3}{25}\) \(=\frac{-17}{25}.1+\frac{-3}{25}=\frac{-17}{25}+\frac{-3}{25}=\frac{-17-3}{25}=\frac{-20}{25}=\frac{-4}{5}\) \(d.\frac{5}{7}.\frac{19}{23}+\frac{5}{7}.\frac{5}{23}-\frac{5}{7}.\frac{1}{23}=\frac{5}{7}\left(\frac{19}{23}+\frac{5}{23}-\frac{1}{23}\right)\) \(=\frac{5}{7}\left(\frac{19+5-1}{23}\right)=\frac{5}{7}.1=\frac{5}{7}\) \(c.\left(-11\right).\frac{9}{22}=\frac{\left(-11\right).9}{22}=\frac{-99}{22}=\frac{-9}{2}\) \(b.\frac{5}{6}-\frac{1}{8}=\frac{5.4}{6.4}-\frac{1.3}{8.3}=\frac{20}{24}-\frac{3}{24}=\frac{17}{24}\) \(a.\frac{2}{3}+\frac{1}{5}-\frac{1}{6}=\frac{2.10}{3.10}+\frac{1.6}{5.6}-\frac{1.5}{6.5}=\frac{20}{30}+\frac{6}{30}-\frac{5}{30}\) \(=\frac{20+6-5}{30}=\frac{21}{30}=\frac{7}{10}\) Bài 2: \(a.\frac{3}{4}+x=\frac{11}{12}\) \(\Leftrightarrow x=\frac{11}{12}-\frac{3}{4}\) \(\Leftrightarrow x=\frac{11}{12}-\frac{9}{12}\) \(\Leftrightarrow x=\frac{2}{12}=\frac{1}{6}\) \(b.x-\frac{11}{12}=0,5\) \(\Leftrightarrow x=\frac{1}{2}-\frac{11}{12}\) \(\Leftrightarrow x=\frac{6}{12}+\frac{11}{12}\) \(\Leftrightarrow x=\frac{17}{12}\) \(\frac37+\frac{5}{13}+\frac{4}{13}\) =\(\frac37+\left(\frac{5}{13}+\frac{4}{13}\right)\) =\(\frac37+\frac{9}{13}\) =\(\frac{39}{91}+\frac{63}{91}\) =\(\frac{102}{91}\) \(\left(\frac38+\frac{-3}{4}+\frac{7}{12}\right):\frac56+\frac12\) =\(\left(\frac{9}{24}+\frac{-18}{24}+\frac{7}{24}\right)\times\frac65+\frac12\) =\(\frac{5}{24}\times\frac65+\frac12\) =\(\frac14+\frac12\) =\(\frac14+\frac24\) =\(\frac34\)
K
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CM
Cao Minh Tâm
14 tháng 7 2019
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