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F = 7 + 72 + 73 + 74 + ..... + 7100
F= 7+(1+7)+73+(1+7)+...+799+(1+7)
F = 7x8+73x8+...+799x8
F= 8x(7+73+...+799)
mà 8 chia hết 8 => 8(7+73+...+799) chia hết 8
Vậy F chia hết cho 8
a, = 89+43-32 = 132-32 = 100
b, = 25:5 = 5
c, = -27 : 9 + 49.2 = -3+98 = 95
d, = 115+85+53-(-447) = 200+53+447 = 700
Tk mk nha
12 : { 400 : [500 – (125 + 25 . 7)]}
12 : { 400 : [500 – (125 + 175]}
12 : { 400 : [500 – 300]}
12 : { 400 : 200}
12 : 2 = 6
\(12\div\left(400\left[500-\left(125+25.7\right)\right]\right)]\)
12 : ( 400 : [ 500 - ( 125 + 175 ]}
12 : ( 400 : [ 500 - 300 ]}
12 : ( 400 : 200 )
12 : 2 = 6
Ta có:
\(12:\left\{390:\left[500-\left(5^3+7^2.5\right)\right]\right\}\)
\(=12:\left\{390:\left[500-125-245\right]\right\}\)
\(=12:\left(390:130\right)\)
\(=12:3=4\)
a, 75 + 58.50 – 58.25 = 3.25 + 58.(50 – 25) = 3.25 + 58.25 = 25.(3+58) = 25.61 = 1525
Ta có: 1525 = 5 2 . 61
b, 20: 2 2 – 5 9 : 5 8 = 20:4 – 5 = 5 – 5 = 0
c, 5 19 : 5 17 - 4 : 7 = 5 2 - 4 : 7 = (25 – 4):7 = 3
d, 47 - 45 . 2 4 - 5 2 . 12 : 14 = 47 – (45.16 – 25.12):14 = 47 – (720 – 300):14 = 47 – 420:14 = 47 – 30 = 17
e, 10 2 : 60 : 5 6 : 5 4 - 3 . 5 = 100 – 60: 5 2 - 15 = 100 – 60:(25 – 15) = 100 – 60:10 = 100 – 6 = 94
Ta có: 94 = 2.47
f, 2345 - 1000 : 19 - 2 21 - 18 2 = 2345 – 1000:(19 – 2. 3 2 ) = 2345 – 1000:(19 – 2.9) = 2345 – 1000:(19 – 18) = 2345 – 1000:1 = 2345 – 1000 = 1345
Ta có: 1345 = 3.269
g, 500 – {5.[409 – 2 3 . 3 - 21 2 ]+ 10 3 }:15 = 500 – {5.[409 – 8 . 3 - 21 2 ]+1000}:15 = 500 – {5.[409 – 3 2 ]+1000}:15 = 500 – {5.(409 – 9)+1000}:15 = 500 – {5.400+1000}:15 = 500 – (2000+1000):15 = 500 – 3000:15 = 500 – 200 = 300
Ta có: 300 = 2 2 . 3 . 5 2
h, 967 – [8 + 2 . 3 2 – 24:6 + 9 - 7 3 ].5 = 967 – [8+2.9 – 4+8].5 = 967 – 30.5 = 967 – 150 = 817
Ta có: 817 = 19.43
a) (3⁵ . 3⁷) : 3¹⁰ + 5 . 2⁴ - 7³ : 7
= 3¹² : 3¹⁰ + 5.16 - 7²
= 3² + 80 - 49
= 9 + 31
= 40
b) (7⁵ + 7⁹) . (5⁴ + 5⁶) . (3³.3 - 9²)
= (7⁵ + 7⁹) . (5⁴ + 5⁶) . (81 - 81)
= (7⁵ + 7⁹) . (5⁴ + 5⁶) . 0
= 0
\(2011-5.5^2-\left(7^3:7+2012^0\right)\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50=1836\)
\(120:520:\left(500-5^3+35.7\right)\\ =120:520:\left(500-125+245\right)\\ =120:520:620=\dfrac{3}{8060}\)
\(2011-5\times5^2-\left[7^3:7+2012^0\right]\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50\\ =1836\\ 120:520:\left[500-5^3+35\times7\right]\\ =120:520:\left[500-125+35\times7\right]\\ =120:520:620\\ =\dfrac{3}{8060}\)