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g: =4/9(-3/4+27/4)-14/3
=4/9*6-14/3
=8/3-14/3
=-6/3=-2
h: =11/7-3/5-4/9-4/7+8/5-5/9
=8/5
k: =-9/4(2/7-16/7)-2/3
=-9/4*(-2)-2/3
=9/2-2/3
=27/6-4/6
=23/6
m: =9/17*3/11-9/17*12/11-9/17*13/11
=9/17(3/11-12/11-13/11)
=9/17*(-2)=-18/17
a) (-124) + 24 = -100
b) 37. 78 + 37. 22
= 37 . ( 78 + 22 )
= 37 . 100
= 3700
Câu 9
a) 2/15 + (-3/5)
= 2/15 - 3/5
= 2/15 - 9/15
= -7/15
b) -5/7 + 3/7 . (-2/9)
= -5/7 - 2/21
= -15/21 - 2/21
= -17/21
c) 5/16 - (7/15 - 3/16) + 17/30
= 5/16 - 7/15 + 3/16 + 17/30
= (5/16 + 3/16) + (17/30 - 14/30)
= 1/2 + 1/10
= 5/10 + 1/10
= 6/10
= 3/5
\(a,\dfrac{2}{15}+\left(-\dfrac{3}{5}\right)\\ =\dfrac{2}{15}-\dfrac{3}{5}\\ =\dfrac{2}{15}-\dfrac{9}{15}\\ =-\dfrac{7}{15}\\ b,-\dfrac{5}{7}+\dfrac{3}{7}\times\left(-\dfrac{2}{9}\right)\\ =-\dfrac{5}{7}-\dfrac{2}{21}\\ =-\dfrac{15}{21}-\dfrac{2}{21}\\ =-\dfrac{17}{21}\\ c,\dfrac{5}{16}-\left(\dfrac{7}{15}-\dfrac{3}{16}\right)+\dfrac{17}{30}\\ =\dfrac{5}{16}-\dfrac{7}{15}+\dfrac{3}{16}+\dfrac{17}{30}\\ =\left(\dfrac{5}{16}+\dfrac{3}{16}\right)-\left(\dfrac{17}{15}+\dfrac{17}{30}\right)\\ =\dfrac{1}{2}-\dfrac{17}{10}\\ =\dfrac{5}{10}-\dfrac{17}{10}\\ =-\dfrac{6}{5}.\)
e: =5/7(5/11+2/11-14/11)
=5/7(-7/11)=-5/11
f: =-5/4(2/11+9/11)+1+3/4
=-5/4+7/4
=2/4=1/2
g: =-5/7(3/13+10/13)+1+5/7
=-5/7+1+5/7
=1
h: =7/4(29/5-9/5)+41/13
=-7+41/13=-50/13
\(\dfrac{\dfrac{5}{3}-\dfrac{5}{7}+\dfrac{5}{9}}{\dfrac{10}{3}-\dfrac{10}{7}+\dfrac{10}{9}}=\dfrac{5\left(\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{9}\right)}{10\left(\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{9}\right)}=\dfrac{1}{2}\)
Câu 1:
A={1;3;5;7;9}
Câu 2:
A. 24 x 82 + 24 x 18 - 100
= 24 x (82 + 18) - 100
= 24 x 100 - 100
= 2400 - 100 = 2300
B.12 + 3 [ 39 - (5 - 2 )2 ]
= 12 + 3. [39 - 32 ]
= 12 + 3 . [39-9]
= 12 + 3.30
= 12 + 90 = 102
\(112\cdot35+112\cdot65+800\)
\(=112\cdot\left(35+65\right)+800\)
\(=112\cdot100+800\)
\(=11200+800\)
\(=12000\)
d: \(\dfrac{-3}{-4}:\left(\dfrac{7}{-5}\cdot\dfrac{-5}{2}\right)\)
\(=\dfrac{3}{4}:\dfrac{7}{2}\)
\(=\dfrac{3}{4}\cdot\dfrac{2}{7}=\dfrac{3}{2\cdot7}=\dfrac{3}{14}\)
h: \(\dfrac{-5}{-16}\cdot\left(\dfrac{7}{44}\cdot\dfrac{32}{-5}\right)\)
\(=-\dfrac{5}{16}\cdot\dfrac{7}{44}\cdot\dfrac{32}{5}\)
\(=-\dfrac{5}{5}\cdot\dfrac{32}{16}\cdot\dfrac{7}{44}\)
\(=-2\cdot\dfrac{7}{44}=-\dfrac{7}{22}\)