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23 . 75 + 25 . 23 + 180
= 23 . (75 + 25) + 180
= 23 . 100 + 180
= 2300 + 180 = 2480

a, \(\dfrac{7}{15}\)+\(\dfrac{18}{54}\)
= \(\dfrac{7}{15}\)+ \(\dfrac{1}{3}\)
= \(\dfrac{7}{15}\)+\(\dfrac{5}{15}\)
= \(\dfrac{12}{15}\) = \(\dfrac{4}{5}\) =0,8
b, \(\dfrac{12}{25}\)+\(\dfrac{23}{75}\)-\(\dfrac{1}{4}\)
= \(\dfrac{59}{75}\) -\(\dfrac{1}{4}\)
= \(\dfrac{161}{300}\)

a) − 105 + − 25 + ( − 105 ) + 50
= 105 + 25 + ( - 105) + 50
= [105 + ( -105)] + ( 25 + 50 )
= 0 + 75 = 75
b) 465 + − 38 + − 465 − 12 − − 42
= 465 + ( - 38) + ( -465) – 12 – 42
= [ 465 + (- 465) ] – ( 12 + 42 )
= 0 – 54 = 0 + ( -54 ) = -54
c) 65. − 19 + − 19 .24 + − 19 .11
= ( - 19) . ( 65 + 24 + 11 )
= ( -19) . 100 = -1900
d) − 3 2 + 2 3 − − 5 2 + 4 3
= 9 + 8 – 25 + 64 = 56

a, 2 17 + 17 2 9 15 - 3 15 2 4 - 4 2
= 2 17 + 17 2 9 15 - 3 15 16 - 16
= 2 17 + 17 2 9 15 - 3 15 . 0
= 0
b, 1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) ( 3 8 - 81 2 )
= 1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) ( 3 4 . 2 - 81 2 )
= 1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) ( 81 2 - 81 2 )
= 1 2 + 2 3 + 3 4 + 4 5 . ( 1 3 + 2 3 + 3 3 + 4 3 ) . 0
= 0
c, 7 24 + 7 23 : 7 22
= 7 24 : 7 22 + 7 23 : 7 22
= 7 24 - 22 + 7 23 - 22
= 7 2 + 7 1
= 49 + 7 = 56

\(5^6\text{ : }5^4+2^3\cdot2^2-1^{2017}\)
\(=5^2+2^5-1\)
\(=25-32-1\)
\(=-7-1\)
\(=-8\)
12+(-23)=-11 (-43)+(-19)=-62 =23*(75+25)+180=23*100+180=2300+180=2480
12+|-23|=12+23=35
(-43)+(-19)= -(43+19)= -62
23*75+25*23+180=23*(75+25)+180=23*100+180=2300+180=2480